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e) 5(3-2x)+5(x-4)=6-4x
⇔15-10x+5x-20-6+4x=0
⇔-x-11=0
hay -x=11
⇔x=-11
Vậy: x=-11
g) 2(4x-8)-7(3+x)=|-4|(3-2)
⇔8x-16-21-7x=4
⇔x-37=4
hay x=41
Vậy: x=41
k) -7(5-x)-2(x-10)=15
⇔-35+7x-2x+20=15
⇔5x-15=15
hay 5x=30
⇔x=6
Vậy: x=6
m) -4(x+1)+(89x-3)=24
⇔-4x-4+89x-3=24
⇔85x-7=24
⇔85x=31
hay \(x=\frac{31}{85}\)(ktm x∈Z)
Vậy: x∈∅
q) 10(x-7)-8(x+5)=6*(-5)+24
⇔10x-70-8x-40=-6
⇔2x-110=-6
⇔2x=104
hay x=52
Vậy: x=52
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\(\left\{\left[\left(10-x\right)\cdot2-1\right]:2+7\right\}\cdot2=24\)
\(\left[\left(10-x\right)\cdot2-1\right]:3+7=\frac{24}{2}=12\)
\(\left[\left(10-x\right)\cdot2-1\right]:3=12-7=5\)
\(\left(10-x\right)\cdot2-1=5\cdot3=15\)
\(\left(10-x\right)\cdot2=15+1=16\)
\(10-x=\frac{16}{2}=8\)
\(x=10-8\)
\(\Rightarrow x=2\)
Vậy ...
{ [ ( 10 - x ) . 2 - 1 ] : 3 + 7 } . 2 = 24
[ ( 10 - x ) . 2 - 1 ] : 3 + 7 = 24 : 2
[ ( 10 - x ) . 2 - 1 ] : 3 + 7 = 12
[ ( 10 - x ) . 2 -1 ] : 3 = 12 - 7
[ ( 10 -x ) . 2 - 1 ] : 3 = 5
( 10 - x ) . 2 - 1 = 5 . 3
( 10 - x ) . 2 - 1 = 15
( 10 - x ) . 2 = 15 + 1
( 10 - x ) . 2 = 16
10 - x = 16 : 2
10 - x = 8
x = 10 - 8
x = 2
Vậy x = 2
chúc bn hok tốt
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a/
\(-24+\left(x+4\right)^4=10^3\)3
\(\Leftrightarrow-24+x^4+16x^3+96x^2+256x+256=10^3\)
<=>\(x^4+16x^3+96x^2+256x-768=0\)
Giải trên tập số phức ta được
\(x=-\sqrt{32}-4\)
\(x=\sqrt{32}-4\)
\(x=-\sqrt{32}i-4\)
\(x=\sqrt{32}1-4\)=> Phần a kog có giá trị nguyên nào của x thỏa mãn phương trình
b/
2(x+7)-3(6-x)=-24
<=> 2x+14-18+3x=-24
<=>5x=-20
<=>x=-4
Vậy x=-4
c/
\(3x-6x^2=0\)
\(\Leftrightarrow3x\left(1-2x\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}3x=0\\1-2x=0\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=0\\x=\frac{1}{2}\end{cases}}\)(x = 1/2 kog thỏa mãn yêu cầu)
Vậy x=0
a/\(\left(x+4\right)^4=1000+24\)
\(\Rightarrow x^4+8x^2+4^4-1024=0\)
\(\Rightarrow x^4+8x^2-768\)
\(\Rightarrow x^4-24x+32x-768=0\)
\(\Rightarrow x.\left(x-24\right)+32.\left(x-24\right)\)
\(\Rightarrow\left(x+32\right).\left(x-24\right)\Rightarrow\orbr{\begin{cases}x=-32\\x=24\end{cases}}\)
b/2x+14-18+3x=-24
5x=-24-14+18
x=-20/5=-4
c/3x-6x\(^2\) =0
\(3x.\left(1-2x\right)=0\)
\(\Rightarrow\orbr{\begin{cases}3x=0\rightarrow x=0\\1-2x=0\rightarrow x=\frac{1}{2}\end{cases}}\)
KL bAN tu lam nhe
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a/ 7*25-49/7*24+21
=( 7*25 ) - ( 49/7 ) * ( 24+21)
= 175 - 7 * 45
= 175 - ( 7*45 )
=175 - 315
= -140
mk k bít đúng k
-36/120 - 35/120
= -1/120
=-1/120