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Tính :
1-2+3-4+5-6+...+201-202
=(1-2)+(3-4)+(5-6)+...+(201-202) (có 101 cặp)
=(-1)+(-1)+(-1)+...+(-1)
=(-1).101=-101.
Tìm x là số nguyên :
30-(x+1)=-17
x+1=30-(-17)
x+1=47
x=47-1
x=46
Vậy x=46.
x(|15|-10)=53
x(15-10)=53
x.5=53
x=53:5
x=52=25
Vậy x=25
2x+5=7-x-5
2x+x+5=7-5
3x+5=2
3x=2-5
3x=-3
x=(-3):3
x=-1
Vậy x=-1.

1) (x - 20).15 = 0
x - 20 = 0 : 15
x - 20 = 0
x = 0 + 20 = 20
2) 4.(x - 7) = 4
x - 7 = 4 : 4
x - 7 = 1
x = 1 + 7 = 8
3) 6.(x - 12) = 6
x - 12 = 6 : 6
x - 12 = 1
x = 1 + 12 = 13
4) (2x - 34).69 = 0
2x - 34 = 0 : 69
2x - 34 = 0
2x = 0 + 34
2x = 34
x = 34 : 2 = 17
5) 17.(x - 9) = 0
x - 9 = 0 : 17
x - 9 = 0
x = 0 + 9 = 9
6) (x - 40) - 270 = 0
x - 40 = 0 + 270
x - 40 = 270
x = 270 + 40 = 310
7) 127 + (200 - x) = 217
200 - x = 217 - 127
200 - x = 90
x = 200 - 90 = 110
8) 427 - (x + 100) = 227
x + 100 = 427 - 227
x + 100 = 200
x = 200 - 100 = 100
~ Học tốt ~
1).ta co (x-20).15=0
suy ra x-20=0
suy ra x=20
vay x=20
2).ta co 4(x-7)=4
suy ra x-7=1
suy ra x=8
vay x=8
- 3) ta co 6.(x-12)=6
suy ra x-12=1
suy ra x=13
4)ta co (2x-34).69=0
suy ra 2x-34=0
suy ra 2x=34
suy ra x=17
vay x=17
5)ta co 17.(x-9)=0
suy ra x-9=0
suy ra x=9
vay x=9
6)ta co (x-40)-270=0
suy ra x-40=270
suy ra x=310
vay x=310
7) ta co 127+(200-x)=217
suy ra 200-x=90
suy ra x=110
vay x=110
8) ta co 427-(x+100)=227
suy ra x+100=200
suy ra x=100
vay x =100
Chuc Cac Ban Hoc Tot Nhe!

\(-\frac{17}{x}-\frac{1}{15}=\frac{1}{10}\)
\(-\frac{17}{x}=\frac{1}{10}+\frac{1}{15}\)
\(-\frac{17}{x}=\frac{1}{6}\)
\(\Rightarrow x=-17.6\)
\(\Rightarrow x=-102\)

A. Ta có :
8.|x|=8
=>|x| =8:8
=>|x|=1
=>x=1 hoặc x= -1
Vậy x=1 hoặc x= -1

a) -21 + (4 - x) = -17 + (-20) + 5
=>-21 + 4 - x = -32
=> -17 - x = -32
=> x = -17 + 32
=> x = 15
b) (15 - x) - (+9) = 34 - (-31)
=> 15 - x - 9 = 34 + 31
=> 6 - x = 65
=> x = 6 - 65
=> x = -59
c) (17 + x) - (-12) = -14 - (-10)
=> 17 + x + 12 = -14 + 10
=> 29 + x = -4
=> x = -4 - 29
=> x = -33
c) (x + 24) + 15 = 8 - 17
=> x + 24 + 15 = -9
=> x + 39 = -9
=> x = -9 - 39
=> x = -48

x + (x + 1) + (x + 2) + ..... + (x + 2003) = 2004
2014x + (1 + 2 + 3 + .... + 2003) = 2004
2014x + 2007006 = 2004
2014 - 2014x = 2007006
<=> 2014(1 - x) = 2007006
=> 1 - x = 1001,5
=> x = -1000,5
b) \(\frac{x+5}{20}+\frac{x+6}{19}=\frac{x+7}{18}+\frac{x+8}{17}\)
\(\frac{x+5}{20}+1+\frac{x+6}{19}+1=\frac{x+7}{18}+1+\frac{x+8}{17}+1\)
\(\frac{x+25}{20}+\frac{x+25}{19}=\frac{x+25}{18}+\frac{x+25}{17}\)
\(\frac{x+25}{20}+\frac{x+25}{19}-\frac{x+25}{18}-\frac{x+25}{17}=0\)
\(\left(x+25\right)\left(\frac{1}{20}+\frac{1}{19}-\frac{1}{18}-\frac{1}{17}\right)=0\)
Vì \(\frac{1}{20}+\frac{1}{19}-\frac{1}{18}-\frac{1}{17}\ne0\)
=> x + 25 = 0
=> x = -25
có 2004 cái x => 2004x + (1+2+3+4+5+...+2003) = 2004
2004x +2007006 = 2004
2007006 = 2004 -2004x
2007006 = 2004*(1-x)
=>1 - x = 2007006 : 2004 = 1001.5
x = 1-1001.5=-1000.5

Đặt \(A=\left|x+100\right|+\left|y-5\right|+\left|z+200\right|=0\)
Ta có : \(\hept{\begin{cases}\left|x+100\right|\ge0\forall x\\\left|y-5\right|\ge0\forall y\\\left|z+200\right|\ge0\forall z\end{cases}}\Rightarrow A\ge0\forall x;y;z\)
Dấu ''='' xảy ra : \(x=-100;y=5;z=-200\)

(x - 35) - 120 = 0
<=> x-35-120=0
<=> x=155
124 + (118 - x) = 217
<=> 242-x=217
<=> x=25
156 - (x + 61) = 82
<=> 156-x-61=82
<=> 95-x=82
<=> x=13
217 - 17 x X = 200
=> 17 x X = 217 - 200 = 17
=> X = 17 : 17 = 1
X = 1