Question

[bê trần]

(2x-1)(x+2)\(\le\)0

giải bất phương trình

help me

Answer 1

[Mysterious Person]

ta có : \(\left(2x-1\right)\left(x+2\right)=0\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{2}\\x=-2\end{matrix}\right.\)

mà ta có : \(\left(2x-1\right)\left(x+2\right)=2x^2+3x-2\) \(\Rightarrow a=2>0\)

\(\Rightarrow\left(2x-1\right)\left(x+2\right)\le0\Leftrightarrow-2\le x\le\dfrac{1}{2}\)