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a: =>2x+17=27
=>2x=27-17=10
=>x=5
b: =>2(19-x)=24
=>19-x=12
=>x=7
\(2\cdot x+17=3^5:3^2\)
\(\Rightarrow2\cdot x+17=3^3\)
\(\Rightarrow2\cdot x+17=27\)
\(\Rightarrow2\cdot x=27-17\)
\(\Rightarrow2\cdot x=10\)
\(\Rightarrow x=\dfrac{10}{2}\)
\(\Rightarrow x=5\)
___________
\(\left(19-x\right)\cdot2-20=4\)
\(\Rightarrow\left(19-x\right)\cdot2=24\)
\(\Rightarrow19-x=24:2\)
\(\Rightarrow19-x=12\)
\(\Rightarrow x=19-12\)
\(\Rightarrow x=7\)
11: Ta có: \(\left(x+3\right)^3=125\)
\(\Leftrightarrow x+3=5\)
hay x=2
12: Ta có: \(\left(2x\right)^4=16\)
\(\Leftrightarrow x^4=1\)
hay \(x\in\left\{1;-1\right\}\)
a) 2(x-51)=2.23+20 b)32(x+4)-52=5.52
2(x-51)=2.8+20 9(x+4)-25=125
2(x-51)=36 9(x+4)=125+25
x-51=36:2 9(x+4)=150
x-51=18 x+4= 150:9
x=18+51 x+4=50/9
x=69 x=14/9
Vậy:x=69 Vậy:x=14/9
Mik sai thì thôi nha!!!!
a) 2(x-51)=2.23+20 b)32(x+4)-52=5.52
2(x-51)=2.8+20 9(x+4)-25=125
2(x-51)=36 9(x+4)=125+25
x-51=36:2 9(x+4)=150
x-51=18 x+4= 150:9
x=18+51 x+4=50/9
x=69 x=4/9
Vậy:x=69 Vậy:x=4/9
\(a,[(2\cdot x-11):3+1]\cdot5=20\\\Rightarrow (2x-11):3+1=20:5\\\Rightarrow (2x-11):3+1=4\\\Rightarrow (2x-11):3=4-1\\\Rightarrow (2x-11):3=3\\\Rightarrow2x-11=3\cdot3\\\Rightarrow2x-11=9\\\Rightarrow2x=9+11\\\Rightarrow2x=20\\\Rightarrow x=20:2=10\)
\(b,(25-2x)^3:5-3^2=4^2\\\Rightarrow(25-2x)^3:5-9=16\\\Rightarrow(25-2x)^3:5=16+9\\\Rightarrow(25-2x)^3:5=25\\\Rightarrow(25-2x)^3=25\cdot5\\\Rightarrow(25-2x)^3=125\\\Rightarrow(25-2x)^3=5^3\\\Rightarrow25-2x=5\\\Rightarrow2x=25-5\\\Rightarrow2x=20\\\Rightarrow x=20:2=10\\Toru\)
a,\(x+5=20-\left(12-7\right)\)
\(x+5=15\)
\(x=10\)
b,\(15+\left(x-4\right)=20\)
\(x-4=5\)
\(x=9\)
a, (-4) . (+125) . (-25) . 6 . (-8)
=[ (-4) . (-25) ] . [ (+125) . (-8) ] . 6
= 100 . (-1000) . 6
= -100 000 . 6
= -600 000
b, 122 . (-12345) + 12345 . (-78)
= 12345 . [ (-122) + (-78) ]
= 12345 . (-200)
= -2 469 000
2x + 4(x - 2) = 32
<=> 2x + 4x - 8 = 32
<=> 6x = 40
<=> \(x=\dfrac{20}{3}\)
ai giúp