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\(8^x.16^{-2x}=4^5\)
\(\Leftrightarrow8^x.8^{-2x}.2^{-2x}=4^5\)
\(\Leftrightarrow8^{x+\left(-2x\right)}.2^{-2x}=\left(2^2\right)^5\)
\(\Leftrightarrow8^{-x}=2^{10}:2^{-2x}\)
\(\Leftrightarrow8^{-x}=2^{10-\left(-2x\right)}=2^{10+2x}\)
\(\Leftrightarrow\left(2^3\right)^{-x}=2^{10+2x}\)
\(\Leftrightarrow2^{-3x}=2^{10+2x}\)
\(\Leftrightarrow-3x=10+2x\)
\(\Leftrightarrow5x=-10\)
\(\Leftrightarrow x=-2\)
Vậy : \(x=-2\)
\(8^x.16^{-2x}=4^5\)
\(\Leftrightarrow2^{3x}.2^{-8x}=2^{10}\)
\(\Leftrightarrow2^{-24x^2}=2^{10}\)
\(\Leftrightarrow-24x^2=10\)
\(\Leftrightarrow x^2=\frac{10}{-24}\)
Mà \(x^2\ge0\)nên pt vô nghiệm
\(8^x.16^{-2x}=4^5=>\frac{8^x.1}{16^{2x}}=4^5=>\frac{8^x}{256^x}=4^5=>\frac{1}{32^x}=4^5=>4^5.32^x=1=>2^{10}.2^{5x}=1\)
\(2^{10+5x}=1=>10+5x=0=>5x=-10=>x=-2\)
Noob ơi, bạn phải đưa vào máy tính ý solve cái là ra x luôn, chỉ tội là đợi hơi lâu
a, 4.(18 - 5x) - 12(3x - 7) = 15(2x - 16) - 6(x + 14)
=> 72 - 20x - 36x + 84 = 30x - 240 - 6x - 84
=> (72 + 84) + (-20x - 36x) = (30x - 6x) + (-240 - 84)
=> 156 - 56x = 24x - 324
=> 24x + 56x = 324 + 156
=> 80x = 480
=> x = 480 : 80 = 6
Vậy x = 6
a, \(\frac{x+1}{5}=\frac{3}{7}\Rightarrow7\left(x+1\right)=15\Rightarrow7x+7=15\Rightarrow7x=8\Rightarrow x=\frac{8}{7}\)
b, \(\frac{x-2}{3}=\frac{3}{8}\Rightarrow8\left(x-2\right)=9\Rightarrow8x-16=9\Rightarrow8x=25\Rightarrow x=\frac{25}{8}\)
c, \(\frac{-x-1}{2}=\frac{-3}{5}\Rightarrow5\left(-x-1\right)=-6\Rightarrow-5x-5=-6\Rightarrow-5x=-1\Rightarrow x=\frac{1}{5}\)
d, \(\frac{4}{5-x}=\frac{1}{3}\Rightarrow5-x=12\Rightarrow x=-7\)
e, \(2x\left(x-\frac{1}{7}\right)=0\Rightarrow\orbr{\begin{cases}2x=0\\x-\frac{1}{7}=0\end{cases}\Rightarrow\orbr{\begin{cases}x=0\\x=\frac{1}{7}\end{cases}}}\)
\(\left(\frac{-7}{4}:\frac{5}{8}\right)\cdot\frac{11}{16}=\frac{-7}{4}\cdot\frac{8}{5}\cdot\frac{11}{16}=\frac{-7.11}{4.5.2}=\frac{-77}{40}\)
a) (5x+1) ^ 2 = 4^2 : 5^ 2
( 5x+1) ^2 = (4:5) ^2
=> (5x+1) = ( 4 : 5) = 0.8
5x = 0.8 - 1
x = 0.7 : 5
x = 0,14
B1 :a) <=> 3-2x-1=4-x+3
<=> 3-1-4-3=-x+2x
<=>x=-5
b) <=> 4x>16+5
<=>4x>21
<=>x>21/4
c) <=> -x<21-5
<=>-x<16
<=> x>16
B2 :
A =3(X-2)^2-5
Ta có (x-2)^2 > 0
=>3(x-2)^2 > 0
=> 3(x-2)2 -5 > -5
=> A > -5
=> Min A=-5 <=> x=2
162x = 45 . 8x
=> ( 42 ) 2x = 45 . ( 42 )x
=> 44x = 4 2x + 5
=> 4x = 2x + 5
=> 2x = 5
=> x = 2, 5
Vậy x = 2,5
\(16^{2x}=4^5\cdot8^x\)
\(x=-21\frac{677}{1250}\)
Hok tốt! ^-<