\(3\dfrac{4}{5}\) : \(40\dfrac{8}{15}\) = 0,25 : x

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12 tháng 1 2024

\(3\dfrac{4}{5}:40\dfrac{8}{15}=0,25:x\)

\(\Rightarrow\dfrac{19}{5}:\dfrac{608}{15}=0,25:x\)

\(\Rightarrow\dfrac{19}{5}\cdot\dfrac{15}{608}=\dfrac{1}{4}:x\)

\(\Rightarrow\dfrac{3}{32}=\dfrac{1}{4}:x\)

\(\Rightarrow x=\dfrac{1}{4}:\dfrac{3}{32}\)

\(\Rightarrow x=\dfrac{8}{3}\)

9 tháng 8 2017

a) \(\dfrac{5}{6}:x=30:3\)

\(\Leftrightarrow\dfrac{5}{6}:x=10\)

\(\Leftrightarrow x=\dfrac{5}{6}:10\)

\(\Leftrightarrow x=\dfrac{1}{12}\)

Vậy .......

b) \(x:2,5=0,003:0,75\)

\(\Leftrightarrow x:2,5=0,004\)

\(\Leftrightarrow x=0,004.2,5\)

\(\Leftrightarrow x=0,01\)

Vậy .......

c) \(3,8:\left(2x\right)=\dfrac{1}{4}:2\dfrac{2}{3}\)

\(\Leftrightarrow3,8:\left(2x\right)=\dfrac{1}{4}:\dfrac{8}{3}=\dfrac{3}{32}\)

\(\Leftrightarrow2x=3,8:\dfrac{3}{32}\)

\(\Leftrightarrow2x=\dfrac{698}{25}\)

\(\Leftrightarrow x=\dfrac{304}{15}\)

Vậy ...

d) \(\dfrac{2}{3}:0,4=x:\dfrac{4}{5}\)

\(\Leftrightarrow x:\dfrac{4}{5}=\dfrac{2}{3}\)

\(\Leftrightarrow x=\dfrac{8}{15}\)

Vậy ....

e) \(3\dfrac{4}{5}:40\dfrac{8}{15}=0,25:x\)

\(\Leftrightarrow0,25:x=\dfrac{19}{5}:\dfrac{608}{15}\)

\(\Leftrightarrow0,25x=\dfrac{57}{608}\)

\(\Leftrightarrow x=\dfrac{228}{608}\)

Vậy ...

e) \(\dfrac{x}{-15}=\dfrac{-60}{x}\)

\(\Leftrightarrow xx=\left(-60\right)\left(-15\right)\)

\(\Leftrightarrow x^2=900\)

\(\Leftrightarrow\left[{}\begin{matrix}x^2=30^2\\x^2=\left(-30\right)^2\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=30\\x=-30\end{matrix}\right.\)

Vậy ...

19 tháng 6 2018

8)\(\frac{4}{9}:\left(-\frac{1}{7}\right)+6\frac{5}{9}:\left(-\frac{1}{7}\right)\)

=\(\frac{4}{9}:\left(-\frac{1}{7}\right)+\frac{59}{9}:\left(-\frac{1}{7}\right)\)

=\(\left(\frac{4}{9}+\frac{59}{9}\right).\left(-7\right)\)

=7.(-7)

=-49

30 tháng 8 2019

1) -2/3

1: \(\Leftrightarrow3x+4=2\)

=>3x=-2

=>x=-2/3

2: \(\Leftrightarrow7x-7=6x-30\)

=>x=-23

3: =>\(5x-5=3x+9\)

=>2x=14

=>x=7

4: =>9x+15=14x+7

=>-5x=-8

=>x=8/5

11 tháng 11 2018

e)\(16\dfrac{2}{7}:\left(-\dfrac{3}{5}\right)+28\dfrac{2}{7}:\left(-\dfrac{3}{5}\right)\)

=\(\left(16\dfrac{2}{7}+28\dfrac{2}{7}\right):\left(-\dfrac{3}{5}\right)\)

=\(\dfrac{312}{7}\)\(:\left(-\dfrac{3}{5}\right)\)

=\(-\dfrac{516}{7}\)

11 tháng 11 2018

a)\(\dfrac{7}{8}.\left(\dfrac{2}{12}+\dfrac{4}{10}\right)\)

=\(\dfrac{7}{8}.\left(\dfrac{1}{6}+\dfrac{2}{5}\right)\)

=\(\dfrac{7}{8}.\)\(\dfrac{17}{30}\)

=\(\dfrac{119}{240}\)

29 tháng 7 2018

A)0,25:(10,3-9,8)-3/4

=1/4:(103/10-49/5)-3/4

=1/4:1/2-3/4

=1/2-3/4

=2/4-3/4

=-1/4

B)-5/9.13/28-13/28.4/9

=-5/9-4/9.13/28

=-1.13/28

=-13/28

c)6/7+5/8:5-3/16

=6/7+1/8-3/16

=55/56-3/16

=89/112

d)-5/7.2/11+-5/7.9/11+1/5/7

=-5/7.(2/11+9/11)+12/7

=-5/7.1+12/7

=-5/7+12/7

=1

e)-7/12-8/15+11/20

=-67/60+11/20

=-17/30

f)-17/25.20/33+-17/25.13/33+-3/25

=-17/25.(20/33+13/33)-3/25

=-17/25.1-3/25

=-17/25-3/25

=-4/5

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27 tháng 11 2022

b: =>(3x-1)(3x+1)(2x+3)=0

hay \(x\in\left\{\dfrac{1}{3};-\dfrac{1}{3};-\dfrac{3}{2}\right\}\)

c: \(\Leftrightarrow\left|2x-\dfrac{1}{3}\right|=\dfrac{5}{6}+\dfrac{3}{4}=\dfrac{19}{12}\)

=>2x-1/3=19/12 hoặc 2x-1/3=-19/12

=>2x=23/12 hoặc 2x=-15/12=-5/4

=>x=23/24 hoặc x=-5/8

d: \(\Leftrightarrow-\dfrac{5}{6}\cdot x+\dfrac{3}{4}=-\dfrac{3}{4}\)

=>-5/6x=-3/2

=>x=3/2:5/6=3/2*6/5=18/10=9/5

e: =>2/5x-1/2=3/4 hoặc 2/5x-1/2=-3/4

=>2/5x=5/4 hoặc 2/5x=-1/4

=>x=5/4:2/5=25/8 hoặc x=-1/4:2/5=-1/4*5/2=-5/8

f: =>14x-21=9x+6

=>5x=27

=>x=27/5

h: =>(2/3)^2x+1=(2/3)^27

=>2x+1=27

=>x=13

i: =>5^3x*(2+5^2)=3375

=>5^3x=125

=>3x=3

=>x=1

4 tháng 8 2018

\(a)\dfrac{-1}{4}.13\dfrac{9}{11}-0,25.6\dfrac{2}{11}\)

\(=\dfrac{-1}{4}.\dfrac{152}{11}-\dfrac{1}{4}.\dfrac{68}{11}\)

\(=-38-\dfrac{17}{11}\)

\(=\dfrac{-418}{11}+\dfrac{-17}{11}\)

\(=\dfrac{-435}{11}\)

\(b)\dfrac{31}{9}.\left|x\right|-\dfrac{5}{2}=\dfrac{8}{3}\)

\(\Leftrightarrow\dfrac{31}{9}.\left|x\right|=\dfrac{16}{6}+\dfrac{15}{6}\)

\(\Leftrightarrow\dfrac{31}{9}.\left|x\right|=\dfrac{31}{6}\)

\(\Leftrightarrow\left|x\right|=\dfrac{31}{6}.\dfrac{9}{31}\)

\(\Leftrightarrow\left|x\right|=1,5\)

\(\Leftrightarrow x\in\left\{1,5;-1,5\right\}\)

Vậy \(x\in\left\{1,5;-1,5\right\}\)