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\(a,81^3=\left(9^2\right)^3=9^6\)
Vì \(9^{27}>9^6\) nên \(9^{27}>81^3\)
\(b,5^{14}=\left(5^2\right)^7=25^7\)
Vì \(25^7< 27^7\) nên \(5^{14}< 27^7\)
\(c,10^{30}=\left(10^3\right)^{10}=1000^{10}\)
\(2^{100}=\left(2^{10}\right)^{10}=1024^{10}\)
Vì \(1000^{10}< 1024^{10}\) nên \(10^{30}< 2^{100}\)
a) \(3^{29}\)< \(10^{20}\)
b) \(3^{11}\)< \(17^{14}\)
c) \(27^4\): \(9^3\). \(81^4\) > \(16^3\).\(32^4\)
\(8^{14}:\left(4^4.64^5\right)=2^{42}:\left(2^8.2^{30}\right)=2^{42}:\left(2^{8+30}\right)=2^{42}:2^{38}=2^{42-38}=2^4=16\)
\(\left(9^{10}.27^7\right):\left(81^7.3^{15}\right)=\left(3^{20}.3^{21}\right):\left(3^{28}.3^{15}\right)=\left(3^{20+21}\right)\left(3^{28+15}\right)\)
\(=3^{41}:3^{43}=3^{41-43}=3^{-2}=\frac{1}{9}\)
9^27=3^81 > 81^13 =3^52
5^14 =25^7 < 27^7
10^30>9^30=3^90 > 2^100 (chú ý 3^3>2^4)
2^300=8^100 < 3^200=9^100
8^5=2^15=2^6.2^9 < 2^6.3^6 (chú ý 2^3<3^2)
3^450=(3^3)^150=27^150 > 5^300=(5^2)^150=25^150
A=7.9+7.9.2.3+7.9.3.4/21.27+21.27.2.3+21.27.3.4
=7.9(1+2.3+3.4)/21.27(1+2.3+3.4)
=7.9/21.27
=7.9/7.9.3.3
=1/9
\(\left(3^3\right)^{14}:\left(3^4\right)^{10}=3^{42}:3^{40}=3^{42-40}=3^2=9\)
(33)14:(34)10=342:340=32=9