Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(a.=\dfrac{2019}{2020}\times\left(\dfrac{4}{11}+\dfrac{5}{11}+\dfrac{2}{11}\right)\\ =\dfrac{2019}{2020}\times1=\dfrac{2019}{2020}\\ b.=\dfrac{25}{27}\times\left(\dfrac{17}{14}-\dfrac{1}{14}-\dfrac{2}{14}\right)\\ =\dfrac{25}{27}\times1=\dfrac{25}{27}\)
3, 54 x 73 + 0,23 x 25 + 3,54 x 27 + 0,17 x 25
= 3,54 x 73 + 3,54 x 27 + 0,23 x 25 + 0,17 x 25
= 3,54 x(73+27) + 25 x (0,23+0,17)
= 3,54 x 100 + 25 x 0,4
= 3,54 x 100 + 10
= 35,4 x 10 + 10
= 10 x (35,4+1)
= 10 x 36,4
= 364
22 x X + X x 27 + X = 25
22 x X + X x 27 + X x 1 = 25
X x ( 22 + 27 +1 ) = 25
X x 50 = 25
X = 25 : 50
X = \(\dfrac{1}{2}\) = 0,5
22 x X + X x 27 + X = 25
22 x X + X x 27 + X x 1 = 25
X x (22 + 27 + 1) = 25
X x 50 = 25
X = 25 : 50
X = 0,2
Chúc bạn học tốt!
`@` `\text {Ans}`
`\downarrow`
`22 \times x + 27 \times x + x = 25`
`x \times (22 + 27 + 1) = 25`
`x \times 50 = 25`
`x = 25 \div 50`
`x =`\(\dfrac{25}{50}=\dfrac{1}{2}\)
Vậy, \(x=\dfrac{1}{2}\)
\(22xX+27xX+X=25\\ \left(22+27+1\right)xX=25\\ 50xX=25\\ x=50:25=2.\)
Vậy \(X=2.\)
\(a,123\times54+27\times123-12\times123+123\times31\)
\(=123\times\left(54+27-12+31\right)\)
\(=123\times100\)
\(=12300\)
\(b,\dfrac{121}{27}\times\dfrac{54}{11}< n< \dfrac{100}{21}:\dfrac{25}{126}\)
\(22< n< \dfrac{100}{21}\times\dfrac{126}{25}\)
\(22< n< 24\)
Vì \(23>22\) và \(23< 24\) nên \(n=23\)
a123x54+27x123-12x123+123x31
=123:54+27:123-12:123+123:31
=6642+27:123-12:123+123:31
=6642+3321-12:123+123:31
=6642+3321-1476+123:31
=6642+3321-1476+3813
=12300
b,121/27x54/11<n>100/21:25/126
=22<n>24
n=23
\(22\times x+27\times x+x=25\)
\(x\times\left(22+27+1\right)=25\)
\(50x=25\)
\(x=\dfrac{25}{50}=\dfrac{1}{2}\)
\(x\)x50=25
\(x\) =25:50
\(x\) =0,5