![](https://rs.olm.vn/images/avt/0.png?1311)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
1.4./x-5/-54=-34
4./x-5/=-34+54
4./x-5/=20
/x-5/=20:4
/x-5/=5
=>x-5=5 va x-5=-5
TH1:x-5=-5
=>x=0
TH2:x-5=5
=>x=10
2. /x-1/+(-5)=2
/x-1/=2-(-5)
/x-1/=7
=>x-1=7 va x-1=-7
TH1: x-1=7
=>x=8
TH2:x-1=-7
=>x=-6
vay x=-6 hoac x=8
![](https://rs.olm.vn/images/avt/0.png?1311)
\(2^2.3-\left(10^6+8\right):3^2\)
\(=4.3-\left(1000000+8\right):9\)
\(=12-1000008:9\)
\(=12-111112\)
\(=-111100\)
![](https://rs.olm.vn/images/avt/0.png?1311)
1.
a)8102-2102
= 82 .8100 - 22. 2100
=64.(84)25-4.(24)25
=64 . ...625 - 4 . ...625
=....4 - ...4
.=...0 chia hết cho 10
b)34n+1+2
=(34)n+1 + 2
= ....1 + 2
=....3 chia hết cho 3
2.
a)C = 2.1+2.3+...+2.32004
C = 2.(1+3+...+32004)
đặt D=1+3+..+32004
3D=3+ .....+32005
3D - D=32005 - 3
2D=32005-1
2D= (34)501.3 - 1
2D = 81501 .3 - 1
D= (...1 . 3- 1):2
D = (...3 - 1) :2
D= ...2 : 2
D=....1
b)B= 1+ 3+...+3300
3B= 3+...+3101
2D = 3101 - 1
D= (3101 - 1):2
D=(3100.3-1):2
D=[(34)25. 3 -1]:2
D= [...125.3-1]:2
D= [...3-1]:2
D=...2:2
D=....1
![](https://rs.olm.vn/images/avt/0.png?1311)
a ta co ;
13 -12 +11+10-9+8-7-6+5-4+3+2-1
=13-(12-11-10+9) +(8-7-6+5) -(4-3-2+1)
= 13 -0+0 -0
=13
![](https://rs.olm.vn/images/avt/0.png?1311)
1. 25 : 5,7 = 250/57
2. 30:2.8.4 = 480
3. 20:2^2.14= 70
4. 125:5^3.170= 170
5. 64:2^5.30.4=240
6. (25:5^2.30): 15.7=14
bạn à! Nhiều quá mình ko làm hết được. sorry nha.^-^
![](https://rs.olm.vn/images/avt/0.png?1311)
\(2.3^x=10.3^{12}+8.27^4\)
\(\Rightarrow2.3^x=10.3^{12}+8.3^{12}\)
\(\Rightarrow2.3^x=3^{12}\left(10+8\right)=3^{12}.18\)
\(\Rightarrow3^x=3^{12}.18:2=3^{12}.3^2=3^{15}\)
\(\Rightarrow x=15\)
2.3^x=10.3^12+8.(3^3)^4
2.3^x=10.3^12+8.3^12
2.3^x=3^12.(10+8)
2.3^x=3^12.18
2.3^x=3^12.9.2
2.3^x=3^14.2
vậy x =14
![](https://rs.olm.vn/images/avt/0.png?1311)
1) (-10)-|5-x|=(-12)
|5-x|=(-10)-(-12)
|5-x|=2
\(\Rightarrow\left[{}\begin{matrix}5-x=2\\5-x=\left(-2\right)\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=7\end{matrix}\right.\)
Vậy:............
\(2^2.3-\left(1^{10}+8\right):3^2\)
\(=4.3-\left(1+8\right):9\)
\(=12-9:9\)
\(=12-1\)
\(=11\)
cảm ơn tôi có hỏi thêm 12 câu đươc ko