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1 tháng 8 2019

Đặt A = 1 x 2 + 2 x 3 + ... + 2011 x 2012

   3A = 1 x 2 x 3 + 2 x 3 x 3 + ... + 2010 x 2011 x 3 + 2011 x 2012 x 3

   3A = 1 x 2 x 3 + 2 x 3 x (4 - 1) + ... + 2010 x 2011 x (2012 - 2009) + 2011 x 2012 x (2013 - 2010)

   3A = 1 x 2 x 3 + 2 x 3 x 4 - 1 x 2 x 3 + ... + 2010 x 2011 x 2012 - 2009 x 2010 x 2011 + 2011 x 2012 x 2013 - 2010 x 2011 x 2012

   3A = 2011 x 2012 x  2013

   3A = 8 144 863 176

     A = 2 714 954 572

4 tháng 11 2023

\(\dfrac{2}{1\times2\times3}+\dfrac{2}{2\times3\times4}+\dfrac{2}{3\times4\times5}+...+\dfrac{2}{48\times49\times50}\)

\(=\dfrac{1}{1\times2}-\dfrac{1}{2\times3}+\dfrac{1}{2\times3}-\dfrac{1}{3\times4}+\dfrac{1}{3\times4}-\dfrac{1}{4\times5}+...+\dfrac{1}{48\times49}-\dfrac{1}{49\times50}\)

\(=\dfrac{1}{1\times2}-\dfrac{1}{49\times50}\)

\(=\dfrac{1}{2}-\dfrac{1}{2450}\)

\(=\dfrac{612}{1225}\)

\(\text{#}Toru\)

4 tháng 11 2023

1/2 - 1/49 x50

\(\frac{1}{1.2.3}+\frac{1}{2.3.4}+...+\frac{1}{8.9.10}=\frac{1}{2}.\left(\frac{1}{1.2}-\frac{1}{2.3}\right)+\frac{1}{2}.\left(\frac{1}{2.3}-\frac{1}{3.4}\right)+...+\frac{1}{2}.\left(\frac{1}{8.9}-\frac{1}{9.10}\right)\)

\(=\frac{1}{2}.\left(\frac{1}{1.2}-\frac{1}{2.3}+\frac{1}{2.3}-\frac{1}{3.4}+...+\frac{1}{8.9}-\frac{1}{9.10}\right)\)

\(\frac{1}{2}.\left(\frac{1}{1.2}-\frac{1}{9.10}\right)=\frac{1}{2}.\frac{22}{45}=\frac{11}{45}\)

6 tháng 6 2017

\(\frac{1x1x1}{1x2x4}x\frac{2.2.1}{1.1.2.2}=\frac{1}{8}.1=\frac{1}{8}\)

6 tháng 6 2017

=1X2X3/1X2X3X4X2= 1/8                 =3X2X2X2X5/3X2X2X5X2= 1/1

=1/8X1/1=1/8

28 tháng 8 2017

Cho biểu thức A= 11×2×3 12×3×4 13×

4×5 +...+ 118×19×20 . So sánh A với 14 .

Dương Đình Hưởng

cố lên mà k

23 tháng 7 2023

\(1,\\ =\dfrac{2-1}{1\times2}+\dfrac{3-2}{2\times3}+\dfrac{4-3}{3\times4}+\dfrac{5-4}{4\times5}+.....+\dfrac{99-98}{98\times99}+\dfrac{100-99}{99\times100}\\ =1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}+....+\dfrac{1}{98}-\dfrac{1}{99}+\dfrac{1}{99}-\dfrac{1}{100}\\ =1-\dfrac{1}{100}=\dfrac{100-1}{100}=\dfrac{99}{100}\)

\(2,=\dfrac{13-11}{11\times13}+\dfrac{15-13}{13\times15}+....+\dfrac{21-19}{19\times21}+\dfrac{23-21}{21\times23}\\ =\dfrac{1}{11}-\dfrac{1}{13}+\dfrac{1}{13}-\dfrac{1}{15}+....+\dfrac{1}{19}-\dfrac{1}{21}+\dfrac{1}{21}-\dfrac{1}{23}\\ =\dfrac{1}{11}-\dfrac{1}{23}\\ =\dfrac{23-11}{11\times23}=\dfrac{12}{253}\)

@seven

a: 1/1*2+1/2*3+...+1/99*100

=1-1/2+1/2-1/3+...+1/99-1/100

=1-1/100

=99/100

b: 2/11*13+2/13*15+...+2/21*23
=1/11-1/13+1/13-1/15+...+1/21-1/23

=1/11-1/23

=12/253

( 1/1.2 + 1/2.3 + 1/3.4 + 1/4.5 +1/5.6 ) x 10 - x = 0

= ( 1- 1/2 +1/2 -1/3 +1/3 - 1/4 + 1/4 - 1/5 +1/5 -1/6 ) x 10 - x = 0

= ( 1 - 1/6 ) x 10 - x = 0

= 5/6 x 10 - x =0

=   25/3 - x =0

               x = 25/3 - 0

                x  = 25/3

2 tháng 6 2015

\(\left(\frac{1}{1\times2}+\frac{1}{2\times3}+\frac{1}{3\times4}+\frac{1}{4\times5}+\frac{1}{5\times6}\right)\times10-x=0\)

\(\left(\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}\right)\times10-x=0\)

\(\left(\frac{1}{1}-\frac{1}{6}\right)\times10-x=0\)

\(\frac{5}{6}\times10-x=0\)

\(\frac{25}{3}-x=0\)

x              =\(\frac{25}{3}-0=\frac{25}{3}\)

24 tháng 3 2018

Suy ra 2A=2/1x2x3+2/2x3x4+2/3x4x5+......+2/38x39x40

        2A=3-1/1x2x3+4-2/2x3x4+5-3/3x4x5+........+40-38/38x39x40

       2A=1/1x2-1/2x3+1/2x3-1/3x4+1/4x5-1/5x6+........+1/38x39-1/39x40

      2A=1/2-1/1560

      2A=780/1560-1/1560

      2A=779/1560

     A=779/1560:2

     A=779/1560x1/2

   A=779/3120

24 tháng 3 2018

\(A=\frac{1}{1.2.3}+\frac{1}{2.3.4}+\frac{1}{3.4.5}+.......+\frac{1}{38.39.40}\)

\(2A=\frac{2}{1.2.3}+\frac{2}{2.3.4}+\frac{2}{3.4.5}+.........+\frac{2}{38.39.40}\)

\(2A=\frac{3-1}{1.2.3}+\frac{4-2}{2.3.4}+\frac{5-3}{3.4.5}+....+\frac{40-38}{38.39.40}\)

\(2A=\frac{3}{1.2.3}-\frac{1}{1.2.3}+\frac{4}{2.3.4}-\frac{2}{2.3.4}+\frac{5}{3.4.5}-\frac{3}{3.4.5}+.......+\frac{40}{38.39.40}-\frac{38}{38.39.40}\)

\(2A=\frac{1}{1.2}-\frac{1}{2.3}+\frac{1}{2.3}-\frac{1}{3.4}+\frac{1}{3.4}-\frac{1}{4.5}+.......+\frac{1}{38.39}-\frac{1}{39.40}\)

\(2A=\frac{1}{1.2}-\frac{1}{39.40}\)

\(2A=\frac{1}{2}-\frac{1}{1560}\)

\(2A=\frac{779}{1560}\)

\(A=\frac{779}{1560}:2\)

\(A=\frac{779}{3120}\)

3 tháng 3 2017

bằng 2014 nhé bạn