Question

[bảokhanh nguễn]

2.b)4√8-√18-6√1/2-√200 

3.a)(a√6/a+√2a/3+√6a):√6a  (a>0)

b)2/3a-1*√3a^2(9a^2-6a+1)  (1/3>a>0)

Answer 1

[Nguyễn Lê Phước Thịnh]

2b: \(=8\sqrt{2}-3\sqrt{2}-3\sqrt{2}-10\sqrt{2}=-8\sqrt{2}\)

3:

a: \(=\left(\sqrt{6a}+\dfrac{\sqrt{6a}}{3}+\sqrt{6a}\right):\sqrt{6a}\)

=1+1/3+1

=7/3

b: \(=\dfrac{2}{3a-1}\cdot\sqrt{3}\cdot a\cdot\left|3a-1\right|\)

\(=\dfrac{2\sqrt{3}\cdot a\left(1-3a\right)}{3a-1}=-2a\sqrt{3}\)