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a. ( x - 1 )2 = 25
<=> \(\orbr{\begin{cases}x-1=5\\x-1=-5\end{cases}}\)
<=>\(\orbr{\begin{cases}x=6\\x=-4\end{cases}}\)
b. 2x + 2 - 2x = 96
<=> 2x.4-2x=96
<=> 2x.3=96
<=> 2x=32=25
<=> x=5
c. 2x . 7 = 224
<=> 2x=32=25
<=> x=5
d. ( 7x - 11 )3 = 25 . 52 = 200 (xem lại đề)
e. 9 < 3x < 81
<=> 32<3x<34
<=> 2<x<4

1)\(79-5\left(11-x\right)=34\)
\(\Rightarrow79-55+5x=34\)
\(\Rightarrow24+5x=34\)
\(\Rightarrow5x=-10\)
\(\Rightarrow x=-2\)
Vậy \(x=-2\)
2)\(32+2\left(7-x\right)=40\)
\(\Rightarrow32+14-2x=40\)
\(\Rightarrow46-2x=40\)
\(\Rightarrow2x=6\)
\(\Rightarrow x=3\)
Vậy \(x=3\)
3)\(\left(166-2x\right).8^9=2.8^{11}\)
\(\Rightarrow\left(83-x\right).2.8^9=2.8^{11}\)
\(\Rightarrow83-x=8^3\)
\(\Rightarrow83-x=512\)
\(\Rightarrow x=-429\)
Vậy \(x=-429\)
4)\(5^2.x-2^3.x=51\)
\(\Rightarrow x\left(5^2-2^3\right)=51\)
\(\Rightarrow x\left(25-8\right)=51\)
\(\Rightarrow17x=51\)
\(\Rightarrow x=3\)
Vậy \(x=3\)
5)\(3^x+4.3^x=5.3^7\)
\(\Rightarrow3^x\left(1+4\right)=5.3^7\)
\(\Rightarrow5.3^x=5.3^7\)
\(\Rightarrow3^x=3^7\)
\(\Rightarrow x=7\)
Vậy \(x=7\)
6)\(7.2^x-2^x=6.32\)
\(\Rightarrow2^x\left(7-1\right)=6.2^5\)
\(\Rightarrow6.2^x=6.2^5\)
\(\Rightarrow2^x=2^5\)
\(\Rightarrow x=5\)
Vậy \(x=5\)
7)\(15^{3-x}=225\)
\(\Rightarrow15^{3-x}=15^2\)
\(\Rightarrow3-x=2\)
\(\Rightarrow x=1\)
Vậy \(x=1\)
8)\(4.5^x-3=97\)
\(\Rightarrow4.5^x=100\)
\(\Rightarrow5^x=25\)
\(\Rightarrow5^x=5^2\)
\(\Rightarrow x=2\)
Vậy \(x=2\)
9)\(171-3.2^x=123\)
\(\Rightarrow3.2^x=48\)
\(\Rightarrow2^x=16\)
\(\Rightarrow2^x=2^4\)
\(\Rightarrow x=4\)
Vậy \(x=4\)
10)\(180-4.x^5=32\)
\(\Rightarrow4.x^5=148\)
\(\Rightarrow x^5=37\)//Đề có lỗi không ???

1)Đưa về lũy thừa cùng cơ số 2
82= \(\left(2^3\right)^2=2^6\) 323= \(\left(2^5\right)^3=2^{15}\) 644= \(\left(2^6\right)^4=2^{24}\) 43= \(\left(2^2\right)^{^3}=2^6\)
2)Đưa về lũy thừa cùng cơ số 3
93= \(\left(3^2\right)^3=3^6\) 274= \(\left(3^3\right)^4=3^{12}\) 95= \(\left(3^2\right)^5=3^{10}\) 816= \(\left(3^4\right)^6=3^{24}\)
3)Đưa về lũy thừa cùng cơ số 2
83:42= \(\left(2^3\right)^3:\left(2^2\right)^2=2^9:2^4=2^5\) 162:32= \(\left(2^4\right)^2:2^5=2^8:2^5=2^3\)
\(64^4:4^3=\left(2^6\right)^4:\left(2^2\right)^3=2^{24}:2^6=2^{18}\) 323:82= \(\left(2^5\right)^3:\left(2^3\right)^2=2^{15}:2^6=2^9\)

a) 5x * 5 = 54
5x+1 = 54
=> x = 3
c) (x-1)2=25
(x-1)2=52
x - 1 = 5
x = 6
a, 5x . 5 = 54
=> 5x + 1 = 54
=> x + 1 = 4
=> x = 3
vậy_
câu b đề k rõ
c, (x - 1)2 = 25
=> (x - 1)2 = (+ 5)2
=> x - 1 = + 5
=> x = 6 hoặc x = -4

1/
a. \(x^3-2=25\)
\(x^3=25+2\)
\(x^3=27\)
\(\Rightarrow x=3\)
b.\(\left(x-3\right)^2=25\)
\(\left(x-3\right)^2=5^2\)
\(\Rightarrow x-3=5\)
\(\Rightarrow x=8\)
1,a, x^3-2=25 b, (x-3)^2=25 c, x^3-x^2=55 d,[(8.x-12):4].3^7=3^10
x^3=27 (x-3)^2=5^2 không có giá trị x (8.x-12):4=3^3
x^3=3^3 x-3=5 8.x-12=108
x=3 x=8 8.x=120
x=15
2, a, \(7^6:7^4+3^4.3^2-3^7:3\) b, 1736-(21-16).32+6.7^2 c,56.17+17.44-4^3.5+6.(3^2-2)
=\(7^2+3^6-3^6\) =1736-5.32+6.49 =17.(56+44)-320+42
=\(49\) =1736-160+294 =17.10-278
=1736+134 =170-278
=1870 =-108
d, 3.10^2-[1200-(4^2-2.3)^3]
=300-[1200-(16-6)^3]
=300-(1200-10^3)
=300-(1200-1000)
=300-200
=100

a)
7-x-25-7=-25
-x-25=-25
-x=0
x=0
b)
(3x-24).73=2.74
3x-24 = 2.74 : 73 = 2.74-3=2.7=14
3x-16=14
3x=14+16=30
x=30:3=10
\(\frac{3^7.3^9}{3^{14}}+x^2=25\)
\(\frac{3^{16}}{3^{14}}+x^2=5^2\)
\(3^2+x^2=5^2\)
\(x^2=5^2-3^2=16=4^2=\left(-4\right)^2\)
\(=>\orbr{\begin{cases}x=4\\x=-4\end{cases}}\)
Vậy ...
\(\Leftrightarrow3^{16}\text{:}3^{14}+x^2=25.\)
\(\Leftrightarrow3^2+x^2=25\)
\(\Leftrightarrow x^2=25-3^2=16\)
\(\Rightarrow\orbr{\begin{cases}x=5\\x=-5\end{cases}}\)
Vậy \(x\in\left\{-5,5\right\}.\)