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a: \(=\dfrac{3^3\cdot2^6}{3^{-4}\cdot2^6}=3^7\)
b: \(=\left(\dfrac{3}{7}\cdot\dfrac{5}{3}\right)^6\cdot\dfrac{5}{3}\cdot\dfrac{3}{7}:\left(\dfrac{7^3}{5^4}\right)^{-2}\)
\(=\left(\dfrac{5}{7}\right)^6\cdot\dfrac{5}{7}\cdot\left(\dfrac{5}{7}\right)^6\cdot5^2\)
\(=\left(\dfrac{5}{7}\right)^{13}\cdot5^2\)
c: \(=5^4\cdot2.5^{-5}\cdot125\cdot0.04\)
\(=5^4\cdot5\cdot\left(\dfrac{5}{2}\right)^{-5}\)
\(=5^5\cdot\left(\dfrac{2}{5}\right)^5=2^5\)
15: Tính
a) Ta có: \(\frac{3^6\cdot45^4-15^{13}\cdot5^{-9}}{27^4\cdot25^3+45^6}\)
\(=\frac{3^6\cdot3^4\cdot15^4-15^{13}\cdot\frac{1}{5^9}}{9^4\cdot3^4\cdot5^6+9^6\cdot5^6}\)
\(=\frac{3^6\cdot45^4-\frac{5^{13}\cdot3^{13}}{5^9}}{9^4\cdot5^6\left(3^4+9^2\right)}\)
\(=\frac{45^4\cdot3^6-5^4\cdot3^{13}}{45^4\cdot5^2\cdot2\cdot9^2}\)
\(=\frac{5^4\cdot3^6\left(9^4-3^7\right)}{5^2\cdot3^4\cdot45^4\cdot2}\)
\(=\frac{5^2\cdot3^2\cdot\left(3^8-3^7\right)}{45^4\cdot2}\)
\(=\frac{5^2\cdot3^9\cdot\left(3-1\right)}{5^4\cdot3^8\cdot2}\)
\(=\frac{1}{5^2}\cdot3\)
\(=\frac{3}{25}\)
a: \(=\dfrac{3^3\cdot2^6}{3^{-4}\cdot2^6}=3^7\)
b: \(=\left(\dfrac{3}{7}\right)^5\cdot\left(\dfrac{3}{7}\right)\cdot\dfrac{5^6}{3^6}:\left(\dfrac{625}{343}\right)^2\)
\(=\dfrac{3^6}{7^6}\cdot\dfrac{5^6}{3^6}:\dfrac{5^8}{7^6}\)
\(=\dfrac{1}{5^2}\)
c: \(=5^{4+3}\cdot\left(\dfrac{5}{2}\right)^{-5}\cdot\dfrac{1}{25}\)
\(=5^5\cdot\left(\dfrac{2}{5}\right)^5=2^5\)
chuyển vế bình hết lên ko thì xset 2 th mỗi th chắc dài lê thê nên ngại làm
nè mình giúp được ko
bài 2:\(\frac{1}{x}+\frac{1}{y}+\frac{2}{xy}=1\)
\(\frac{1}{x}+\frac{1}{y}+\frac{1}{x}+\frac{1}{y}=1\)
\(\left(\frac{1}{x}+\frac{1}{x}\right)+\left(\frac{1}{y}+\frac{1}{y}\right)=1\)
\(\left(\frac{2}{x}\right)+\left(\frac{2}{y}\right)=1\)
\(\frac{4}{xy}=1\)
\(xy=4:1\)
xy = 4
làm mò chưa chắc chắn
a) ta có: \(\frac{x+13}{2006}+\frac{x+2006}{13}+\frac{x+1}{2018}+3=0\)
\(\Rightarrow\frac{x+13}{2006}+1+\frac{x+2006}{13}+1+\frac{x+1}{2018}+1=0\)
\(\Rightarrow\frac{x+2019}{2006}+\frac{x+2019}{13}+\frac{x+2019}{2018}=0\)
\(\Rightarrow\left(x+2019\right)\left(\frac{1}{2006}+\frac{1}{13}+\frac{1}{2018}\right)=0\)
mà \(\frac{1}{2006}+\frac{1}{13}+\frac{1}{2018}>0\)
\(\Rightarrow x+2019=0\)
\(\Rightarrow x=-2019\)
b) \(\frac{4}{\left(x+3\right)\left(x+7\right)}+\frac{3}{\left(x+7\right)\left(x+10\right)}=\frac{x}{\left(x+3\right)\left(x+10\right)}\)
\(\Rightarrow\frac{\left(x+7\right)-\left(x+3\right)}{\left(x+3\right)\left(x+7\right)}+\frac{\left(x+10\right)-\left(x+7\right)}{\left(x+7\right)\left(x+10\right)}=\frac{x}{\left(x+3\right)\left(x+10\right)}\)
\(\Rightarrow\frac{1}{x+3}-\frac{1}{x+7}+\frac{1}{x+7}-\frac{1}{x+10}=\frac{x}{\left(x+3\right)\left(x+10\right)}\)
\(\Rightarrow\frac{1}{x+3}-\frac{1}{x+10}=\frac{x}{\left(x+3\right)\left(x+10\right)}\)
\(\Rightarrow\frac{7}{\left(x+3\right)\left(x+10\right)}=\frac{x}{\left(x+3\right)\left(x+10\right)}\)
\(\Rightarrow x=7\)
làm bừa thui,ai tích mình mình tích lại
Số số hạng là :
Có số cặp là :
50 : 2 = 25 ( cặp )
Mỗi cặp có giá trị là :
99 - 97 = 2
Tổng dãy trên là :
25 x 2 = 50
Đáp số : 50
a)\(12^3.3^{-4}.64\)
\(=3^3.2^6.3^{-3}.2^6=2^{12}\)
b) \(\left(\frac{3}{7}\right)^5.\left(\frac{7}{3}\right)^{-1}.\left(\frac{5}{3}\right)^6:\left(\frac{343}{625}\right)^2\)
\(=\frac{3^5.7^{-1}}{7^5.3^{-1}}.\left(\frac{5}{3}\right)^6:\frac{7^6}{5^8}\)
\(=\frac{3^6}{7^6.}.\frac{5^6}{3^6}.\frac{5^8}{7^6}\)
\(=\frac{5^{14}}{7^{12}}\)