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a: \(\left(2x-3\right)\cdot12=6^2\)
\(\Leftrightarrow2x-3=3\)
hay x=3
a) \(60\%x+\frac{2}{3}x=\frac{1}{3}.6\frac{1}{3}\)
=> \(\frac{3}{5}x+\frac{2}{3}x=\frac{19}{9}\)
=> \(\frac{19}{15}x=\frac{19}{9}\)
=> \(x=\frac{19}{9}:\frac{19}{15}\)
=> \(x=\frac{5}{3}\)
b) (-0,6x - 1/3) . 3/5 - (-1) = 1/3
=> (-3/5x - 1/3) .3/5 = 1/3 - 1
=> (-3/5x - 1/3).3/5 = -2/3
=> -3/5x - 1/3 = -2/3 : 3/5
=> -3/5x - 1/3 = -10/9
=> -3/5x = -10/9 + 1/3
=> -3/5x = -7/9
=> x = -7/9 : (-3/5)
=> x = 35/27
a,60%x+2/3x=1/3.6 1/3
x(60%+2/3)=19/6
x.19/15=19/6
x=19/6 : 19/15
x=5/2
b,[-0,6x-1/2].3/4-(-1)=1/3
(-3/5x-1/2).3/4=1/3-1
(-3/5x-1/2).3/4=-2/3
-0,6x-0,5=-2/3:3/4
................................
c,2[1/2x-1/3]-3/2=1/4
....................................... (tương tự...)
d,Số đó là:720% : 2/3=10,8
a: =>3^x=3^4*3=3^5
=>x=5
b: =>\(2^{x+1}=2^5\)
=>x+1=5
=>x=4
c: \(\Leftrightarrow3^{x+2-3}=3\)
=>x-1=1
=>x=2
d: \(\Leftrightarrow x^2=\dfrac{32}{2}=16\)
=>x=4 hoặc x=-4
e: (2x-1)^4=81
=>2x-1=3 hoặc 2x-1=-3
=>2x=4 hoặc 2x=-2
=>x=-1 hoặc x=2
f: (2x-6)^4=0
=>2x-6=0
=>x-3=0
=>x=3
a) \(3^x=81\cdot3\)
\(\Rightarrow3^x=3^4\cdot3\)
\(\Rightarrow3^x=3^5\)
\(\Rightarrow x=5\)
b) \(2^{x+1}=32\)
\(\Rightarrow2^{x+1}=2^5\)
\(\Rightarrow x+1=5\)
\(\Rightarrow x=4\)
c) \(3^{x+2}:27=3\)
\(\Rightarrow3^{x+2}:3^3=3\)
\(\Rightarrow3^{x+2-3}=3\)
\(\Rightarrow3^{x-1}=3\)
\(\Rightarrow x-1=1\)
\(\Rightarrow x=2\)
d) \(2x^2=32\)
\(\Rightarrow x^2=16\)
\(\Rightarrow x^2=4^2\)
\(\Rightarrow\left[{}\begin{matrix}x=4\\x=-4\end{matrix}\right.\)
e) \(\left(2x-1\right)^4=81\)
\(\Rightarrow\left(2x-1\right)^4=3^4\)
\(\Rightarrow\left[{}\begin{matrix}2x-1=3\\2x-1=-3\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}2x=4\\2x=-2\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=2\\x=-1\end{matrix}\right.\)
f) \(\left(2x-6\right)^4=0\)
\(\Rightarrow2x-6=0\)
\(\Rightarrow2x=6\)
\(\Rightarrow x=6:2\)
\(\Rightarrow x=3\)
a: x=3
b: \(2x-1=2\)
hay \(x=\dfrac{3}{2}\)
c: \(\Leftrightarrow\left[{}\begin{matrix}2x-3=3\\2x-3=-3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=0\end{matrix}\right.\)
Ta có : 7(x - 1) + 2x(x - 1) = 0
<=> (2x + 7)(x - 1) = 0
\(\Leftrightarrow\orbr{\begin{cases}2x+7=0\\x-1=0\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}2x=-7\\x=1\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=-\frac{7}{2}\\x=1\end{cases}}\)
ai trả lời trức thì tick cho một sao
\(\left(2x-1\right)^4=3.6^2-27\)
\(\Leftrightarrow\left(2x-1\right)^4=81\)
\(\Leftrightarrow\left(2x-1\right)^2=9\)
\(\Leftrightarrow\left[{}\begin{matrix}2x-1=3\\2x-1=-3\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-1\end{matrix}\right.\)