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HH
3
15 tháng 1 2017
Ta có:
\(\frac{3}{4}+\frac{3}{28}+\frac{3}{70}+\frac{3}{130}+\frac{3}{208}\)
\(=\frac{3}{1\times4}+\frac{3}{4\times7}+\frac{3}{7\times10}+\frac{3}{10\times13}+\frac{3}{13\times16}\)
\(=\frac{4-1}{1\times4}+\frac{7-4}{4\times7}+\frac{10-7}{7\times10}+\frac{13-10}{10\times13}+\frac{16-13}{13\times16}\) \(=1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+\frac{1}{10}-\frac{1}{13}+\frac{1}{13}-\frac{1}{16}\)
\(=1-\frac{1}{16}\)
\(=\frac{15}{16}\)
Chắc chắn đúng nhé !
QT
1
29 tháng 7 2015
X = 3/4 + 3/28 + 3/70 + .... + 3/208
X = 3/1.4 + 3/4.7 + 3/7.10 + ... + 3/13.16
X = 1 - 1/4 + 1/4 - 1/7 + 1/7 - 1/10 + .... + 1/13 - 1/16
X = 1 - 1/16
X = 15/16
NK
2
XO
12 tháng 7 2019
\(\frac{2}{4}+\frac{2}{28}+\frac{2}{70}+\frac{2}{130}+\frac{2}{208}\)
= \(\frac{2}{1.4}+\frac{2}{4.7}+\frac{2}{7.10}+\frac{2}{10.13}+\frac{2}{13.16}\)
= \(\frac{2}{3}.\left(\frac{3}{1.4}+\frac{3}{4.7}+\frac{3}{7.10}+\frac{3}{10.13}+...+\frac{3}{13.16}\right)\)
= \(\frac{2}{3}.\left(1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+\frac{1}{10}-\frac{1}{13}+\frac{1}{13}-\frac{1}{16}\right)\)
= \(\frac{2}{3}.\left(1-\frac{1}{16}\right)\)
= \(\frac{2}{3}.\frac{15}{16}\)
= \(\frac{5}{8}\)
12 tháng 7 2019
2/4 + 2/28 + 2/70 + 2/130 + 2/208
= 2/1.4 + 2/4.7 + 1/7.10 + 1/10.13 + 1/13.16
= 2/3.(1 - 1/4 + 1/4 - 1/7 + 1/7 - 1/10 + 1/10 - 1/13 + 1/13 - 1/16)
= 2/3.(1 - 1/16)
= 2/3.15/16
= 5/8
P/s: "." là nhân nhé :V
T
10 tháng 7 2015
= \(\frac{9}{1x4}+\frac{9}{4x7}+\frac{9}{7x10}+.........+\frac{9}{19x22}+\frac{9}{22x25}\)
= \(\frac{1}{3}x\left(\frac{9}{1}-\frac{9}{4}\right)+\left(\frac{9}{4}-\frac{9}{7}\right)x\frac{1}{3}+........+\left(\frac{9}{22}-\frac{9}{25}\right)x\frac{1}{3}\)
= \(\frac{1}{3}\left(\frac{9}{1}-\frac{9}{4}+\frac{9}{4}-\frac{9}{7}+....+\frac{9}{22}-\frac{9}{25}\right)\)
= \(\frac{1}{3}x\left(\frac{9}{1}-\frac{9}{25}\right)\)
= \(\frac{1}{3}x\frac{216}{25}\)
= \(\frac{72}{25}\)
nhớ ********** nha bn thân
10 tháng 7 2015
\(\frac{9}{4}+\frac{9}{28}+\frac{9}{70}+\frac{9}{130}+...+\frac{9}{418}+\frac{9}{550}\)
\(=3\left(\frac{3}{1.4}+\frac{3}{4.7}+...+\frac{3}{19.22}+\frac{3}{22.25}\right)\)
\(=3\left(1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+...+\frac{1}{22}-\frac{1}{25}\right)\)
\(=3\left(1-\frac{1}{25}\right)\)
\(=3.\frac{24}{25}=\frac{72}{25}\)
7 tháng 5 2019
A=\(\frac{1}{3}\)+\(\frac{1}{8}\)+\(\frac{1}{15}\)+\(\frac{1}{24}\)+\(\frac{1}{35}\)+\(\frac{1}{48}\)+\(\frac{1}{63}\)+\(\frac{1}{80}\)
A=\(\frac{1}{2}\)(\(\frac{1}{1\cdot3}\)+\(\frac{1}{2\cdot4}\)+\(\frac{1}{3\cdot5}\)+\(\frac{1}{4.6}\)+\(\frac{1}{5.7}\)+\(\frac{1}{6.8}\)+\(\frac{1}{7.9}\)+\(\frac{2}{8.10}\))
A=\(\frac{1}{2}\)(1-1/3 +1/2-1/4 + 1/3 -1/5 +1/4-1/6 +1/5 - 1/7 +1/6 -1/8 +1/7 - 1/9 +1/8 - 1/10)
A= \(\frac{1}{2}\)(1 + 1/2 -1/9 -1/10)
A=\(\frac{29}{45}\)
NT
1
15 tháng 2 2018
\(3+\frac{35}{21}+6=\frac{3}{1}+\frac{35}{21}+\frac{6}{1}=\frac{63}{21}+\frac{35}{21}+\frac{126}{21}=\frac{224}{21}\)
\(\frac{3}{8}+\frac{1}{5}+7=\frac{3}{8}+\frac{1}{5}+\frac{7}{1}=\frac{15}{40}+\frac{8}{40}+\frac{280}{40}=\frac{303}{40}\)
\(\frac{14}{28}+\frac{3}{4}+2=\frac{2}{4}+\frac{3}{4}+2=\frac{2}{4}+\frac{3}{4}+\frac{2}{1}=\frac{2}{4}+\frac{3}{4}+\frac{8}{4}=\frac{13}{4}\)
\(\frac{3}{5}+\frac{1}{4}+\frac{2}{3}=\frac{36}{60}+\frac{15}{60}+\frac{40}{60}=\frac{91}{60}\)
5 tháng 3 2018
1/ ( \(\frac{13}{2}\)+ \(\frac{14}{6}\)) - ( \(\frac{5}{15}\) + \(\frac{1}{3}\))
= \(\frac{53}{6}\) - \(\frac{2}{3}\)
= \(\frac{49}{6}\)
2/ \(\frac{4}{16}\)+ \(\frac{3}{4}\)+ \(\frac{4}{16}\) - \(\frac{3}{4}\)
= \(\frac{1}{2}\)
3/ ( \(\frac{35}{70}\)- \(\frac{2}{10}\)) + ( \(\frac{14}{8}\)-1)
= \(\frac{3}{10}\)+ \(\frac{3}{4}\)
= \(\frac{21}{20}\)
k cho mk nha
3/4 + 3/28 + 3/70 +...+ 3/10300
=3/(1×4) + 3/(4×7) + 3/(7×10) +...+ 3/(100×103)
=1 − 1/4 + 1/4 − 1/7 + 1/7 − 1/10 +...+ 1/100−1/103
=1 − 1/103
=102/103
102/103