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Đặt \(A=\frac{3\cdot7\cdot13\cdot37\cdot39-10101}{505050-70707}\)
\(A=\frac{\left(3\cdot7\cdot13\cdot37\right)\cdot39-10101\cdot1}{50\cdot10101+7\cdot10101}\)
\(A=\frac{10101\cdot39-10101\cdot1}{10101\cdot\left(50+7\right)}\)
\(A=\frac{10101\cdot\left(39-1\right)}{10101\cdot57}\)
\(A=\frac{10101\cdot38}{10101\cdot57}\)
\(A=\frac{38}{57}=\frac{38:19}{57:19}=\frac{2}{3}\)
Ta có: \(B=\frac{3.5.7.11.13.17-10101}{1313130+20202}\)
\(\Rightarrow B=\frac{255255-10101}{1313130+20202}\)
\(\Rightarrow B=\frac{1001.255-10101}{10101.13.10+10101.2}\)
\(\Rightarrow B=\frac{1001.255-10101}{10101.\left(13.10+2\right)}\)
\(\Rightarrow B=\frac{1001.255-10101}{10101.132}\)
\(\Rightarrow B=\frac{10101.255-19201}{10101.132}\)
3.7.13.37.39-10101/505050+70707
=393939-10101/505050+70707
=10101.39-10101/505050+70707
=10101(39-1)/10101.50 +70707
=10101.38/10101+70707
=38+70707=70745
Đề : \(\frac{3\cdot7\cdot13\cdot37\cdot39-10101}{505050-70707}\)
\(\Rightarrow\frac{\left(3\cdot7\cdot13\cdot37\right)\cdot39-10101}{505050-70707}\)
\(\Rightarrow\frac{10101\cdot39-10101}{505050-70707}\)
\(\Rightarrow\frac{10101\cdot\left(39-1\right)}{505050-70707}\)
\(\Rightarrow\frac{10101\cdot38}{50\cdot10101-7\cdot10101}\)
\(\Rightarrow\frac{10101\cdot38}{10101\cdot\left(50-7\right)}\)
\(\Rightarrow\frac{10101\cdot38}{10101\cdot43}\)
\(\Rightarrow\frac{38}{43}\)
\(\frac{3.7.13.37.19-10101}{505050+70707}\)=\(\frac{10101.39-10101}{10101.50+10101.7}\)=\(\frac{10101.\left(39-1\right)}{10101.\left(50+7\right)}\)=\(\frac{38}{57}\)=\(\frac{2}{3}\)
so sánh hả bạn?
ta có : 191919 + 20202 = 212121
353535 + 70707 = 424242
vì 212121 < 424242
=> 191919 + 20202 < 353535 + 70707