Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
( 2,4 x - 36) : \(1\dfrac{5}{7}\) = -14
( \(\dfrac{12}{5}\) x - 36) : \(\dfrac{12}{7}\) = -14
( \(\dfrac{12}{5}\) x -36 ) = -14 . \(\dfrac{12}{7}\)
\(\dfrac{12}{5}\) x -36 = -24
\(\dfrac{12}{5}\) x = -24 + 36
\(\dfrac{12}{5}\) x = 12
x = 12 : \(\dfrac{12}{5}\)
x = 5
sorry bạn chữ hơi bị đẹp mong bạn bỏ qua giùm mk nghĩa là đúng
`1/7+(-9/27)+10/7+(-4/7)`
`= (1/7 + (-4)/7+10/7) +(-9/27)`
`= 7/7 +(-9/27)`
`= 1 +(-9/27)`
`= 27/27 + (-9/27)`
`=18/27`
`=2/3`
__
`1,3 xx2 1/4 -1,3 xx3 1/4`
`= 1,3 xx 9/4 -1,3 xx 13/4`
`=1,3 xx (9/4-13/4)`
`=1,3xx(-4)/4`
`=1,3 xx (-1)`
`=-1,3`
__
`1/4: x = 2,4 -4/5`
`=> 1/4 : x= 12/5 -4/5`
`=> 1/4 : x=8/5`
`=> x=1/4 : 8/5`
`=> x= 1/4 xx 5/8`
`=> x= 5/32`
__
`5/4 ( x- 3/5)= -1/8`
`=> x-3/5 = -1/8 : 5/4`
`=> x-3/5 = -1/8 xx 4/5`
`=> x-3/5 =-4/40`
`=> x-3/5 =-1/10`
`=> x=-1/10 +3/5`
`=> x=-1/10 + 6/10`
`=> x= 5/10`
`=>x=1/2`
` @ yngoc`
\(B=\frac{36}{1.3.5}+\frac{36}{3.5.7}+\frac{36}{5.7.9}+...+\frac{36}{25.27.29}\)
\(=9.\left(\frac{4}{1.3.5}+\frac{4}{3.5.7}+\frac{4}{5.7.9}+...+\frac{4}{25.27.29}\right)\)
\(=9.\left(\frac{1}{1.3}-\frac{1}{3.5}+\frac{1}{3.5}-\frac{1}{5.7}+\frac{1}{5.7}-\frac{1}{7.9}+...+\frac{1}{25.27}-\frac{1}{27.29}\right)\)
\(=9.\left(\frac{1}{3}-\frac{1}{675}\right)\)
\(=9.\frac{224}{675}\)
\(=\frac{224}{75}\)
a)\(\frac{5}{6}-x=-\frac{7}{12}+\frac{2}{3}\)
\(\frac{5}{6}-x=\frac{1}{12}\)
\(x=\frac{5}{6}-\frac{1}{12}\)
\(\Rightarrow x=\frac{3}{4}\)
b)\(\left(2,4x-36\right):1\frac{5}{7}=-14\)
\(\left(2,4x-36\right)=-24\)
\(2,4x=12\)
\(\Rightarrow x=5\)
c)\(\left(3\frac{1}{2}+2x\right).3\frac{2}{3}=5\frac{1}{3}\)
\(3\frac{1}{2}+2x=\frac{16}{11}\)
\(2x=-\frac{45}{22}\)
\(x=-\frac{45}{44}\)
d)\(\frac{5}{6}-\left|\frac{1}{2}x-\frac{1}{3}\right|=\frac{3}{8}\)
\(\left|\frac{1}{2}x-\frac{1}{3}\right|=\frac{11}{24}\)
\(\Rightarrow\hept{\begin{cases}\frac{1}{2}x-\frac{1}{3}=\frac{11}{24}\\\frac{1}{2}x-\frac{1}{3}=-\frac{11}{24}\end{cases}}\Rightarrow\hept{\begin{cases}x=\frac{19}{12}\\x=-\frac{1}{4}\end{cases}}\)
e)\(\left|\frac{1}{4}-2x\right|-\frac{3}{4}=0\)
\(\left|\frac{1}{4}-2x\right|=\frac{3}{4}\)
\(\Rightarrow\hept{\begin{cases}\frac{1}{4}-2x=\frac{3}{4}\\\frac{1}{4}-2x=-\frac{3}{4}\end{cases}\Rightarrow}\hept{\begin{cases}x=-\frac{1}{4}\\x=\frac{1}{2}\end{cases}}\)
\(a,5,2x+7\dfrac{2}{5}=6\dfrac{3}{4}\\ \Rightarrow\dfrac{26}{5}x+\dfrac{37}{5}=\dfrac{27}{4}\\ \Rightarrow\dfrac{26}{5}x=-\dfrac{13}{20}\\ \Rightarrow x=-\dfrac{1}{8}\\ b,2,4:\left(\dfrac{-1}{2}-x\right)=1\dfrac{3}{5}\\ \Rightarrow\dfrac{12}{5}:\left(\dfrac{-1}{2}-x\right)=\dfrac{8}{5}\\ \Rightarrow\dfrac{-1}{2}-x=\dfrac{3}{2}\\ \Rightarrow x=-2\)