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\(\frac{3^6\times45^4-15^{13}\times5^{-9}}{27^4\times25^3+45^6}\)
\(=\frac{3^6\times\left(3^2\times5\right)^4-\left(3\times5\right)^{13}\times5^{-9}}{\left(3^3\right)^4\times\left(5^2\right)^3+\left(3^2\times5\right)^6}\)
\(=\frac{3^6\times3^8\times5^4-3^{13}\times5^{13}\times5^{-9}}{3^{12}\times5^6+3^{12}\times5^6}\)
\(=\frac{3^{14}\times5^4-3^{13}\times5^4}{3^{12}\times5^6+3^{12}\times5^6}\)
\(=\frac{3^{13}\times5^4\times\left(3-1\right)}{2\times3^{12}\times5^6}\)
\(=\frac{3\times2}{2\times5^2}\)
\(=\frac{3}{25}\)
\(\dfrac{3^6.45^4-15^{13}.5^{-9}}{27^4.25^3+45^6}=\dfrac{3^6.3^85^4-3^{13}.5^{13}.5^{-9}}{3^{12}.5^6+3^{12}.5^6}\)
\(=\dfrac{3^{14}.5^4-3^{13}.5^4}{2.3^{12}.5^6}=\dfrac{3^{13}.5^4\left(3-1\right)}{2.3^{12}.5^6}\)
\(=\dfrac{3.2}{2.5^2}=\dfrac{3}{25}\)
\(\frac{3^6.45^4-15^{13}:5^9}{27^4.25^3+45^6}\)=\(\frac{3^{14}.5^4-3^{13}.5^4}{3^{12}.5^6+3^{12}.5^6}=\frac{3^{13}.5^4\left(3-1\right)}{3^{12}.5^6\left(1+1\right)}\)=\(\frac{3}{25}\)
\(\frac{3^6.3^6.5^4-3^{13}.5^{13}.5^{-9}}{3^{12}.5^6+3^{12}.5^6}=\frac{3^{12}.5^4-3^{13}.5^7}{2.3^{12}.5^6}\) \(=\frac{3^{12}.5^4.\left(1-5^3\right)}{3^{12}.5^6.2}=\frac{-124}{5^2.2}=\frac{-62}{25}\) =2,48
Ta có : \(A=\frac{3^6.45^4-15^{13}.5^{-9}}{27^4.25^3.45^6}\)
=\(\frac{3^6.5^4.3^8-3^{13}.5^{13}.5^{-9}}{3^{12}.5^6+5^6.3^{12}}\)
=\(\frac{3^{14}.5^4-3^{13}.5^4}{3^{12}.5^6+5^6.3^{12}}=\frac{3^{13}.5^4.\left(3-1\right)}{5^6.3^{12}.\left(1+1\right)}=\frac{3}{5^2}=\frac{3}{25}\)
có bạn nào ko giúp mình với