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Ta có: \(2020^{45}-2020^{44}\)
\(=2020^{44}\cdot2020-2020^{44}\cdot1\)
\(=2020^{44}\cdot\left(2020-1\right)\)
\(=2020^{44}\cdot2019\)
Ta có: \(2020^{44}-2020^{43}\)
\(=2020^{43}\cdot2020-2020^{43}\cdot1\)
\(=2020^{43}\cdot\left(2020-1\right)\)
\(=2020^{43}\cdot2019\)
Vì \(2020^{44}>2020^{43}\)
nên \(2020^{44}\cdot2019>2020^{43}\cdot2019\)
hay \(2020^{45}-2020^{44}>2020^{44}-2020^{43}\)
Mình làm 5 câu thôi nhé !:
1) \(7^x\cdot49=7^{90}\)
\(\Rightarrow7^x\cdot7^2=7^{90}\)
\(\Rightarrow7^{x+2}=7^{90}\)
\(\Rightarrow x=90-2\)
\(\Rightarrow x=88\)
2) \(2^x\cdot4=128\)
\(\Rightarrow2^x\cdot2^2=2^7\)
\(\Rightarrow2^{x+2}=2^7\)
\(\Rightarrow x=7-2\)
\(\Rightarrow x=5\)
3) \(3^x-1=2^4\cdot5\)
\(\Rightarrow3^x=80+1\)
\(\Rightarrow3^x=81\)
\(\Rightarrow3^x=3^4\)
\(\Rightarrow x=4\)
4) \(3^x+15=42\)
\(\Rightarrow3^x=42-15\)
\(\Rightarrow3^x=27\)
\(\Rightarrow3^x=3^3\)
\(\Rightarrow x=3\)
5) \(4\cdot2^x-3=125\)
\(\Rightarrow2^2\cdot2^x=128\)
\(\Rightarrow2^{x+2}=2^7\)
\(\Rightarrow x=7-2\)
\(\Rightarrow x=5\)
6)
\(5^x=5^{15}:5^3\\ \Leftrightarrow5^x=5^{15-3}\\ \Leftrightarrow5^x=5^{12}\\ \Leftrightarrow x=12\)
7)
\(4^x=4^{15}:16\\ \Leftrightarrow4^x=4^{15}:4^2\\ \Leftrightarrow4^x=4^{15-2}\\ 4^x=4^{13}\\ \Leftrightarrow x=13\)
8)
\(7^x=7^{20}:7^{10}\\ \Leftrightarrow7^x=7^{20-10}\\ \Leftrightarrow7^x=7^{10}\\ \Leftrightarrow x=10\)
9)
\(11^x=11^{11}:11\\ \Leftrightarrow11^x=11^{11-1}\\ \Leftrightarrow11^x=11^{10}\\ \Leftrightarrow x=10\)
10)
\(3^{15}.3^x=3^{30}\\ \Leftrightarrow3^x=3^{30}:3^{15}\\ 3^x=3^{30-15}\\ \Leftrightarrow3^x=3^{15}\\ \Leftrightarrow x=15\)
Lời giải:
$45-5(x+4)=10$
$5(x+4)=45-10=35$
$x+4=35:5=7$
$x=7-4=3$
------------------------
$(7x-15):3-6=17$
$(7x-15):3=17+6=23$
$7x-15=23\times 3=69$
$7x=69+15=84$
$x=84:7=12$
------------------
$3^{x+2}-5.3^x=108$
$3^x(3^2-5)=108$
$3^x.4=108$
$3^x=108:4=27=3^3$
$\Rightarrow x=3$
\(45-5\left(x+4\right)=10\)
\(\Rightarrow5\left(x+4\right)=45-10\)
\(\Rightarrow5\left(x+4\right)=35\)
\(\Rightarrow x+4=35:5\)
\(\Rightarrow x+4=7\)
\(\Rightarrow x=7-4\)
\(\Rightarrow x=3\)
______________
\(\left(7x-15\right):3-6=17\)
\(\Rightarrow\left(7x-15\right):3=17+6\)
\(\Rightarrow\left(7x-15\right):3=23\)
\(\Rightarrow7x-15=23\cdot3\)
\(\Rightarrow7x-15=69\)
\(\Rightarrow7x=69+15\)
\(\Rightarrow7x=84\)
\(\Rightarrow x=12\)
______________
\(3^{x+2}-5\cdot3^x=108\)
\(\Rightarrow3^x\cdot\left(3^2-5\right)=108\)
\(\Rightarrow3^x\cdot\left(9-5\right)=108\)
\(\Rightarrow3^x\cdot4=108\)
\(\Rightarrow3^x=108:4\)
\(\Rightarrow3^x=27\)
\(\Rightarrow3^x=3^3\)
\(\Rightarrow x=3\)
a) x + 45 -[ 90 + (-20) + 5 - (-45)] +3x
= x +45 -( 90 - 20 + 5 + 45) + 3x
= x +45 -120 +3x
= -75 +4x
b) x +(-294 +13 -2x) +(94 -13) +9x
= x -281 -2x +81 +9x
= -200 +8x
\(1,\Leftrightarrow7x=42\Leftrightarrow x=6\\ 2,\Leftrightarrow36-4x=4\Leftrightarrow4x=32\Leftrightarrow x=8\\ 3,\Leftrightarrow3x=35\Leftrightarrow x=\dfrac{35}{3}\\ 4,\Leftrightarrow x-12=144\Leftrightarrow x=156\\ 5,\Leftrightarrow x-14=16\Leftrightarrow x=30\\ 6,\Leftrightarrow3x-24=\dfrac{148}{73}\Leftrightarrow3x=\dfrac{1900}{73}\Leftrightarrow x=\dfrac{1900}{219}\\ 7,\Leftrightarrow33+x=45\Leftrightarrow x=12\\ 8,Sai.đề\\ 9,\Leftrightarrow\left(x+9\right):2=39\Leftrightarrow x+9=78\Leftrightarrow x=69\\ 11,\Leftrightarrow2\left(x+7\right)=38\Leftrightarrow x+7=19\Leftrightarrow x=12\\ 13,\Leftrightarrow2\left(x-51\right)=66\Leftrightarrow x-51=33\Leftrightarrow x=84\)
\(15,\Leftrightarrow x-19=9\Leftrightarrow x=28\\ 17,\Leftrightarrow\left(x-3\right):2=48\Leftrightarrow x-3=96\Leftrightarrow x=99\\ 19,\Leftrightarrow0x=46\Leftrightarrow x\in\varnothing\\ 8,Sai.đề\\ 14,\Leftrightarrow2x=209\Leftrightarrow x=\dfrac{209}{2}\\ 16,\Leftrightarrow2x+6=157\Leftrightarrow2x=151\Leftrightarrow x=\dfrac{151}{2}\\ 18,\Leftrightarrow5\left(x+4\right)=100\Leftrightarrow x+4=20\Leftrightarrow x=16\\ 20,\Leftrightarrow\left(3x-5\right)^3=27=3^3\Leftrightarrow3x-5=3\Leftrightarrow x=\dfrac{8}{3}\)
\(-3x+5=41\)
\(-3x=41-5\)
\(-3x=36\)
\(x=36:-3\)
\(x=-12\)
\(52-\left|x\right|=80\)
\(\left|x\right|=52-80\)
\(\left|x\right|=-28\)
\(\Rightarrow x=\orbr{\begin{cases}-28\\28\end{cases}}\)
-3x+5=41 52-|x|=80
-3x=41-5 |x|=52-80
-3x=36 |x|=-28
x=36:-3 \(x\in\Phi\)(vì giá trị tuyệt đối của một số không thể là 1 số âm)
x=-12
|7x+1|=20
\(\Leftrightarrow\orbr{\begin{cases}7x+1=20\\7x+1=-20\end{cases}}\Leftrightarrow\orbr{\begin{cases}7x=19\\7x=-21\end{cases}}\Leftrightarrow\orbr{\begin{cases}x\in\Phi\\x=-3\end{cases}}\)
Vậy x=-3
\(7x-2x=6^{20}:36^9+44:11\)
\(=>x\left(7-2\right)=6^{20}:6^{18}+4\)
\(=>x5=6^2+4=36+4=40\)
\(=>x=40:5\)
\(=>x=8\)
a, 7x + 10x = 5x
17x = 5x
17x - 5x = 0
12x = 0
x =0
2;
a, 4x + 7x = 22
11x = 22
x = 2
b, 12x - 8x = 25
4x = 25
x = \(\dfrac{25}{4}\)
c, \(\dfrac{1}{2}\)x - \(\dfrac{1}{3}\)x = \(\dfrac{4}{5}\)
(\(\dfrac{1}{2}-\dfrac{1}{3}\))x = \(\dfrac{4}{5}\)
\(\dfrac{1}{6}\)x = \(\dfrac{4}{5}\)
x = \(\dfrac{4}{5}\) : \(\dfrac{1}{6}\)
x = \(\dfrac{24}{5}\)
\(20+7x-3x=4^5:4^3\)
\(20+4x=4^2\)
\(20+4x=16\)
\(4x=16-20\)
\(4x=-4\)
\(x=-1\)
Vậy \(x=-1\)
\(20+7x-3x=4^5:4^3\)
\(\Rightarrow\) \(20+4x=4^2\)
\(\Rightarrow\) \(20+4x=16\)
\(\Rightarrow\) \(4x=16-20\)
\(\Rightarrow\) \(4x=-4\)
\(\Rightarrow\) \(x=-1\)