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\(a)x=\dfrac{1}{4}+\dfrac{5}{13}=\dfrac{33}{52}.\\ b)\dfrac{x}{3}=\dfrac{2}{3}+\dfrac{-1}{7}.\\ \Leftrightarrow\dfrac{x}{3}=\dfrac{11}{21}.\\ \Leftrightarrow\dfrac{7x}{21}=\dfrac{11}{21}.\\ \Rightarrow7x=11.\\ \Leftrightarrow x=\dfrac{11}{7}.\\ c)\dfrac{x}{3}=\dfrac{16}{24}+\dfrac{24}{36}=\dfrac{2}{3}+\dfrac{2}{3}=\dfrac{4}{3}.\\ \Rightarrow x=4.\\ d)\dfrac{x}{15}=\dfrac{1}{5}+\dfrac{2}{3}=\dfrac{13}{15}.\\ \Rightarrow x=13.\)
a)15/8+3/4-5/12
=45+18-10/24
=53/24
b)11/24.12/33+5/6
=11.12/12.2.11.3+5/6
=1/6+5/6
=6/6=1
c)15/8+7/24:5/8
=15/8+7/24.8/5
=15/8+7.8/3.8.5
=15/8+7/15
=đề sai, nếu đúng thì như này
=8/15+7/15
=15/15=1
a) 47 – x + 15 = 21 ⇔ 47 – x − 15 = 21 ⇔ 47 − x = 21 + 15 ⇔ 7 − x = 36 ⇔ − x = 47 − 36 ⇔ − x = 11 ⇔ x = − 11.
b) – 5 – 24 – x = – 11 ⇔ − 5 − 24 + x = − 11 ⇔ − 29 + x = − 11 ⇔ x = − 11 + 29 ⇔ x = 18.
c) 11 + 15 – x = 1 ⇔ 15 − x = 1 − 11 ⇔ 15 − x = − 10 ⇔ 15 + 10 = x ⇔ x = 25.
Bui Bao Ngoc oi! phan a,la (x+1)/10 hay x+(1/10)?
cac phan khac nua!
Bài 2:
a: \(\Leftrightarrow x-1\in\left\{1;-1;2;-2;3;-3;6;-6\right\}\)
=>\(x\in\left\{2;0;3;-1;4;-2;7;-5\right\}\)
b: \(\Leftrightarrow x+3\in\left\{1;-1;3;-3;5;-5;15;-15\right\}\)
=>\(x\in\left\{-2;-4;0;-6;2;-8;12;-18\right\}\)
c: \(\Leftrightarrow x+3\in\left\{1;-1;2;-2;3;-3;4;-4;6;-6;12;-12\right\}\)
=>\(x\in\left\{-2;-4;-1;-5;0;-6;1;-7;3;-9;9;-15\right\}\)
d: =>x+1+15 chia hết cho x+1
=>\(x+1\in\left\{1;-1;3;-3;5;-5;15;-15\right\}\)
=>\(x\in\left\{0;-2;2;-4;4;-6;14;-16\right\}\)
\(24+x=30\Rightarrow x=6\)
\(15+x=20\)
\(\Rightarrow x=5\)
\(12+1=14-x\)
\(\Rightarrow13=14-x\Rightarrow x=1\)
24 + x =30=>x=30-24=6
15 + x = 20=>x=20-15=5
12 + 1 = 14 - x=>=13=14-x
=>x=14-13
=>x=1
Từ giả thiết \(\Rightarrow\left\{{}\begin{matrix}x\inƯ\left(24\right)=\left\{1;2;3;4;6;8;12;24\right\}\\x+1\inƯ\left(15\right)=\left\{1;3;5;15\right\}\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x\in\left\{1;2;3;4;6;8;12;24\right\}\\x\in\left\{0;2;4;14\right\}\end{matrix}\right.\)
Vậy \(x\in\left\{2;4\right\}\)