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Câu 2:
1: =>x-1=5 hoặc x-1=-5
=>x=-4 hoặc x=6
2: =>|x-2|=6,75-0,75=6
=>x-2=6 hoặc x-2=-6
=>x=-4 hoặc x=8
4: =>|x|=22,5
=>x=22,5 hoặc x=-22,5
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Trả lời:
\(B=\frac{0,75-30\%+\frac{3}{7}+\frac{3}{13}}{2,75-2,2+1\frac{4}{7}+3\frac{2}{3}}\)
\(B=\frac{\frac{3}{4}-\frac{3}{10}+\frac{3}{7}+\frac{3}{13}}{\frac{11}{4}-\frac{11}{5}+\frac{11}{7}+\frac{11}{3}}\)
\(B=\frac{2019}{1820}\div\frac{2431}{420}\)
\(B=\frac{2019}{1820}\times\frac{420}{2431}\)
\(B=\frac{6057}{31603}\)
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=43/306:599/105x1473/1820
=1505/61098x1473/1820
=0.01993613035
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\(P=\frac{0,75-0,6+\frac{3}{7}+\frac{3}{13}}{2,75-2,2+\frac{11}{7}+\frac{11}{13}}\)
\(\Rightarrow P=\frac{\frac{3}{4}-\frac{3}{5}+\frac{3}{7}+\frac{3}{13}}{\frac{11}{4}-\frac{11}{5}+\frac{11}{7}+\frac{11}{13}}\)
\(\Rightarrow P=\frac{3\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{7}+\frac{1}{13}\right)}{11\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{7}+\frac{1}{13}\right)}\)
\(\Rightarrow P=\frac{3}{11}\)
Vậy \(P=\frac{3}{11}\)
Bài 1:
\(P=\frac{0,75-0,6+\frac{3}{7}+\frac{3}{13}}{2,75-2,2+\frac{1}{7}+\frac{11}{13}}\)
\(=\frac{\frac{3}{4}-\frac{3}{5}+\frac{3}{7}+\frac{3}{13}}{\frac{11}{4}-\frac{11}{5}+\frac{11}{7}-\frac{11}{3}}\)
\(=\frac{3.\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{7}-\frac{1}{13}\right)}{11.\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{7}-\frac{1}{13}\right)}=\frac{3}{11}\)
Bài 2:
a) \(\left(x+1\right)\left(x-2\right)< 0\Leftrightarrow\orbr{\begin{cases}\left(x+1\right)=0\left(\text{loại}\right)\\\left(x-2\right)=0\end{cases}}\Rightarrow x=2\)
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\(\frac{2}{3}\left|x\right|-\frac{1}{2}=2,2\)
\(\frac{2}{3}\left|x\right|=\frac{11}{5}+\frac{1}{2}\)
\(\frac{2}{3}\left|x\right|=\frac{22}{10}+\frac{5}{10}\)
\(\frac{2}{3}\left|x\right|=\frac{27}{10}\)
\(\left|x\right|=\frac{27}{10}:\frac{2}{3}\)
\(\left|x\right|=\frac{81}{20}\)
\(\orbr{\begin{cases}x=\frac{81}{20}\\x=-\frac{81}{20}\end{cases}}\)
Vậy x= 81/20 hoặc x= -81/20