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a) \(4x=3y<=>\frac{x}{3}=\frac{y}{4}=>\frac{x}{15}=\frac{y}{20}\)
\(7y=5z<=>\frac{y}{5}=\frac{z}{7}=>\frac{y}{20}=\frac{z}{28}\)
Ap dung tinh chat bac cau ta duoc:
\(\frac{x}{15}=\frac{y}{20}=\frac{z}{28}=>\frac{2x}{30}=\frac{3y}{60}=\frac{z}{28}=\frac{2x+3y-z}{30+60-28}=\frac{186}{62}=3\)
=> x = 45 ; y=60 ; z=84
(3x)2 : 33 = \(\frac{1}{243}\)
<=> 32x : 33 = \(\frac{1}{3^5}\)
<=> 32x - 3 = 3-5
=> 2x - 3 = -5
2x = -5 + 3
2x = -2
x = -2 : 2
x = -1
\(\left(3^x\right)^2:3^3=\frac{1}{243}\Rightarrow3^{2x}:3^3=\frac{1}{3^5}\Rightarrow3^{2x-3}=3^{-5}\Rightarrow2x-3=-5\Rightarrow2x=-2\Rightarrow x=-1\)
a) 3x+1=9x
3x+1=(32)x
3x+1=32x
=>x+1=2x
x-2x=-1
-x=-1
=>x=1
b)32x-1=243
32x-1=35
=>2x-1=5
2x=6
x=3
(3.x)^2 : 3^3=243
9.x^2 : 27=243
9.x^2=243.27
9.x^2=6561
x^2=6561:9
x^2=729
X=27
( 1/3 ) x + ( 1 / 3 ) x - 2 = 10 / 243
( 1 / 3 ) x ( 1 + ( 1/3 ) -2 = 10 / 243
( 1 / 3 ) x . 10 = 10 / 243
( 1 / 3 ) x = 1/243
( 1 / 3 ) x = ( 1/3 ) 5
=> x = 5
32x-1=243
Mà 243=35
=>2x-1=5
=>2x=5+1
=>2x=6
=>x=6:2
=>x=3
\(3^{2x-1}=243=3^5\)
\(\Rightarrow2x-1=5\)
\(\Rightarrow2x=6\)
\(\Rightarrow x=3\)
34x - 1 : 3x = 243
=> 34x - 1 - x = 35
=> 33x - 1 = 35
=> 3x - 1 = 5
=> 3x = 6
=> x = 2
Vậy x = 2
\(3^{4x-1}:3^x=243\)
\(\Rightarrow3^{4x-1}:3^x=3^5\)
\(\Rightarrow4x-1=5\)
\(\Rightarrow4x=5+1\)
\(\Rightarrow4x=6\)
\(\Rightarrow x=\frac{3}{2}\)