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a) x=50-37
x= 13
b) 2.x=11+3
2.x=14
x=14:2=7
c) 2+x=6.5
2.x=30
x=30:2=15
e) \(^{^{^{ }}x^9}\)=25
\(\Rightarrow\)x=5
Bài 1:
2\(x\) = 4
2\(^x\) = 22
\(x=2\)
Vậy \(x=2\)
Bài 2:
2\(^x\) = 8
2\(^x\) = 23
\(x=3\)
Vậy \(x=3\)
Lời giải:
a. $x^3=4^3\Rightarrow x=4$
b. $x^2=49=7^2=(-7)^2$
$\Rightarrow x=7$ hoặc $x=-7$
c. $x^3+1=28$
$x^3=28-1=27=3^3$
$\Rightarrow x=3$
d. $2^x=16=2^4$
$\Rightarrow x=4$
e. $2^4.2^x=2^6$
$\Rightarrow 2^{4+x}=2^6$
$\Rightarrow 4+x=6$
$\Rightarrow x=2$
g.
$5^x=25.5^3=5^2.5^3=5^5$
$\Rightarrow x=5$
Lần sau bạn lưu ý viết đề bằng công thức toán (biểu tượng $\sum$ góc trái khung soạn thảo) để đề được rõ ràng hơn nhé.
a) \(3^2.x+2^3.x=51\)
\(\Leftrightarrow x\left(3^2+2^3\right)=51\)
\(\Leftrightarrow17x=51\)
\(\Leftrightarrow x=3\)
Vậy
b) \(6^2.2-\left(84-3^2.x\right):7=69\)
\(\Leftrightarrow\left(84-3^2.x\right):7=3\)
\(\Leftrightarrow84-3^2.x=21\)
\(\Leftrightarrow3^2.x=63\)
\(\Leftrightarrow x=7\)
Vậy
Mình cho đề bài thế này nhé \(2^x+2^{x+1}+2^{x+2}+...+2^{x+2017}=2^{2020}-4\) (1)
Nhân cả 2 vế của (1) cho 2, ta được \(2^{x+1}+2^{x+2}+2^{x+3}+...+2^{x+2018}=2^{2021}-8\) (2)
Lấy (2) trừ theo vế với (1), ta thu được \(2^{x+2018}-2^x=2^{2020}-4\)
\(\Leftrightarrow2^x.2^{2018}-2^x=2^2.2^{2018}-2^2.1\)
\(\Leftrightarrow2^x\left(2^{2018}-1\right)=2^2\left(2^{2018}-1\right)\)
do \(2^{2018}-1\ne0\) nên ta hoàn toàn có thể suy ra \(2^x=2^2\Leftrightarrow x=2\)
Vậy \(x=2\)
(x² + 1) + (x² + 2) + ... + (x² + 50) = 1475
x² + 1 + x² + 2 + ... + x² + 50 = 1475
50x² + (1 + 2 + ... + 50) = 1475
50x² + 50 . 51 : 2 = 1475
50x² + 1275 = 1475
50x² = 1475 - 1275
50x² = 200
x² = 200 : 50
x² = 4
x = 2 hoặc x = -2
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