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23 x 67 + 63 x 67 + 67 x 14 + 100 x 33
= 67 x (23+63+14) +100 x 33
= 67 x 100 + 100 x 33
= 100 x (67+33)
= 100 x 100
= 10000
tk cho mình nha!
= ( 23 + 63 + 14 ) x 67 + 100 x 33
= 100 x 67 + 100 x 33
= 100 x ( 67 + 33 )
= 100 x 100
= 10 000
Đó chính là đáp án nha bạn. Hok tốt
a) Ta có: \(x+\left(-5\right)=-\left(-7\right)\)
\(\Leftrightarrow x-5=7\)
\(\Leftrightarrow x=7+5=12\)
Vậy: x=12
b) Ta có: \(-5\cdot\left|x\right|=-30\)
\(\Leftrightarrow\left|x\right|=-30:\left(-5\right)=6\)
hay \(x\in\left\{6;-6\right\}\)
Vậy: \(x\in\left\{6;-6\right\}\)
c) Ta có: \(2x+20=-22\)
\(\Leftrightarrow2x=-22-20=-42\)
hay x=-21
Vậy: x=-21
d) Ta có: \(\left|x+2\right|=4\)
\(\Leftrightarrow\left[{}\begin{matrix}x+2=4\\x+2=-4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-6\end{matrix}\right.\)
Vậy: \(x\in\left\{2;-6\right\}\)
a, \(6.x.5.\left(x-2\right)=23\)
\(\Leftrightarrow30x.\left(x-2\right)=23\)
\(\Leftrightarrow\orbr{\begin{cases}30x=1\\x-20=23\end{cases}\Leftrightarrow\orbr{\begin{cases}x=\frac{1}{30}\\x=43\end{cases}}\left(1\right)}\)
\(\Leftrightarrow\orbr{\begin{cases}30x=23\\x-20=1\end{cases}\Leftrightarrow\orbr{\begin{cases}x=\frac{23}{30}\\x=21\end{cases}\left(2\right)}}\)
\(\Leftrightarrow\orbr{\begin{cases}30x=-1\\x-20=-23\end{cases}\Leftrightarrow\orbr{\begin{cases}x=-\frac{1}{30}\\x=-3\end{cases}}\left(3\right)}\)
\(\Leftrightarrow\orbr{\begin{cases}30x=-23\\x-20=-1\end{cases}\Leftrightarrow\orbr{\begin{cases}x=-\frac{23}{30}\\x=19\end{cases}}}\)
b, \(42-\left(2x+32\right)+12:2=6\)
\(\Leftrightarrow42-\left(2x+32\right)+6=6\)
\(\Leftrightarrow42-\left(2x+32\right)=0\)
\(\Leftrightarrow2x-32=42\)
\(\Leftrightarrow2x=74\)
\(\Leftrightarrow x=37\)
\(A=47.36+64.47+15\)
\(A=47.\left(36+64\right)+15\)
\(A=47.100+15\)
\(A=4700+15\)
\(A=4715\)
\(B=27+35+65+73+75\)
\(B=\left(27+73\right)+\left(35+65\right)+75\)
\(B=100+100+75\)
\(B=275\)
\(C=37+37.15+84.37\)
\(C=37.\left(1+15+84\right)\)
\(C=37.100\)
\(C=3700\)
\(D=\frac{1}{20.21}+\frac{1}{21.22}+\frac{1}{22.23}+\frac{1}{23.24}\)
\(D=\frac{1}{20}-\frac{1}{21}+\frac{1}{21}-\frac{1}{22}+\frac{1}{22}-\frac{1}{23}+\frac{1}{23}-\frac{1}{24}\)
\(D=\frac{1}{20}-\frac{1}{24}\)
\(D=\frac{24}{480}-\frac{20}{480}\)
\(D=\frac{4}{480}=\frac{1}{120}\)
\(E=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{49.50}\)
\(E=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{49}-\frac{1}{50}\)
\(E=1-\frac{1}{50}\)
\(E=\frac{49}{50}\)
\(\frac{11.3^{29}-\left(3.3\right)^{15}}{2^2.3^{28}}\)=\(\frac{11.3^{29}-3^{30}}{2^2.3^{28}}=\frac{3^{29}.\left(11-3\right)}{3^{28}.2^2}=\frac{3.8}{2^2}=3.2\)=6
-22< -21;-20;....;22<23
-36<-35;-34;...;33<34
-22<x<23=>x=(-21;-22...........22)
-36<x<34=>x=(-35;-34.........33)
rồi đó nhá