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a, 27x 36 + 73 x 99 + 27 x 14 - 49 x 73
= 27 ( 36 + 14 ) + 73 ( 99 - 49 ) = 27 x 50 + 73 x 50
= 50 ( 27 + 73) = 50 x 100 = 5 000
b, 21 x (271 + 29 ) + 79 x ( 271 + 29)
= (271 + 29 ) ( 21 + 79)
= 300 x 100 = 30 000
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a)\(\frac{x}{5}=\frac{2}{5}\)
\(\Leftrightarrow x=\frac{2\times5}{5}=2\)
Vậy .............
b) \(\frac{3}{8}=\frac{6}{x}\)
\(\Leftrightarrow x=\frac{8\times6}{3}=16\)
Vậy ................
c) \(\frac{1}{9}=\frac{x}{27}\)
\(\Leftrightarrow x=\frac{1\times27}{9}=3\)
Vậy ................
d) \(\frac{4}{x}=\frac{8}{6}\)
\(\Leftrightarrow x=\frac{4\times6}{8}=3\)
Vậy ............
e) \(\frac{3}{x-5}=\frac{-4}{x+2}\)
\(\Leftrightarrow3\left(x+2\right)=-4\left(x-5\right)\)
\(\Leftrightarrow3x+6=-4x+20\)
\(\Leftrightarrow3x+4x=20-6\)
\(\Leftrightarrow7x=14\)
\(\Leftrightarrow x=2\)
Vậy .............
f) \(\frac{x}{-2}=\frac{-8}{x}\)
\(\Leftrightarrow x^2=16\)
\(\Leftrightarrow x=\pm4\)
Vậy ...............
\(\frac{x}{5}=\frac{2}{5}\Rightarrow x=\frac{2\times5}{5}=2\)
\(\frac{1}{9}=\frac{x}{27}\Rightarrow x=\frac{1\times27}{9}=3\)
\(\frac{4}{x}=\frac{8}{6}\Rightarrow x=\frac{8\times6}{8}=6\)
\(\frac{3}{x-5}=\frac{-4}{x+2}\)
\(\Rightarrow3.\left(x+2\right)=-4.\left(x-5\right)\)
\(\Rightarrow3x+6=-4x+20\)
\(\Rightarrow3x+4x=20-6\)
\(\Rightarrow7x=14\)
\(\Rightarrow x=2\)
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a/ => x3 = 64 => x3 = 43 => x = 4
b/ => x5 = 32 => x5 = 25 => x = 2
c/ => 3x = 81 => 3x = 34 => x = 4
d/ => 3x+2 = 243 => 3x+2 = 35 => x + 2 = 5 => x = 3
e/ => (x - 2)3 = 64 => (x - 2)3 = 43 => x - 2 = 4 => x = 6
f/ => (x - 8)2 = 81 => (x - 8)2 = 92 => x - 8 = 9 => x = 17
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a)\(\frac{x}{5}=\frac{-2}{5}\)
\(\Leftrightarrow x=-2\)
b)\(\frac{3}{8}=\frac{6}{x}\)
\(\Leftrightarrow3x=6.8\)
\(\Leftrightarrow3x=48\)
\(\Leftrightarrow x=16\)
c)\(\frac{1}{9}=\frac{-x}{27}\)
\(\Leftrightarrow-9x=27\)
\(\Leftrightarrow x=-3\)
d) \(\frac{x}{-2}=\frac{-8}{x}\)
\(\Leftrightarrow x^2=-2.\left(-8\right)\)
\(\Leftrightarrow x^2=16\)
\(\Leftrightarrow\orbr{\begin{cases}x=4\\x=-4\end{cases}}\)
#H
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a) \(\left(19x+2\cdot5^2\right)\div14=\left(13-8\right)^2-4^2\)
\(\left(19x+2\cdot25\right)\div14=5^2-16\)
\(\left(19x+50\right)\div14=25-16=9\)
\(19x+50=9\cdot14=126\)
\(19x=126-50=76\)
\(x=76\div19=4\)
b) \(2\cdot3^x=10\cdot3^{12}+8\cdot\left(3^3\right)^4\)
\(2\cdot3^x=\left(10+8\right)\cdot3^{12}\)
\(2\cdot3^x=18\cdot3^{12}\)
\(\Rightarrow2\cdot3^x=2\cdot3^2\cdot3^{12}\Rightarrow2\cdot3^x=2\cdot3^{15}\Rightarrow x=15\)
a, \left(19.x+2.5^2\right)\div14=\left(13-8\right)^2-4^2(19.x+2.52)÷14=(13−8)2−42
\left(19.x+2.25\right)\div14=5^2-4^2(19.x+2.25)÷14=52−42
\left(19.x+2.25\right)\div14=25-16(19.x+2.25)÷14=25−16
\left(19.x+50\right)\div14=9(19.x+50)÷14=9
\left(19.x+50\right)=9.14(19.x+50)=9.14
19.x+50=12619.x+50=126
19.x=126-5019.x=126−50
19.x=7619.x=76
\Rightarrow x=76\div19⇒x=76÷19
\Rightarrow x=4⇒x=4
Vậy x = 4
b, 2.3^x=10.3^{12}+8.27^42.3x=10.312+8.274
2.3^x=10.3^{12}+8.\left(3^3\right)^42.3x=10.312+8.(33)4
2.3^x=10.3^{12}+8.3^{12}2.3x=10.312+8.312
2.3^x=\left(10+8\right).3^{12}2.3x=(10+8).312
2.3^x=18.3^{12}2.3x=18.312
2.3^x=2.3^3.3^{12}2.3x=2.33.312
2.3^x=2.3^{15}2.3x=2.315
\Rightarrow x=15⇒x=15
Vậy x = 15
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