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5x = 625
=> 5x = 54
=> x = 4
3 . 2x = 96
=> 2x = 96 : 3
=> 2x = 32
=> 2x = 25
=> x = 5
c) 8x + 1 = 165
=> (23)x + 1 = (24)5
=> 23(x + 1) = 24.5
=> 23(x + 1) = 220
=> 3(x + 1) = 20
=> x + 1 = 20:3
=> x + 1 = 20/3
=> x = 20/3 - 1
=> x = 17/3
1) 5x = 625
<=. 5x = 54
<=> x = 4
=> x = 4
2) 3.2x = 96
<=> 2x = 96 : 3
<=> 2x = 32
<=> 2x = 25
<=> x = 5
=> x = 5
3) 8x + 1 = 165
<=> (23)x + 1 = (24)5
<=> 23.(x + 1) = 24.5
<=> 3.(x + 1) = 4.5
<=> 3.(x + 1) = 20
<=> x + 1 = 20 : 3
<=> x + 1 = 20/3
<=> x = 20/3 - 1
<=> x = 17/3
=> x = 17/3
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a)9x-1=9
9x-1=91
x-1=1
x=2
Vây x=2
b)7x-x=521:519+3.22-70
6x=52+12-1
6x=25+11
6x=36
x=6
Vậy x=6
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9\(^{x-1}\)=3\(^4\) 9\(^{x-1}\)=9\(^2\) suy ra:x-1=2 x=1+2 x=3
x\(^2\)+7\(^0\)=5\(^{21}\):5\(^{19}\)+3x2\(^2\) x\(^2\)+1=5\(^2\)+3x4 x\(^2\)+1=25+12 x\(^2\)+1=37 x\(^2\)=37-1 x\(^2\)=36 x\(^2\)=6\(^2\)hoặc x\(^2\)=(-6)\(^2\) suy ra x=6 hoặc x=-6
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1) \(-\frac{2}{3}\left(x-\frac{1}{4}\right)=\frac{1}{3}\left(2x-1\right)\)
\(-\frac{2}{3}x+\frac{1}{6}=\frac{2}{3}x-\frac{1}{3}\)
\(-\frac{2}{3}x-\frac{2}{3}x=-\frac{1}{3}-\frac{1}{6}\)
\(-\frac{4}{3}x=-\frac{1}{2}\)
\(x=\left(-\frac{1}{2}\right):\left(-\frac{4}{3}\right)\)
\(x=\frac{3}{8}\)
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7x-x =521: 519. 3.22-70
=>6x =521: 519+3.22-70
=> 6x = 52 + 3.4-1
=> 6x =25+3.2-1
=> 6x = 25+6-1
=> 6x = 30
=> x = 30:6
=> x = 5
3.2x+1 - 5 = 91
3.2x+1 = 96
2x+1 = 32
2x+1 = 25
=> x + 1 = 5
x = 5 - 1 = 4