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\(2\times5\times\dfrac{11}{3}\times11\times5=\left(2\times5\times5\right)\times\left(\dfrac{11}{3}\times11\right)=50\times\dfrac{121}{3}=\dfrac{6050}{3}\)
2 x 5 x 11/3 x 11 x 5
= 10 x 11/3 x 11 x 5
= ( 10 x 5 ) x( 11/3 x 11)
= 50 x 121/3
= 6050/3
\(\left(\dfrac{2}{7}+\dfrac{5}{7}\right)+\left(\dfrac{3}{5}+\dfrac{2}{5}\right)+\left(\dfrac{3}{8}+\dfrac{4}{8}+\dfrac{1}{8}\right)+\left(\dfrac{1}{9}+\dfrac{8}{9}\right)=1+1+1+1=4\)
`2/5 xx 4/7 + 3/5 xx 4/7`
`= 4/7 xx (2/5 + 3/5)`
`= 4/7 xx 1`
`= 4/7`
\(\dfrac{4}{7}x\left(\dfrac{2}{5}+\dfrac{3}{5}\right)=\dfrac{4}{7}x1=\dfrac{4}{7}\)
\(\dfrac{1}{7}+\dfrac{2}{7}+\dfrac{3}{7}+\dfrac{4}{7}+\dfrac{5}{7}+\dfrac{6}{7}\)
\(=\dfrac{1+2+3+4+5+6}{7}=3\)
\(\dfrac{1}{7}+\dfrac{2}{7}+\dfrac{3}{7}+\dfrac{4}{7}+\dfrac{5}{7}+\dfrac{6}{7}\)
\(=\left(\dfrac{1}{7}+\dfrac{6}{7}\right)+\left(\dfrac{2}{7}+\dfrac{5}{7}\right)+\left(\dfrac{3}{7}+\dfrac{4}{7}\right)\)
\(=1+1+1\)
\(=3\)
1+2+3+...+9
=(1+9)+(2+8)+...+5
=10+10+...+5
=10.4+5
=45
HT
= 2/7+5/7+1/5+4/5
=7/7+5/5
=1+1
=2
= (2/7+5/7)+(1/5+4/5)
=1+1=2