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a)\(\frac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}=\frac{\left(2^2\right)^5.\left(3^2\right)^4-2.\left(2.3\right)^9}{2^{10}.3^8+\left(3.2\right)^8.2^2.5}=\frac{2^{10}.3^8-2.2^9.3^9}{2^{10}.3^8+3^8.2^8.2^2.5}=\frac{2^{10}.3^8-2^{10}.3^9}{2^{10}.3^8+3^8.2^{10}.5}\)
\(=\frac{2^{10}.3^8.\left(1-3\right)}{2^{10}.3^8.\left(1+5\right)}=\frac{-2}{6}=\frac{-1}{3}\)
b) đặt A=2100 - 299 + 298 - 297 +...+ 22 - 2
=>2A=2101-2100+299-298+...+23-22
=>2A+A=2101-2100+299-298+...+23-22+2100 - 299 + 298 - 297 +...+ 22 - 2
=>3A=2101-2
=>A=\(\frac{2^{101}-2}{3}\)
\(\text{Theo đề ta có :}\)
\(\frac{\left(-1\right)^6\cdot3^5\cdot4^3}{9^2\cdot2^5}\)
= \(\frac{1\cdot3^5\cdot\left(2^2\right)^3}{\left(3^2\right)^2\cdot2^5}\) = \(\frac{3^5\cdot2^6}{3^4\cdot2^5}=\frac{3^4\cdot3\cdot2^5\cdot2}{3^4\cdot2^5}=3\cdot2=6\)
\(\frac{5\cdot2^{13}\cdot4^{11}-16^9}{\left(3\cdot2^{17}\right)^2}\)
\(\frac{5\cdot2^{13}\cdot\left(2^2\right)^{11}-\left(2^4\right)^9}{3^2\cdot2^{17\cdot2}}\)
\(\frac{5\cdot2^{13}\cdot2^{22}-2^{36}}{9\cdot2^{34}}\)
\(\frac{5\cdot2^{35}-2^{35}\cdot2}{9\cdot2^{34}}\)
\(\frac{\left(5-2\right)2\cdot2^{34}}{3\cdot3\cdot2^{34}}\)
\(\frac{3\cdot2}{3\cdot3}\)
\(\frac{2}{3}\)
\(\frac{2^7.9^3}{6^5.8^2}=\frac{2^7.\left(3^2\right)^3}{2^5.3^5.\left(2^3\right)^2}=\frac{2^7.3^6}{2^{11}.3^5}=\frac{3}{2^4}=\frac{3}{16}\)