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a) 2x = 64
=> 2x = 26
=> x = 6
b) 5x = 7x
=> 7x - 5x = 0
=> 5x(2x - 1) = 0
=> \(\orbr{\begin{cases}5^x=0\\2^x-1=0\end{cases}}\)\(\Rightarrow\orbr{\begin{cases}x\in\varnothing\\2^x=1\end{cases}}\)\(\Rightarrow2^x=2^0\Rightarrow x=0\)
c) 5x . 53 = 125
=> 5x + 3 = 53
=> x + 3 = 3
=> x = 0
d) 3x - 17 = 64
=> 3x = 64 + 17
=> 3x = 81
=> 3x = 34
=> x = 4
e) (3x - 5)3 = 52 . 24 + 600
=> (3x - 5)3 = 25.16 + 600
=> (3x - 5)3 = 400+ 600
=> (3x - 5)3 = 1000
=> (3x - 5)3 = 103
=> 3x - 5 = 10
=> 3x = 15
=> x = 15 : 3
=> x = 5
g) (5x - 15)3 = (5x - 15)7
=> (5x - 15)7 - (5x - 15)3 = 0
=> (5x - 15)3. [(5x - 15)4 - 1] = 0
=> \(\orbr{\begin{cases}\left(5x-15\right)^3=0\\\left(5x-15\right)^4-1=0\end{cases}\Rightarrow\orbr{\begin{cases}\left(5x-15\right)=0\\\left(5x-15\right)^4=1\end{cases}\Rightarrow}\orbr{\begin{cases}5x-15=0\\5x-15=\pm1\end{cases}}}\)
Nếu 5x - 15 =0
=> 5x = 15
=> x = 3
Nếu 5x - 15 = 1
=> 5x = 16
=> x = 16 : 5
=> x = 16/5
Nếu 5x - 16 = -1
=> 5x = 14
=> x = 14 : 5
=> x = 14/5
Vậy \(x\in\left\{3;\frac{16}{5};\frac{14}{5}\right\}\)
a) 2x = 64
Vì 26 = 64 nên x = 6
Vậy x = 6
b) 5x = 7x
Vì 50 = 1 và 70 = 1
=> x = 0
Vậy, x = 0
c) 5x . 53 = 625
Ta có 625 = 54
nên 5x . 53 = 54
5x+3 = 54
=> x = 1
Vậy x = 1
d) 3x - 17 = 64
3x = 64 + 17 = 81 = 34
=> x = 4
Vậy x = 4
e) ( 3x - 5 ) 3 = 52 . 24 + 600
( 3x - 5 ) 3 = 25 . 16 + 600 = 1000 = 103
=> 3x - 5 = 10
3x = 10 + 5 = 15
x = 15 : 3 = 5
Vậy x = 5
g) ( 5x - 15 ) 3 = ( 5x - 15 ) 7
=> (5x - 15 ) 3 : ( 5x - 15 ) 7 = 1
( 5x - 15 ) 3 - 7 = 1
( 5x - 15 ) -4 = 1 = 1-4 = -1-4
=> 5x - 15 = 1 hoặc 5x - 15 = -1
5x = 1 + 15 hoặc 5x = -1 + 15
5x = 16 hoặc 5x = 14
\(x=\frac{16}{5}\) hoặc \(x=\frac{14}{5}\)
Vậy, \(x\in\left\{\frac{16}{5};\frac{14}{5}\right\}\)
Cbht

a)(x-1)5=(-32)=(-2)5
=>x-1=-2
x=-2+1
x=-1
b)(23/4)*2x+1=64
(8/4)*2x+1=64
2*2x+1=64
2x+1+1=26
=>x+2=6
x=6-2
x=4

a) \(125^7:25^4=\left(5^3\right)^7:\left(5^2\right)^4=5^{21}:5^8=5^{13}\)
b) \(27^8:9^5=\left(3^3\right)^8:\left(3^2\right)^5=3^{24}:3^{10}=3^{14}\)
c) \(4^{20}:2^{30}=\left(2^2\right)^{20}:2^{30}=2^{40}:2^{30}=2^{10}\)
d) \(28^n:2^n=28^n:4^n=7^n\)
e) \(64^5.16^6:4^{20}=2^{30}.2^{24}:2^{10}=2^{54}:2^{40}=2^{14}\)
f) \(32^4:8^6=2^{20}:2^{18}=2^2\)
\(a.125^7:25^4=5^{21}:5^8=5^{13}\)
\(b.27^8:9^5=3^{24}:3^{10}=3^{14}\)
\(c.4^{20}:2^{30}=2^{40}:2^{30}=2^{10}\)
\(d.28^n:2^{2n}=28^n:4^n=7n\)
\(\hept{\begin{cases}e.64^5.16^6:4^{20}=4^{15}.4^{12}:4^{20}=4^7\\f.32^4:8^6=2^{20}:2^{18}=2^2\end{cases}}\)

1)Đưa về lũy thừa cùng cơ số 2
82= \(\left(2^3\right)^2=2^6\) 323= \(\left(2^5\right)^3=2^{15}\) 644= \(\left(2^6\right)^4=2^{24}\) 43= \(\left(2^2\right)^{^3}=2^6\)
2)Đưa về lũy thừa cùng cơ số 3
93= \(\left(3^2\right)^3=3^6\) 274= \(\left(3^3\right)^4=3^{12}\) 95= \(\left(3^2\right)^5=3^{10}\) 816= \(\left(3^4\right)^6=3^{24}\)
3)Đưa về lũy thừa cùng cơ số 2
83:42= \(\left(2^3\right)^3:\left(2^2\right)^2=2^9:2^4=2^5\) 162:32= \(\left(2^4\right)^2:2^5=2^8:2^5=2^3\)
\(64^4:4^3=\left(2^6\right)^4:\left(2^2\right)^3=2^{24}:2^6=2^{18}\) 323:82= \(\left(2^5\right)^3:\left(2^3\right)^2=2^{15}:2^6=2^9\)

\(a,\left(x-2\right)^2=64\)
\(\Rightarrow x-2=\orbr{\begin{cases}8\\-8\end{cases}}\)
\(\Rightarrow x=\orbr{\begin{cases}10\\-6\end{cases}}\)
\(b,\left(5x-1\right)^3=64\)
\(\Rightarrow5x-1=4\)
\(\Rightarrow5x=5\Leftrightarrow x=1\)
\(c,3^x+3^{x+3}=270\)(đề sai)
\(d,4^{x+1}+4^{x+2}=336\)(đề sai)
\(e,S=1+3+3^2+...+3^{50}\)
\(\Rightarrow2S=3^{51}-1\)
\(\Rightarrow S=\frac{3^{51}-1}{2}\)
a) \(\left(x-2\right)^2=64\)
\(\Rightarrow\orbr{\begin{cases}\left(x-2\right)^2=8^2\\\left(x-2\right)^2=\left(-8\right)^2\end{cases}}\Rightarrow\orbr{\begin{cases}x-2=8\\x-2=-8\end{cases}}\Rightarrow\orbr{\begin{cases}x=10\\x=-6\end{cases}}\)
Vậy x = 10 hoặc x = -6
b) \(\left(5x-1\right)^3=64\)
\(\Rightarrow\left(5x-1\right)^3=4^3\)
\(\Rightarrow5x-1=4\)
\(\Rightarrow5x=4+1\)
\(\Rightarrow5x=5\)
\(\Rightarrow x=5:5\)
\(\Rightarrow x=1\)
Vậy x = 1
c) \(3^x+3^{x+3}=270\)
\(\Rightarrow3^x+3^x\times3^3=270\)
\(\Rightarrow3^x\times\left(1+3^3\right)=270\)
\(\Rightarrow3^x\times28=270\)
\(\Rightarrow3^x=270:28\)
\(\Rightarrow3^x=\frac{135}{14}\)
\(\Rightarrow\)Không có giá trị x thỏa mãn
Vậy không có giá trị x thỏa mãn
d) \(S=1+3+3^2+...+3^{50}\)
\(\Rightarrow3S=3+3^2+3^3+...+3^{51}\)
\(\Rightarrow3S-S=\left(3+3^2+3^3+...+3^{51}\right)-\left(1+3+3^2+...+3^{50}\right)\)
\(\Rightarrow2S=3^{51}-1\)
\(\Rightarrow S=\frac{3^{51}-1}{2}\)
Vậy \(S=\frac{3^{51}-1}{2}\)
_Chúc bạn học tốt_

ko ghi lại đề nha
a ) x - 2 = 12
x = 14
b ) 5x + x = 39-311 : 39
6x = 39 - 32
6x = 39 - 9
6x= 30
x = 5
c ) 3x = 9
x = 2 ( vì 32 = 9 )
d ) 4x = 64
x = 64/4 = 16
e ) 2x = 16
x = 4 ( vì 24 = 16 )
f ) 9x-1 = 9
x - 1 = 1 ( vì 91 = 9 )
x = 2
g ) x4 = 16
x = 2
h ) 2x : 25 = 1
2x-5 = 1
x - 5 = 0 ( vì bất cứ số nào luỹ thừa 0 cũng bằng 1 )
x = 5
2(5x-4)+32=64
=> 2(5x-4)=64-32
=> 2(5x-4)=32
=> 5x-4=32:2
=> 5x-4=16
=> 5x=16+4
=> 5x=20
=> x=20:5
=> x=4
kho he