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1/2 + 1/4 +1/8 + 1/16 + 1/32
= 16/32 + 3/32 + 4/32 + 2/32 + 1/32
=26/32 =13/16

\(2\frac{1}{2}+3\frac{1}{18}+7\frac{5}{36}\)
\(=\frac{5}{2}+\frac{55}{18}+\frac{257}{36}\)
\(=\frac{90}{36}+\frac{110}{36}+\frac{257}{36}\)
\(=\frac{90+110+257}{36}=\frac{457}{36}\)
\(2\frac{1}{2}+3\frac{1}{18}+7\frac{5}{36}\)
\(=\left(2+3+7\right)\left(\frac{1}{2}+\frac{1}{18}+\frac{5}{36}\right)\)
\(=12\left(\frac{1}{2}+\frac{1}{18}+\frac{5}{36}\right)\)
\(=12\frac{25}{36}=\frac{457}{36}\)

\(2\frac{3}{4}\times3\frac{1}{5}\)
\(=\frac{11}{4}\times\frac{16}{5}\)
\(=\frac{176}{20}=\frac{44}{5}\)
\(2\frac{3}{4}\cdot3\frac{1}{5}=8\frac{4}{5}\)

a. 6 và 5/3 + 7 và 13/8 +3 và 1/3- 4 và 5/8
=23/3+69/8+4/3-37/8
=391/24+4/3+37/8=141/8-37/8=103/8
b.=(27/5+69/11)-(17/5-52/11)
=642/55+73/55=13

\(\frac{6}{7}+\frac{2}{5}-\frac{1}{2}+2\frac{38}{91}-\frac{4}{5}=\frac{27300}{31850}+\frac{12740}{31850}-\frac{15925}{31850}+\) \(2\frac{13300}{31850}\)\(-\frac{25480}{31850}\)
\(=2\frac{27300+12740-15925+13300-25480}{31850}\)\(=2\frac{341}{910}\)
HỌC TỐT!!!

Tìm \(x\):
a; \(x\) + 35,2 = [25,6 + 3,14] x 3
\(x+\) 35,2 = 28,74 x 3
\(x\) + 35,2 = 86,22
\(x\) = 86,22 - 35,2
\(x\) = 51,02
b; \(\frac{17}{5}\) : \(x\) = \(\frac{34}{5}\) : \(\frac43\)
\(\frac{17}{5}\) : \(x\) = \(\frac{34}{5}\) x \(\frac34\)
\(\frac{17}{5}\) : \(x\) = \(\) \(\frac{51}{10}\)
\(x\) = \(\frac{17}{5}\) : \(\frac{51}{10}\)
\(x\) = \(\frac{17}{5}\) x \(\frac{10}{51}\)
\(x\) = \(\frac23\)
c; [\(x\) - \(\frac12\)] x \(\frac53\) = \(\frac74\) - \(\frac12\)
[\(x\) - \(\frac12\)] x \(\frac53\) = \(\frac74-\frac24\)
[\(x-\frac12\)] x \(\frac53\) = \(\frac54\)
\(x-\frac12\) = \(\frac54\) : \(\frac53\)
\(x-\frac12\) = \(\frac54\) x \(\frac35\)
\(x\) - \(\frac12\) = \(\frac34\)
\(x=\frac34+\frac12\)
\(x=\frac34+\frac24\)
\(x=\) \(\frac54\)
d; [72 - 4 x \(x\)] : 9 = 4
72 - 4 x \(x\) = 4 x 9
72 - 4 x \(x\) = 36
4 x \(x\) = 72 - 36
4 x \(x\) = 36
\(x\) = 36 : 4
\(x\) = 9
1/2 x 1/3 + 1/4
( 1/2 x 1/3 ) + 1/4
1/6 + 1/4
5/12
ngongocanhtho
1/2x1/3+1/4
=1/6+1/4
=5/12