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\(\dfrac{\left(2^3.5.7\right).\left(5^2.7^3\right)}{2.5.\left(7^2\right)}=\dfrac{2^3.\left(5.5^2\right).\left(7.7^3\right)}{2.5.7^2}\)
\(=\dfrac{2^3.5^3.7^4}{2.5.7^2}=\left(2^3:2\right).\left(5^3:5\right).\left(7^4:7^2\right)=2^2.5^2.7^2\)
=\(\left(2.5.7\right)^2=4900\)
(23 . 5 . 7) . (52 . 73) / 2 . 5 (72)
= (8 . 5 . 7) . (25 . 343) / 2 . 5 . 49
= 280 . 8575 / 490
= 2401000 / 490
= 4900
Ta có:
\(\frac{2^3.3^4}{2^2.3^2.5}=\frac{2.3^2}{5}=\frac{18}{5}\)
\(\frac{2^4.5^2.11^2.7}{2^3.5^3.7^2.11}=\frac{2.11}{5.7}=\frac{22}{35}\)
a) \(\frac{8}{2^3.25}=\frac{8}{8.25}=\frac{1}{25}\)
\(\frac{10}{2^2.5^2.7}=\frac{100}{10^2.7}=\frac{1}{70}\)
Mẫu chung của 2 phân số là 350
a,(19x+2.52):14=(13-8)2-42
(19x+2.25):14=52-42
19x+50=9.14
19x=126-50
19x=76
x=76:19=4
b,(3x-24).73=2.74
(3x-24).73=2.7.73
(3x-16).73=14.73
3x-16=14
3x=30
x=10
Ta có :
\(B=\frac{3^2.5^2.7^2.3^3.7^2}{3^2.5^2.7^4}=\frac{3^4.5^2.7^4}{3^2.5^2.7^4}=\frac{3^4}{3^2}=3^2=9\)
Vậy B = 9.
k nha bạn
B=\(\frac{\left(9.25.49\right).\left(9.49\right)}{735^2}\)
B=\(\frac{11025.441}{540225}\)
B=\(\frac{4862025}{540225}\)
B=9
\(B=\frac{\left(3^2.5^2.7^2\right).\left(3^3.7^2\right)}{3.5.7^2}=\frac{3^5.5^2.7^4}{3.5.7^2}=\frac{3^4.5.7^2}{1}=19845\)
\(B=\frac{3^2\times5^2\times7^2\times3^3\times7^2}{3\times5\times7^2}=\frac{3^5\times5^2\times7^4}{3\times5\times7^2}=3^4\times5\times7^2=19845\)
1,2 + 2,3 + 2,4 + 2,5 + 2,6 + 2,7 + 2,8
= (1,2 + 2,8) + (2,3 + 2,7) + (2,4 + 2,6) + 2,5
= 4 + 5 + 5 + 2,5
= 4 + 10 + 2,5
= 14 + 2,5
= 16,5
ủng hộ tớ nha
{[83 - (42.10+22.5):18] + 27}.32 + 100 = {[83 - 180:18]+27}.9 + 100 = {73 + 27}.9 +100 = 900 + 100 = 1000
{[83 - (4^2.10 + 2^2.5):18]+27}.3^2 + 100 = [83- 10 + 27].3^2 = 100.9 = 900
ko
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A.\(\frac{2^3.9^2}{2^2.3^2.5}=\frac{2^2.2.\left(3^2\right)^2}{2^2.3^2.5}=\frac{2.3^2}{5}=\frac{18}{5}\)
B.\(\frac{2^4.5^5.11^2.7}{2^3.5^3.7^2.11}=\frac{2^3.2.5^3.5^2.11.11.7}{2^3.5^3.7.7.11}=\frac{2.5^2.11}{7}=\frac{61}{7}\)
32.5 - 22.7 + 83
= 9.5 - 4.7 + 83
= 45 - 28 + 83
= 17 + 83
= 100
32.5 - 22.7 + 83
= 9.5 - 4.7 + 83
= 45 - 28 + 83
= 17 + 83
= 100