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a) 20.16+20.35+20.49
=20.(16+35+49)
=20.100=2000
b) 5.(|-13|-500)+|-2017|
=5.(13-500)+2017
=5.(13-1)+2017
=5.12+2017
=60+2017=2077
c) (24.22-32.7)2017
=(16.4-9.7)2017
=(64-63)2017
=12017=1
d) 160:{180-[36-(22.16-22.12)]}
= 160:{180-[36-(4.16-4.12)]}
=160:{180-[36-4(16-12)]}
=
160:{180-[36-4.4]}
=
160:{180-[36-16
]}
=160:
{180-20
}
=160:160=1
a)48:64.16 bằng 48.43.4^2
Bằng 413
b)53:52+22.3 bằng 5 +12 bằng 17
c)56:54+3.33-80 bằng 5^2 +34-1 bằng 105
1) x - 36 + 12 = - x+ 10
=> x + x = 10 + 24
=> 2x = 34
=> x = 34/2 = 17
2) (x + 15) - (11 - x) = (-2)2
=> x + 15 - 11 + x = 4
=> 2x = 4 - 4
=> 2x = 0
=> x = 0
3) 40 - 4x2 = (-6)2
=> 40 - 4x2 = 36
=> 4x2 = 40 - 36
=> 4x2 = 4
=> x2 = 1
=> x = \(\pm\)1
4) (-50) + 10x2 = (-25) x |-2|
=> -50 + 10x2 = -50
=> 10x2 = -50 + 50
=> 10x2 = 0
=> x2 = 0
=> x = 0
5) |x + 1| = 2020
=> \(\orbr{\begin{cases}x+1=2020\\x+1=-2020\end{cases}}\)
=> \(\orbr{\begin{cases}x=2019\\x=-2021\end{cases}}\)
6) (x + 1)5 + 8 = 0 (xem lại đề)
7) (-20) + x3 : 16 = -24
=> x3 : 16 = -24 + 20
=> x3 : 16 = -4
=> x3 = -4 . 16
=> x3 = -64 = (-4)3
=> x = -4
9) x14 = x17
=> x14 - x17 = 0
=> x14(1 - x3) = 0
=> \(\orbr{\begin{cases}x^{14}=0\\1-x^3=0\end{cases}}\)
=> \(\orbr{\begin{cases}x=0\\x=1\end{cases}}\)
10) (-36) + (1 - x)2 = 0
=> (1 - x)2 = 36
=> (1 - x)2 = 62
=> \(\orbr{\begin{cases}1-x=6\\1-x=-6\end{cases}}\)
=> \(\orbr{\begin{cases}x=-5\\x=7\end{cases}}\)
a)56 : 52 + 2.22 - 122 b)75:72+46:43+ 225
c)38: 35 + 43 +124 d)85: 83 + 74:72+69
e)97: 95+ 3.32 - 1200. F)49: 47: 4.42 - 192
Bài làm :
a) \(5^6:5^2+2.2^2-12^2\)
\(=5^4+2^3-12^2\)
\(=625+8-144\)
\(=633-144\)
\(=489\)
b) \(7^5:7^2+4^6:4^3+225\)
\(=7^3+4^3+225\)
\(=343+64+225\)
\(=407+225\)
\(=632\)
c) \(3^8:3^5+4^3+124\)
\(=3^3+64+124\)
\(=27+64+124\)
\(=91+124\)
\(=215\)
d) \(8^5:8^3+7^4:7^2+69\)
\(=8^2+7^2+69\)
\(=64+49+69\)
\(=113+69\)
\(=182\)
e) \(9^7:9^5+3.3^2-120^0\)
\(=9^2+3^3-1\)
\(=81+27-1\)
\(=108-1\)
\(=107\)
f) \(4^9:4^7:4.4^2-192\)
\(=4^2:4^3-192\)
\(=4^{-1}-192\)
\(=-191,75\)
a: \(=27+5^2-1=27+25-1=52-1=51\)
b: \(=320:\left\{180-36+8\cdot16+4\cdot12\right\}=320:320=1\)