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a) x - 13+x = -24-7 + x
2x-13 = -31 +x
2x-x = -31+13
x = -18
b) 12.20 = 15x
240 = 15x
x = 16
c) 42(-5) = 14x
-210 = 14x
x = -15
mik ko chép lại đề, mik làm luôn:
a) x - \(\frac{31}{36}=\frac{-13}{38}\)
x = \(\frac{-13}{18}+\frac{31}{36}\)
\(x=\frac{5}{36}\)
b)\(2-x-\frac{3}{7}=\frac{9}{-21}\)
\(\frac{11}{7}-x=\frac{3}{7}\)
x = \(\frac{11}{7}-\frac{3}{7}\)
x = 8/7
c) x + 3/11 = 23/44
x = 23/44 - 3/11
x = 1/4
d) \(\frac{1}{12}-x=\frac{-11}{9}\)
x = \(\frac{1}{12}+\frac{11}{9}\)
x = 47/36
e) \(x-\frac{2}{3}=\frac{-17}{3}\)
x= -17/3 + 2/3
x = -5
f) \(x-\frac{1}{2}=\frac{11}{4}.\frac{3}{11}\)
x - 1/2 = 3/4
x = 3/4 + 1/2
x = 5/4
g) \(2x+\frac{3}{8}=\frac{-21}{32}.\frac{4}{7}\)
2x + 3/8 = -3 / 8
2x = -3/8 - 3/8
2x = -9/8
x = -9/8.1/2
x = -9/16
h) x - \(\frac{x}{3}=\frac{3}{57}.\frac{19}{12}\)
x - \(\frac{x}{3}=\frac{1}{12}\)
x = \(\frac{1}{12}+\frac{x}{3}\)
x = \(\frac{1+4x}{12}\)
=> 12x = 1+4x
12x - 4x = 1
8x = 1
x = 1/8
\(x.3\frac{1}{4}+\left(\frac{-7}{6}\right)x-1\frac{2}{3}=\frac{5}{12}\)
\(x.\frac{13}{4}+\left(\frac{-7}{6}\right)x-\frac{5}{3}=\frac{5}{12}\)
\(x\left[\frac{13}{4}+\left(\frac{-7}{6}\right)\right]-\frac{5}{3}=\frac{5}{12}\)
\(x\frac{25}{12}-\frac{5}{3}=\frac{5}{12}\)
\(x\frac{25}{12}=\frac{5}{12}+\frac{5}{3}\)
\(x\frac{25}{12}=\frac{25}{12}\)
\(x=\frac{25}{12}:\frac{25}{12}\)
\(x=1\)
a)\(\frac{5}{6}-x=-\frac{7}{12}+\frac{2}{3}\)
\(\frac{5}{6}-x=\frac{1}{12}\)
\(x=\frac{5}{6}-\frac{1}{12}\)
\(\Rightarrow x=\frac{3}{4}\)
b)\(\left(2,4x-36\right):1\frac{5}{7}=-14\)
\(\left(2,4x-36\right)=-24\)
\(2,4x=12\)
\(\Rightarrow x=5\)
c)\(\left(3\frac{1}{2}+2x\right).3\frac{2}{3}=5\frac{1}{3}\)
\(3\frac{1}{2}+2x=\frac{16}{11}\)
\(2x=-\frac{45}{22}\)
\(x=-\frac{45}{44}\)
d)\(\frac{5}{6}-\left|\frac{1}{2}x-\frac{1}{3}\right|=\frac{3}{8}\)
\(\left|\frac{1}{2}x-\frac{1}{3}\right|=\frac{11}{24}\)
\(\Rightarrow\hept{\begin{cases}\frac{1}{2}x-\frac{1}{3}=\frac{11}{24}\\\frac{1}{2}x-\frac{1}{3}=-\frac{11}{24}\end{cases}}\Rightarrow\hept{\begin{cases}x=\frac{19}{12}\\x=-\frac{1}{4}\end{cases}}\)
e)\(\left|\frac{1}{4}-2x\right|-\frac{3}{4}=0\)
\(\left|\frac{1}{4}-2x\right|=\frac{3}{4}\)
\(\Rightarrow\hept{\begin{cases}\frac{1}{4}-2x=\frac{3}{4}\\\frac{1}{4}-2x=-\frac{3}{4}\end{cases}\Rightarrow}\hept{\begin{cases}x=-\frac{1}{4}\\x=\frac{1}{2}\end{cases}}\)
\(a)x+30\%x=-1,31\)
\(\Leftrightarrow x+\frac{3x}{10}=-1,31\)
\(\Leftrightarrow10x+3x=-13,1\)
\(\Leftrightarrow13x=-13,1\Leftrightarrow x=-\frac{131}{130}\)
\(b)\left(x-\frac{1}{2}\right):\frac{1}{3}+\frac{5}{7}=9\frac{5}{7}\)
\(\Leftrightarrow\frac{2x-1}{2}.3+\frac{5}{7}=\frac{68}{7}\)
\(\Leftrightarrow\frac{6x-3}{2}=\frac{63}{7}\)
\(\Leftrightarrow\frac{6x-3}{2}=9\)
\(\Leftrightarrow6x-3=18\)
\(\Leftrightarrow x=\frac{7}{2}\)
a) x-1/3=5/14.(-7/6)
x-1/3=-5/12
x=-5/12+1/3
x= -1/12
b) 3/4+1/4x=0,2
1/4x=0,2-3/4
1/4x=-11/20
x=-11/20:1-4
x=-11/5
c) 1/12.x^2=1.1/2
1/12.x^2=1/2
x^2= 1/2:1/12
x^2=6
=> x=căn bậc của 6
Chúc bn hok tốt
a)\(x-\frac{1}{3}=\frac{5}{14}\cdot\left(\frac{-7}{6}\right)\)
\(x-\frac{1}{3}=\frac{-5}{12}\)
\(x=\frac{-5}{12}+\frac{1}{3}\)
\(x=\frac{-5}{12}+\frac{4}{12}\)
\(x=\frac{-1}{12}\)
b)\(\frac{3}{4}+\frac{1}{4}\cdot x=0,2\)
\(\frac{3}{4}+\frac{1}{4}\cdot x=\frac{1}{5}\)
\(\frac{1}{4}\cdot x=\frac{1}{5}-\frac{3}{4}\)
\(\frac{1}{4}\cdot x=\frac{4}{20}-\frac{15}{20}\)
\(\frac{1}{4}\cdot x=\frac{-11}{20}\)
\(x=\frac{-11}{20}\cdot4\)
\(x=-\frac{11}{5}\)
c)\(\frac{1}{12}\cdot x^2=1\cdot\frac{1}{3}\)
\(\frac{1}{12}\cdot x^2=\frac{1}{3}\)
\(x^2=\frac{1}{3}\cdot12\)
\(x^2=4=\left(\pm2\right)^2\)
\(x=\pm2\)
\(\left(2\times x-36\right)\div\frac{12}{7}=-14\)
\(2x-36=-14.\frac{12}{7}\)
\(2x-36=-24\)
\(2x=-24+36\)
\(2x=12\)
\(x=12\div2\)
\(x=6\)
Vậy, \(x=6\)