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15+2x=27
=> 2x = 27 - 15
=> 2x = 12
=> x = 12 : 2
=> x = 6
Vậy x = 6
\(125-2x=25\\ 2x=125-25\\ 2x=100\\ x=50\\ 100-\left(x+15\right)=27\\ x+15=100-27\\ x+15=73\\ x=73-15\\ x=58\)
\(125-2x=25\Leftrightarrow-2x=25-125\Leftrightarrow-2x=-100\Leftrightarrow x=\dfrac{-100}{-2}=50\)
\(100-\left(x+15\right)=27\Leftrightarrow-\left(x+15\right)=27-100\Leftrightarrow-\left(x+15\right)=-73\Leftrightarrow x+15=73\Leftrightarrow x=73-15\Leftrightarrow x=58\)
`@` `\text {Ans}`
`\downarrow`
`c)`
`( 34 - 2x ) . ( 2x - 6 ) = 0`
`=>`\(\left[{}\begin{matrix}34-2x=0\\2x-6=0\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}2x=34\\2x=6\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=34\div2\\x=6\div2\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=17\\x=3\end{matrix}\right.\)
Vậy, `x \in {17; 3}`
`d)`
`( 2019 - x ) . ( 3x - 12 ) =0` `?`
`=>`\(\left[{}\begin{matrix}2019-x=0\\3x-12=0\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=2019-0\\3x=12\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=2019\\x=12\div3\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=2019\\x=4\end{matrix}\right.\)
Vậy, `x \in {2019; 4}`
`e) `
`57 . ( 9x - 27 ) = 0`
`=>`\(9x-27=0\div57\)
`=> 9x - 27 = 0`
`=> 9x = 27`
`=> x = 27 \div 9`
`=> x = 3`
Vậy, `x = 3`
`f)`
`25 + ( 15 - x ) = 30`
`=> 15 - x = 30 - 25`
`=> 15 - x = 5`
`=> x = 15 -5 `
`=> x = 10`
Vậy, `x = 10`
`g) `
`43 - ( 24 - x ) = 20`
`=> 24 - x = 43 - 20`
`=> 24 - x = 23`
`=> x = 24 - 23`
`=> x = 1`
Vậy, `x = 1`
`h) `
`2 . ( x - 5 ) - 17 = 25`
`=> 2 ( x - 5) = 25+17`
`=> 2 ( x - 5) = 42`
`=> x - 5 = 42 \div 2`
`=> x - 5 = 21`
`=> x = 21 + 5`
`=> x = 26`
Vậy, `x = 26`
`i)`
`3 . ( x + 7 ) - 15 = 27`
`=> 3(x + 7) = 27 + 15`
`=> 3(x + 7) = 42`
`=> x +7 = 42 \div 3`
`=> x + 7 = 14`
`=> x = 14 - 7`
`=> x = 7`
Vậy, `x = 7`
`j)`
`15 + 4 . ( x - 2 ) = 95`
`=> 4(x - 2) = 95 - 15`
`=> 4(x - 2) = 80`
`=> x - 2 = 80 \div 4`
`=> x - 2 = 20`
`=> x = 20 + 2`
`=> x = 22`
Vậy, `x = 22`
`k)`
`20 - ( x + 14 ) = 5`
`=> x + 14 = 20 - 5`
`=> x + 14 = 15`
`=> x = 15 - 14`
`=> x = 1`
Vậy, `x = 1`
`l) `
`14 + 3 . ( 5 - x ) = 27`
`=> 3(5 - x) = 27 - 14`
`=> 3(5 - x) = 13`
`=> 5 - x = 13 \div 3`
`=> 5 - x = 13/3`
`=> x = 5- 13/3`
`=> x = 2/3`
Vậy, `x = 2/3.`
`@` `\text {Kaizuu lv uuu}`
2x+15=27-4x, collect the terms
2x+4x=27-15
6x=12, divid through by 6
6x/6=12/6
x=2
ủng hộ nha!
2x + 15 = -27
2x = (-27) - 15
2x = -42
x = (-42) : 2
x = -21
2x + 15 = -27
2x = (-27) - 15
2x = -42
x = (-42) : 2
x = -21
a) Ta có: 2 x + 1 3 = 3 3 nên 2x + l = 3. Do đó x = l.
b) Ta có: 2 x - 1 3 = 5 3 nên 2x - 1 = 5. Do đó x = 3.
c) Ta có: x + 1 4 = 2 x 4 nên x +1 = 2x. Do đó x = 1.
d) Ta có: 2 x - 1 5 = x 5 nên 2x - l = x. Do đó x = l
\(2x+15=-27\)
\(\Rightarrow2x=-42\)
\(\Rightarrow x=-21\)
2x+15=-27
=> 2x = -27 - 15
=> 2x = -42
=> x = -42 : 2 = -21