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\(A=\frac{34}{7.13}+\frac{51}{13.22}+\frac{85}{22.37}+\frac{68}{37.49}\)
\(=\frac{17.2}{7.13}+\frac{17.3}{13.22}+\frac{17.5}{22.37}+\frac{17.4}{37.49}\)
\(=17\left(\frac{2}{7.13}+\frac{3}{13.22}+\frac{5}{22.37}+\frac{4}{37.49}\right)\)
\(=\frac{17}{3}\left(\frac{6}{7.13}+\frac{9}{13.22}+\frac{15}{22.37}+\frac{12}{37.49}\right)\)
\(=\frac{17}{3}\left(\frac{1}{7}-\frac{1}{13}+\frac{1}{13}-\frac{1}{22}+...+\frac{1}{37}-\frac{1}{49}\right)\)
\(=\frac{17}{3}\left(\frac{1}{7}-\frac{1}{49}\right)\)\(=\frac{17}{3}.\frac{6}{49}=\frac{17.2}{49}=\frac{34}{49}\)
Có : \(\frac{17}{24}=\frac{34}{48}\)
Vì 48 < 49 => \(\frac{34}{48}>\frac{34}{49}\). Hay \(\frac{17}{24}>A\)

34 + 27 - (85 + 27) + 85
=34 + 27 -112 + 85
=61 - 112 + 85
= - 51 + 85
= 34

c; 37.(24 - 77) - 24.(37 - 77)
= 37.24 - 37.77 - 24.37 + 24.77
= (37.24 - 24.37) - (37.77 - 24.77)
= 0 - 77.(37 - 24)
= - 77 . 13
= - 1001

a) (-351) + (-74) + 51 + (-126) + 149
= (59 + 149) + ((-74) + (-126)) + (-351)
= 200 + (-200) + (-351)
= 0 + (-351)
= -351

=(5016+912). 37 : 13 : 74
=5928.37 : 13 : 74
=219336 : 13 : 74
=16872:74
=2410
(456.11+912).37:13:74
= (456.11+912):13:(74:37)
= (456.11+456.2):13:2
= 456.(11+2):13:2
= 456.13:13:2
= (456:2).(13:13)
= 228.1
= 228

a,(-15)-23+(-85)-77=[(-15)+(-85)]-(23+77)=(-100)-100=-200
b,(-24) + 4 + (-6) + 26 =[(-24)+(-6)]+(4+26)=(-30)+30=0
c, 34 + 35 + 36 + 37 - 14 - 15 - 16 - 17 =(34-14)+(35-15)+(36-16)+(37-17)=20+20+20+20=80

a)73.(74-72)+72.(73-74)
=74.(73-73)+(72-72)
=74.0+0
=74
b)37.(25+27)-27.(37+25)
=37.52-27.62
=1924-1674
=250
tick cho mk nha bạn
-34/37 . 74/-85
= 4/5