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\(1)\frac{1}{3}.\frac{4}{5}+\frac{1}{3}.\frac{6}{5}-\frac{1}{3}\)
\(=\frac{1}{3}\left(\frac{4}{5}+\frac{6}{5}\right)\)
\(=\frac{1}{3}.2\)
\(=\frac{2}{3}\)
\(1)\)\(\frac{1}{3}.\frac{4}{5}+\frac{1}{3}.\frac{6}{5}-\frac{1}{3}\)
\(=\frac{1}{3}.\left(\frac{4}{5}+\frac{6}{5}-1\right)\)
\(=\frac{1}{3}.\left(\frac{4}{5}+\frac{6}{5}-\frac{5}{5}\right)\)
\(=\frac{1}{3}.1\)
\(=\frac{1}{3}\)
\(2)\)\(\frac{3}{7}.\frac{9}{26}-\frac{1}{14}.\frac{1}{13}\)
\(=\frac{1}{7}.\frac{27}{26}-\frac{1}{7}.\frac{1}{26}\)
\(=\left(\frac{27}{26}-\frac{1}{26}\right).\frac{1}{7}\)
\(=1.\frac{1}{7}\)
\(=\frac{1}{7}\)
\(3)\)\(15\left(\frac{1}{5}-\frac{7}{15}+\frac{17}{3}\right)\)
\(=3-7+85\)
\(=81\)
\(4)\)\(38\left(2\frac{1}{19}-5\frac{7}{38}\right)\)
\(=38\left(\frac{39}{19}-\frac{197}{38}\right)\)
\(=78-197\)
\(=-119\)
\(5)\)\(75\left(\frac{-4}{25}+7\frac{1}{15}-5\frac{7}{75}\right)\)
\(=75\left(\frac{-4}{25}+\frac{106}{15}-\frac{382}{75}\right)\)
\(=-12+530-382\)
\(=136\)
Ddaeng
A) 7/38 x 9/11 +7/38 x 4/11 -7/38 x 2/11
=7/38.(9/11+4/11-2/11)
=7/38
B) 5/31 x 21/25 + 5/31 x -7/10 - 5/31 x 9/20
=5/31.(21/25-7/10-9/20)
=5/31.(-31/100)
=-1/20
3: =231+26-209-26=22
4: =19(25+30+45)=19x100=1900
5: =-50+19+143+79-25-48
=-75+95+98
=98+20=118
a)x-160:40=45
x-4=45
x=45+4
x=49
b)(x+45):15=80
x+45=80.15
x+45=1200
x=1155
c)x-50:25=8
x-5=8
x=13
d)5.x-38:19=13
5x-2=13
5x=15
x=3
d)(5x-38):19=13
5x-38=247
5x=285
x=57
e)(3x-18)(2x-20)=0
\(\Rightarrow\left[\begin{array}{nghiempt}3x-18=0\\2x-20=0\end{array}\right.\)\(\Rightarrow\left[\begin{array}{nghiempt}3x=18\\2x=20\end{array}\right.\)\(\Rightarrow\left[\begin{array}{nghiempt}x=6\\x=10\end{array}\right.\)
Vậy x=6;10
g)Gọi số tự nhiên thứ nhất là a
số tự nhiên thứ hai là b
Vì lấy số lớn chia số nhỏ đc thương là 9 và dư là 11
Mà a+b=361
a=361-b
Suy ra:(11+a):b=9
Ta có:(11+a):b=9
(11+361-b):b=9
(372-b):b=9
372:b-1=9
372:b=10
b=372:10
b ko TM
Xem lại đề
x - 160 : 40 = 45
x - 4 = 45
x = 45 + 4
x = 49
Vậy x = 49
(x + 45 ):15 = 80
x + 45 = 80.15
x + 45 = 1000
x = 1000 - 45
x = 955
Vậy x = 995
x - 50:25 = 8
x - 2 = 8
x = 8 + 2
x = 10
Vậy x = 10
5.x - 38:19 = 13
5.x - 2 = 13
5.x = 13 + 2
x = 15:5
x = 3
Vậy x = 3
( 5.x - 38 ):19 = 13
5.x - 38 = 13.19
5.x - 38 = 247
5.x = 247 + 38
5.x = 285
x = 285:5
x = 57
Vậy x = 57
( 3x - 18 ).( 2x - 20 ) = 0
3x - 18 = 0 hoặc 2x - 20 = 0
+) 3x - 18 = 0
3x = 18
x = 6
+) 2x - 20 =0
2x = 20
x = 10
Vậy x = 6 hoăc x = 10
7: =6-7+4-3=0
8: =8x5-9x4+4x6=40-36+24=28
3: =231+26-209-26=22
1) x - 25 =75. 2) 24-x = 19. 3) 3+2*x = 15. 4) 29*x -13= 45. 5) 5* x- 17= 38. 6) 50 -2 * x (x+1) =20
1) x - 25 =75
x=75+25
x=100.
2) 24-x = 19
x=24-19
x=5.
3) 3+2*x = 15
2*x=12
x=12:2
x=6.
4) 29*x -13= 45.
29*x=58
x=58:29
x=2
5) 5* x- 17= 38
5*x=21
x=21/5.
6) 50 -2 * x (x+1) =20
2 * x (x+1) =30
x (x+1) =15
1/\(\left(-12\right)\cdot46-12\cdot54=\left(-12\right)\cdot46+\left(-12\right)\cdot54\)
\(=\left(-12\right)\cdot\left(46+54\right)=\left(-12\right)\cdot100=-1200\)
2/\(3784+23-3785-15=3785+22-3785-15\)
\(=22-15=7\)
3/\(\left(-8\right)\cdot25\cdot\left(-2\right)\cdot4\cdot\left(-5\right)\cdot125\)
\(=\left[\left(-8\right)\cdot125\right]\cdot\left[25\cdot4\right]\cdot\left[\left(-5\right)\cdot\left(-2\right)\right]\)
\(=\left(-1000\right)\cdot100\cdot10=-1000000\)
4/\(19\cdot25+9\cdot95+19\cdot30=19\cdot\left(25+30\right)+9\cdot95\)
\(=19\cdot55+9\cdot95=95\cdot11+9\cdot95=95\cdot\left(11+9\right)=20\cdot95=1900\)
5/\(\left(-50+19+143\right)-\left(-79+25+48\right)\)
\(=\left(-50\right)+19+143+79-25-48\)
\(=118\)
6/\(\left(-25\right)\cdot\left(75-45\right)-75\cdot\left(45-25\right)\)
\(=\left(-25\right)\cdot30+\left(-25\right)\cdot3\cdot20\)
\(=\left(-25\right)\cdot\left(30+60\right)=\left(-25\right)\cdot90=-2250\)
7/\(\left(-37-17\right)\cdot\left(-9\right)+35\left(-9-11\right)\)
\(=\left(-54\right)\cdot\left(-9\right)+35\cdot\left(-20\right)\)
\(=486+\left(-700\right)=-214\)
8/\(\left(187-23\right)-\left(20-180\right)\)
\(=187-23-20+180=324\)
9/\(512\cdot2-128\cdot\left(-512\right)\)
\(=512\cdot2+128\cdot512=512\cdot\left(2+128\right)\)
\(=512\cdot130=66560\)
10/\(17\cdot\left(-25\right)+25\cdot21\)
\(=17\cdot\left(-25\right)-\left(-25\right)\cdot21=\left(-25\right)\cdot\left(17-21\right)\)
\(=\left(-25\right)\cdot\left(-4\right)=100\)
Chúc bạn học tốt.