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( 1 + 3 + 5 + 7 +... + 2003 + 2005 ) x ( 125125 x 127 - 127127 x 125 )
= ( 1 + 3 + 5 + 7 + ... + 2003 + 2005 ) x ( 125 x 1001 x 127 - 127 x 1001 x 125 )
= ( 1 + 3 + 5 + 7 + ... + 2003 + 2005 ) x 0
= 0
~ Thiên Mã ~
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a) \(\frac{35}{14}=\frac{5\times7}{2\times7}=\frac{5}{2}\)
\(\frac{125}{50}=\frac{5\times5\times5}{2\times5\times5}=\frac{5}{2}\)
b)\(\frac{4\times5+4\times11}{8\times7+4\times3}=\frac{4\times\left(5+11\right)}{4\times\left(2\times7+3\right)}=\frac{16}{17}\)
c) \(\frac{3\times11+7\times11}{22\times2+11\times6}=\frac{11\times\left(3+7\right)}{22\times\left(2+3\right)}=\frac{11\times10}{22\times5}=\frac{11\times2\times5}{11\times2\times5}=1\)

(x:125)-4=25
x:125=25+4
x:125=29
x=29.125
x=3625 bn nhé
tk cho mk nha, mk đg bị âm điểm

32,5x7,3+32,5x2,7-125
=32,5x(7,3+2,7)-125
=32,5x10-125
=325-125
=200 k mk~mk k lại!!!!

b, 125 - 25:3 x 12 = 125 - \(\frac{25}{3}\)x 12 = 125 - 100 = 25
a, 50% + \(\frac{7}{12}\)- \(\frac{1}{2}\) = \(\frac{50}{100}+\frac{7}{12}-\frac{1}{2}=\frac{1}{2}-\frac{1}{2}+\frac{7}{12}=0+\frac{7}{12}=\frac{7}{12}\)