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\(\frac{4}{3}.\frac{9}{8}.\frac{16}{15}.....\frac{3481}{3480}\)
\(=\frac{2^2}{1.3}.\frac{3^2}{2.4}.\frac{4^2}{3.5}....\frac{59^2}{58.60}\)
\(=\frac{2.3.4.....59}{1.2.3.....58}.\frac{2.3.4....59}{3.4.5....60}\)
\(=59.\frac{2}{60}=\frac{59}{30}\)
Ta có : \(\frac{4}{3}.\frac{9}{8}.\frac{16}{15}.......\frac{3481}{3480}\)
\(=\frac{2.2}{1.3}.\frac{3.3}{2.4}.\frac{4.4}{3.5}........\frac{59.59}{58.60}\)
\(=\frac{2.3.4........59}{1.2.3.......58}.\frac{2.3.4.......59}{3.4.5........60}\)
\(=59.\frac{1}{30}=\frac{59}{30}\)
\(A=\left(1+\frac{1}{1\cdot3}\right)\left(1+\frac{1}{2\cdot4}\right)\left(1+\frac{1}{3\cdot5}\right)\cdot...\cdot\left(1+\frac{1}{99\cdot101}\right)\)
\(A=\frac{4}{1\cdot3}\cdot\frac{9}{2\cdot4}\cdot\frac{16}{3\cdot5}\cdot...\cdot\frac{10000}{99\cdot101}\)
\(A=\frac{\left(2\cdot2\right)\left(3\cdot3\right)\left(4\cdot4\right)\cdot...\cdot\left(100\cdot100\right)}{\left(1\cdot3\right)\left(2\cdot4\right)\left(3\cdot5\right)\cdot...\cdot\left(99\cdot101\right)}\)
\(A=\frac{\left(2\cdot3\cdot4\cdot...\cdot100\right)\left(2\cdot3\cdot4\cdot...\cdot100\right)}{\left(1\cdot2\cdot3\cdot...\cdot99\right)\left(3\cdot4\cdot5\cdot...\cdot101\right)}\)
\(A=\frac{100\cdot2}{1\cdot101}\)
\(A=\frac{200}{101}\)
1x3:3x9:3x12;3=12
tick nhé Phan Thê Tinh