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3.3\(^x\)+5.3\(^{x+1}\) = 16
=> 3\(^{x+1}\) + 5. 3\(^{x+1}\) = 16
=> 3\(^{x+1}\) . ( 1+5 ) = 16
=> 3\(^{x+1}\) . 6 = 16
=> 3\(^{x+1}\) = \(\dfrac{8}{3}\)
=> x không thuộc giá trị nào
\(\left(2^4:8+5.3^{x+1}\right).2=94\)
\(\Rightarrow\left(2+5.3^{x+1}\right)=94:2=47\)
\(\Rightarrow5.3^{x+1}=47-2=45\)
\(\Rightarrow3^{x+1}=9=3^2\Rightarrow x=2-1=1\)
(24:8 + 5.3x+1) . 2 = 94
2 + 5.3x.3 = 47
15.3x = 45
3x = 3 = 31
=> x = 1
Ta có :
\(3^{x-1}+5.3^{x-1}=162\)
\(\Leftrightarrow\)\(3^{x-1}\left(1+5\right)=162\)
\(\Leftrightarrow\)\(3^{x-1}.6=162\)
\(\Leftrightarrow\)\(3^{x-1}=\frac{162}{6}\)
\(\Leftrightarrow\)\(3^{x-1}=27\)
\(\Leftrightarrow\)\(3^{x-1}=3^3\)
\(\Leftrightarrow\)\(x-1=3\)
\(\Leftrightarrow\)\(x=3+1\)
\(\Leftrightarrow\)\(x=4\)
Vậy \(x=4\)
Chúc bạn học tốt ~
3x-1. (5 + 1) = 162
3x-1. 6 = 162
3x-1 = 27
3x-1 = 33
x - 1 = 3
=> x = 4
\(2^{x+2}-2^x=96\)
\(\Rightarrow2^x\cdot2^2-2^x=96\)
\(\Rightarrow2^x\left(2^2-1\right)=96\)
\(\Rightarrow2^x\left(4-1\right)=96\)
\(\Rightarrow2^x\cdot3=96\)
\(\Rightarrow2^x=96:3\)
\(\Rightarrow2^x=32\)
\(\Rightarrow2^x=2^5\)
\(\Rightarrow x=5\)
\(5^x+5^{x+1}=750\)
\(\Rightarrow5^x+5^x\cdot5=750\)
\(\Rightarrow5^x\left(1+5\right)=750\)
\(\Rightarrow5^x\cdot6=750\)
\(\Rightarrow5^x=750:6\)
\(\Rightarrow5^x=125\)
\(\Rightarrow5^x=5^3\)
\(\Rightarrow x=3\)
\(2^{x+3}+2^x=144\)
\(\Rightarrow2^x\cdot2^3+2^x=144\)
\(\Rightarrow2^x\left(2^3+1\right)=144\)
\(\Rightarrow2^x\cdot9=144\)
\(\Rightarrow2^x=144:9\)
\(\Rightarrow2^x=16\)
\(\Rightarrow2^x=2^4\)
\(\Rightarrow x=4\)
\(3^{x-1}+5.3^{x-1}=162\)
\(3^{x-1}\left(1+5\right)=162\)
\(3^{x-1}=162\div6\)
\(3^{x-1}=27\)
\(3^{x-1}=3^3\)
\(\Rightarrow x-1=3\)
\(\Rightarrow x=4\)
Ko viết lại đề
<=> 3x-1.(1+5)=162
<=> 3x-1.6=162
<=> 3x-1=27
<=> 3x-1=33
<=> x-1=3
<=> x=4
Vậy x=4.
Đúng thì tk nha :3
3^x(3+5.3)=162
3^x=9
x=2