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Trả lời :
\(a,\frac{3}{2}\times\left(\frac{5}{7}-\frac{4}{3}\right)-\frac{4}{3}\times\left(\frac{5}{7}-\frac{3}{2}\right)\)
\(=\frac{3}{2}\times\frac{5}{7}-\frac{3}{2}\times\frac{4}{3}-\frac{4}{3}\times\frac{5}{7}+\frac{4}{3}\times\frac{3}{2}\)
\(=\frac{3}{2}\times\frac{5}{7}-\frac{4}{3}\times\frac{5}{7}\)
\(=\frac{5}{7}\times\left(\frac{3}{2}-\frac{4}{3}\right)\)
\(=\frac{5}{42}\)
b, Tương tự câu a. Kết quả \(=-\frac{3}{7}\)
\(\left(-5\right)^3-\left(3^3+4\right)\cdot\left(-2\right)+\left(3-27\right):4\)
\(=-125-\left(27-4\right)\cdot\left(-2\right)+\left(-24\right):4\)
\(=-125-23\cdot\left(-2\right)-24:4\)
\(=-125-\left(-46\right)-6\)
\(=-125+46-6=-79-6=-88\)
tớ làm nhầm rồi. sorry
\(\left(-5\right)^3-\left(3^3+4\right)\cdot\left(-2\right)+\left(3-27\right):4\)
\(=-125-\left(27+4\right)\cdot\left(-2\right)+\left(-24\right):4\)
\(=-125-31\cdot\left(-2\right)-24:4\)
\(=-125-\left(-62\right)-6\)
\(=-125+62-6=-63-6=-69\)
a) Ta có: \(\dfrac{-3}{5}x+\dfrac{-7}{4}=\dfrac{3}{10}\)
\(\Leftrightarrow\dfrac{-3}{5}x=\dfrac{3}{10}+\dfrac{7}{4}=\dfrac{41}{20}\)
\(\Leftrightarrow x=\dfrac{41}{20}:\dfrac{-3}{5}=\dfrac{41}{20}\cdot\dfrac{-5}{3}\)
hay \(x=-\dfrac{41}{12}\)
Vậy: \(x=-\dfrac{41}{12}\)
\(\dfrac{5\cdot4^6\cdot9^4-3^9\cdot\left(-8\right)^4}{4\cdot2^{13}\cdot3^8+2\cdot8^4\cdot\left(-27\right)^3}\)
\(=\dfrac{5\cdot2^{12}\cdot3^8-3^9\cdot2^{12}}{2^{15}\cdot3^8-2^{13}\cdot3^9}\)
\(=\dfrac{2^{12}\cdot3^8\cdot\left(5-3\right)}{2^{13}\cdot3^8\left(2^2-3\right)}=\dfrac{1}{2}\cdot\dfrac{2}{1}=1\)