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a ) \(\left(19x+2,5^2\right)\div14=\left(13-8\right)^2-4^2\)
\(\Rightarrow\left(19x+50\right)\div14=5^2-16\)
\(\Rightarrow\left(19+50\right)\div14=25-16=9\)
\(\Rightarrow19x+50=9\times14\)
\(\Rightarrow19x+50=126\)
\(\Rightarrow19x=126-50\)
\(\Rightarrow19x=76\)
\(\Rightarrow x=4\)
b ) \(1440\div\left[41-\left(2x-5\right)\right]=2^4.3\)
\(\Leftrightarrow1440\div\left[41-\left(2x-5\right)\right]=48\)
\(\Leftrightarrow41-\left(2x-5\right)=30\)
\(\Leftrightarrow2x-5=11\)
\(\Leftrightarrow2x=16\)
\(\Leftrightarrow x=8\)
câu b sai rồi,thế này mới đúng nè:
b,(19x+2.55):4=(13-8)2-42
(19x+2.52):14=52-42
(19x+2.52):14=8
19x+2.52+126
19x+50=126
19x=76
x=4
a,(19x+2.52):14=(13-8)2-42
(19x+2.25):14=52-42
19x+50=9.14
19x=126-50
19x=76
x=76:19=4
b,(3x-24).73=2.74
(3x-24).73=2.7.73
(3x-16).73=14.73
3x-16=14
3x=30
x=10
(19x+2.52):14=(13-8)2-42
=>19x+50=9.14
=>19x=126-50
=>19x=76
=>x=4
vậy x=4
(19x+2.52):14=(13-8)2-42
=>19x+50=9.14
=>19x=126-50
=>19x=76
=>x=4
vậy x=4
Ta có : \(\left(19x+2\cdot5^2\right):14=\left(13-8\right)^2-4\)
\(\Leftrightarrow\left(19x+2\cdot25\right):14=5^2-4\)
\(\Leftrightarrow\left(19x+50\right)=21\cdot14\)
\(\Leftrightarrow19x+50=294
\)
\(\Leftrightarrow19x=294-50\)
\(\Leftrightarrow x=\frac{244}{19}=12\frac{16}{19}\)
( 19x + 2 . 5\(^2\)) : 14 = ( 13 - 8 )\(^2\) - 4
( 19x + 2 . 25 ) : 14 = 5\(^2\)- 4
( 19x + 50 ) : 14 = 25 - 4
( 19x + 50 ) : 14 = 21
19x + 50 = 21 . 14
19x + 50 = 294
19x = 294 - 50
19x = \(\frac{244}{19}\)
(19x + 2 . 52 ) : 14= ( 13 - 82 ) - 42
(19x + 2 . 25 ) : 14= ( 13 - 64 ) - 16
(19x + 50 ) : 14= ( -51 ) - 16
(19x + 50 ) : 14= -67
(19x + 50 ) =-67 .14
(19x + 50 ) =-938
x =(-938-50): 19
x=-52