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\(\left(2.8x-32\right):\frac{2}{3}=90\)
\(2.8\cdot x-32=90\cdot\frac{2}{3}\)
\(\frac{14}{5}x-32=60\)
\(\frac{14}{5}x=60+32\)
\(\frac{14}{5}x=92\)
\(x=\frac{230}{7}\)
B , c , d tương tự
![](https://rs.olm.vn/images/avt/0.png?1311)
12/14 + 15/20 + 6/7 + 3/4
= ( 12/14 + 6/7 ) + ( 15/20 + 3/4 )
= ( 6/7 + 6/7 ) + ( 3/4 + 3/4 )
= 12/7 + 6/4
= 48/28 + 42/28
= 90/28
= 45/14
Tham khảo nha !!!
![](https://rs.olm.vn/images/avt/0.png?1311)
a/ \(\left[\frac{4}{6}+\frac{14}{6}\right]+\left[\frac{7}{13}+\frac{19}{13}\right]+\left[\frac{17}{9}+\frac{1}{9}\right]=\frac{18}{6}+\frac{26}{13}+\frac{18}{9}=3+2+2=7\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a,\frac{10}{21}×\frac{14}{25}=\frac{4}{15}\)
\(b,3\frac{1}{3}×\frac{12}{35}=\frac{10}{3}×\frac{12}{35}=\frac{8}{7}\)
\(c,\frac{7}{15}×\frac{11}{13}+\frac{7}{15}×\frac{2}{13}+\frac{8}{15}=\frac{7}{15}+\frac{8}{15}=1\)
\(d,\left(\frac{41}{75}+\frac{17}{10}\right)×\frac{80}{129}=\frac{4}{9}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a, \(\frac{3}{4}\times\frac{4}{7}+\frac{5}{14}\)
\(=\frac{3}{7}+\frac{5}{14}=\frac{6}{14}+\frac{5}{14}=\frac{11}{14}\)
b, \(\frac{5}{14}+\frac{9}{7}\div\frac{3}{4}\)
\(=\frac{5}{14}+\frac{9}{7}\times\frac{4}{3}=\frac{5}{14}+\frac{12}{7}=\frac{5}{14}+\frac{24}{14}=\frac{29}{14}\)
c, \(\frac{12}{17}\div x=\frac{3}{5}\)
\(x=\frac{12}{17}\div\frac{3}{5}=\frac{12}{17}\times\frac{5}{3}=\frac{20}{17}\)
\(\frac{3}{4}X\frac{4}{7}+\frac{5}{14}\)
\(=\frac{3}{7}+\frac{5}{14}\)
\(=\frac{6}{14}+\frac{5}{14}\)
\(=\frac{11}{14}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 1:
a) \(\frac{3}{4}×\frac{4}{7}=\frac{3×4}{4×7}=\frac{3}{7}\)
\(\frac{12}{35}:\frac{3}{5}=\frac{12}{35}×\frac{5}{3}=\frac{12×5}{35×3}=\frac{4.}{7}\)
\(\frac{4}{7}×\frac{3}{5}=\frac{4×3}{7×5}=\frac{12}{35}\)
b) \(\frac{13}{11}×2=\frac{13×2}{11}=\frac{26}{11}\)
\(\frac{26}{11}:\frac{13}{11}=\frac{26}{11}×\frac{11}{13}=\frac{26×11}{11×13}=\frac{2×1}{1×1}=\frac{2}{1}=2\)
\(\frac{26}{11}:2=\frac{26}{11}×\frac{1}{2}=\frac{26×1}{11×2}=\frac{13×1}{11×1}=\frac{13}{11}\)
\(2×\frac{13}{11}=\frac{2×13}{11}=\frac{26}{11}\)
k giúp mik ✅
Bài 2:
a) \(\frac{4}{7}×\:x\:=\frac{1}{3}\)
\(\Rightarrow\)x = \(\frac{1}{3}-\frac{4}{7}\)
\(\Rightarrow\)x = \(\frac{7}{21}-\frac{4}{21}\)
\(\Rightarrow\)x = \(\frac{3}{21}=\frac{1}{7}\)
b) x : \(\frac{2}{5}=\frac{2}{9}\)
\(\Rightarrow\)x = \(\frac{2}{9}×\frac{2}{5}\)
\(\Rightarrow\)x = \(\frac{4}{45}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{1}{2}:\frac{3}{2}:\frac{5}{4}:\frac{6}{5}:\frac{7}{6}:\frac{8}{7}\)
\(=\frac{1}{2}\cdot\frac{2}{3}\cdot\frac{4}{5}\cdot\frac{5}{6}\cdot\frac{6}{7}\cdot\frac{7}{8}\)
\(=\frac{1\cdot\left(2\cdot5\cdot6\cdot7\right)}{8\cdot3\cdot\left(2\cdot5\cdot6\cdot7\right)}\)
\(=\frac{1}{24}\)
\(\frac{1}{2}\cdot\frac{2}{3}\cdot\frac{3}{4}\cdot\frac{4}{5}\cdot\frac{5}{6}\cdot\frac{6}{7}\cdot\frac{7}{8}\cdot\frac{8}{9}\cdot\frac{9}{10}\)
\(=\frac{1\cdot\left(2\cdot3\cdot4\cdot5\cdot6\cdot7\cdot8\cdot9\right)}{\left(2\cdot3\cdot4\cdot5\cdot6\cdot7\cdot8\cdot9\right)\cdot10}\)
\(=\frac{1}{10}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{2}{26}\)+\(\frac{9}{12}\)+\(\frac{4}{7}\)+\(\frac{9}{21}\)+\(\frac{12}{13}\)+\(\frac{20}{80}\) = \(\frac{1}{13}+\frac{3}{4}+\frac{4}{7}+\frac{3}{7}+\frac{12}{13}+\frac{1}{4}=\left(\frac{1}{13}+\frac{12}{13}\right)+\left(\frac{4}{7}+\frac{3}{7}\right)+\left(\frac{1}{4}+\frac{3}{4}\right)\)
= 1+ 1+ 1= 3
\(\frac{2}{26}+\frac{9}{12}+\frac{4}{7}+\frac{9}{21}+\frac{12}{13}+\frac{20}{80}\)
=\(\frac{1}{13}+\frac{3}{4}+\frac{4}{7}+\frac{3}{7}+\frac{12}{13}+\frac{1}{4}\)
=\(\left(\frac{1}{13}+\frac{12}{13}\right)+\left(\frac{3}{4}+\frac{1}{4}\right)+\left(\frac{4}{7}+\frac{3}{7}\right)\)
= 1 + 1 + 1
= 3
like nha bạn!!!!
(12/7x4/13)+(12/14x14/26)+(6/7x2/13)
= 48/91 + 6/13 + 12/91
= 90/91 + 12/91
= 102/91