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11 x 13 x 15 x 17 + 23 x 25 x 27 x 29 + 31 x 33 x 35 x 37 + 45 x 47 x 49 x 51
=7096860
#Hok tốt!#
\(\dfrac{11}{49}\times\dfrac{9}{1}\times\dfrac{7}{33}=\dfrac{11\times9\times7}{7\times7\times1\times11\times3}=\dfrac{9}{21}=\dfrac{3}{7}\)
A = 2 x 53 x 12 + 4 x 6 x 87 - 3 x 8 x 40
= 24 x 53 + 24 x 87 - 24 x 40
= 24 x ( 53 + 87 - 40 )
= 24 x 100
= 2400
B = 5 x 7 x 77 - 7 x 60 + 49 x 25 - 15 x 42
= 5 x 7 x 77 - 7 x 5 x 12 + 49 x 5 x 5 - 5 x 3 x 42
= 5 x 539 - 84 x 5 + 245 x 5 - 5 x 126
= 5 x ( 539 - 84 + 245 - 126 )
= 5 x 574
= 2870
a=2×53×12+4×6×87-3×8×40
a=24×53+24×87-24×40
a=24×(53+87-40)
a=24×100
a=2400
\(\frac{7}{10}-\frac{3}{10}x\frac{1}{10}+\frac{4}{25}\)
\(=\frac{7}{10}-\frac{3}{100}+\frac{4}{25}\)
\(=\frac{70}{100}-\frac{3}{100}+\frac{4}{25}\)
\(=\frac{67}{100}+\frac{4}{25}\)
\(=\frac{67}{100}+\frac{16}{100}\)
\(=\frac{83}{100}=0,83\)
\(\frac{6}{11}x\frac{3}{7}+\frac{3}{7}x\frac{5}{11}\)
\(=\frac{18}{77}+\frac{15}{77}\)
\(=\frac{33}{77}=\frac{3}{7}\)
\(49x\left(311-4807:23\right)+98210\)
\(=49x\left(311-209\right)+98210\)
\(=49x102+98210\)
\(=4998+98210\)
\(=103208\)
a) \(\frac{7}{10}-\frac{3}{10}\times\frac{1}{10}+\frac{4}{25}\)
\(=\frac{2}{5}\times\frac{1}{10}+\frac{4}{25}\)
\(=\frac{1}{25}+\frac{4}{25}\)
\(=\frac{5}{25}=\frac{1}{5}\)
b)\(\frac{6}{11}\times\frac{3}{7}+\frac{3}{7}\times\frac{5}{11}\)
\(=\frac{3}{7}\times\left(\frac{6}{11}+\frac{5}{11}\right)\)
\(=\frac{3}{7}\times1\)
\(=\frac{3}{7}\)
c)\(49\times\left(311-4807:23\right)+98210\)
\(=49\times\left(311-209\right)+98210\)
\(=49\times102+98210\)
\(=4998+98210\)
\(=103208\)
a) X = 15
b) X = 4
c ) X= 23
d) X= 11
( Chỉ là ý kiến riêng thôi nhé, nhận gạch đá )
a) \(\frac{6+x}{33}=\frac{7}{11}\)
=> (6 + x). 11 = 33.7
=> 66 + 11x = 231
=> 11x = 231 - 66
=> 11x = 165
=> x = 165 : 11
=> x = 15
b) 15/26 + x/13 = 46/52
=> x/13 = 23/26 - 15/26
=> x/13 = 4/13
=> x = 4
c) 121/27 x 54/11 < x < 100/21 : 25/126
=> 22 < x < 24
=> x = 23 (vì x là số tự nhiên)
d) 1 < 11/x < 12
=> 11/x \(\in\){2; 3; 4 ; ...; 11}
=> x \(\in\) {11/2; 11/3; ...; 1}
Vì x là số tự nhiên => x = 1
Tìm x
a) 17 + 33 : ( 2 . x - 1 ) = 20
33 :( 2 . x - 1 )= 20 - 17
33 :( 2 . x - 1 ) = 3
2 . x - 1 = 33 : 3
2 . x - 1 = 11
2 . x = 11 - 1 = 10
x = 10 : 2
x = 5
b) 25 - [ ( 2 . x + 5 ) . 7 - 15 ] : 5 = 21
[ ( 2 . x + 5 ) . 7 - 15 ] : 5 = 25 - 21
[ ( 2 . x + 5 ) . 7 - 15 ] : 5 = 4
( 2 . x + 5 ) . 7 - 15 = 5 x 4
( 2 . x + 5 ) . 7 - 15 = 20
( 2 . x + 5 ) . 7 = 20 + 15
( 2 . x + 5 ) . 7 = 35
2 . x + 5 = 35 : 7
2 . x + 5 = 5
2 . x = 5 - 5
2 . x = 0
x = 0
hok tốt
a) \(17+33:\left(2x-1\right)=20\)
\(\Rightarrow33:\left(2x-1\right)=20-17\)
\(\Rightarrow33:\left(2x-1\right)=3\)
\(\Rightarrow2x-1=33:3\)
\(\Rightarrow2x-1=11\)
\(\Rightarrow2x=11+1\)
\(\Rightarrow2x=12\)
\(\Rightarrow x=12:2\)
\(\Rightarrow x=6\)
Vậy x = 6
b) \(25-\left[\left(2x+5\right)\times7-15\right]:5=21\)
\(\Rightarrow\left[\left(2x+5\right)\times7-15\right]:5=25-21\)
\(\Rightarrow\left[\left(2x+5\right)\times7-15\right]:5=4\)
\(\Rightarrow\left(2x+5\right)\times7-15=4\times5\)
\(\Rightarrow\left(2x+5\right)\times7-15=20\)
\(\Rightarrow\left(2x+5\right)\times7=20+15\)
\(\Rightarrow\left(2x+5\right)\times7=35\)
\(\Rightarrow2x+5=35:7\)
\(\Rightarrow2x+5=5\)
\(\Rightarrow2x=5-5\)
\(\Rightarrow2x=0\)
\(\Rightarrow x=0:2\)
\(\Rightarrow x=0\)
Vậy x = 0
_Chúc bạn học tốt_
a)\(\frac{8}{3}\)
b)\(\frac{1}{5}=0,2\)
c)\(\frac{17}{135}\)
d)\(\frac{2}{3}\)
e)\(\frac{5}{2}=2,5\)
\(\frac{33}{49}\times\frac{25}{11}\times\frac{7}{15}\)
\(=\frac{33\times25\times7}{49\times11\times15}\)
\(=\frac{3\times5\times1}{7\times1\times3}\)
\(=\frac{5}{7}\)
\(\frac{33}{49}\cdot\frac{25}{11}\cdot\frac{7}{15}=\frac{3\cdot11\cdot5\cdot7\cdot5}{3\cdot11\cdot5\cdot7\cdot7}=\frac{5}{7}\)