Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Ta có: 3x+2+4.3x+1=7.36
=> 3x + 1.(3 + 4) = 7.36
=> 3x + 1 . 7 = 7.36
=> 3x + 1 = 36
=> x + 1 = 6
=> x = 5
\(7\cdot3^{x-1}-3^{x+2}=-540\)
\(\Leftrightarrow3^x\left[7\cdot\left(-3\right)-3^2\right]=-540\)
\(\Leftrightarrow3^x\cdot\left(-30\right)=-540\)
\(\Leftrightarrow3^x=18\)
Ta có : \(7.3^{x-1}-3^{x+2}=-540\)
\(\Leftrightarrow\left(7-3^3\right).3^{x-1}=-540\)
\(\Leftrightarrow\left(7-27\right).3^{x-1}=-540\)
\(\Leftrightarrow-20.3^{x-1}=-540\)
\(\Leftrightarrow3^{x-1}=\left(-540\right):\left(-20\right)\)
\(\Leftrightarrow3^{x-1}=27\)
\(\Leftrightarrow3^{x-1}=3^3\Rightarrow x-1=3\Rightarrow x=4\)
Vậy \(x=4\)
\(7\times3^{x-1}-3^{x+2}=-540\)
\(7\times3^{x-1}-3^{x-1}\times3^3=-540\)
\(3^{x-1}\left(7-3^3\right)=-540\)
\(3^{x-1}\left(7-27\right)=-540\)
\(3^{x-1}\times\left(-20\right)=-540\)
\(3^{x-1}=\left(-540\right)\div\left(-20\right)\)
\(3^{x-1}=27\)
\(3^{x-1}=3^3\)
\(\Rightarrow x-1=3\)
\(x=4\)
Chúc bn học tốt
7.3x-1 - 3x+2 = -540
<=> 7.3x : 3 - 3x.32 = -540
<=> 3x.(7 : 3 - 32) = -540
<=> 3x = 81
<=> 3x = 34
<=> x = 4
\(3^{x+2}+4.3^{x+1}=7.3\)
\(\Leftrightarrow3^x\left(3^2+4.3\right)=21\)
\(\Leftrightarrow3^x.21=21\)
\(\Leftrightarrow3^x=1\Leftrightarrow x=0\)
Tìm x
X-1/5 = 2x+1/3
X+3/2x-5 = 2/3
2/3 . 3x+1 - 7 . 3x = -405
2x+3 . 5 + 2x+2 . 3 + 2x+1 . 24 = 200
\(5^{x+2}=625\)
\(5^x.5^2=625\)
\(5^x.5^2=5^3\)
\(5^x=5^1\)
\(\Rightarrow x=1\)
\(\dfrac{2}{3}\cdot3^{x+1}-7\cdot3^x=-405\)
\(\Rightarrow3^x\cdot\left(\dfrac{2}{3}\cdot3-7\right)=-405\)
\(\Rightarrow3^x\cdot\left(2-7\right)=-405\)
\(\Rightarrow3^x\cdot-5=-405\)
\(\Rightarrow3^x=-405:-5\)
\(\Rightarrow3^x=81\)
\(\Rightarrow3^x=3^4\)
\(\Rightarrow x=4\)
Vậy: \(x=4\)
\(\Leftrightarrow3\cdot\dfrac{2}{3}\cdot3^x-7\cdot3^x=-405\)
=>\(-5\cdot3^x=-405\)
=>3^x=81
=>x=4