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a, => x-2x = 15+25
=> -x=40
=> x=-40
b, => -5x^2+50x = -3x-30x = -33x
=> 5x^2-50x=33x
=> 5x^2-50x-33x=0
=> 5x^2-83x=0
=> x.(5x-83) = 0
=> x=0 hoặc 5x-83=0
=> x=0 hoặc x=83/5
Tk mk nha
\(2x+3x+5x+...+17x+19x\)
\(x.\left(2+3+5+...+17+19\right)=1+2+...+9\)
\(x.101=45\)
\(\Rightarrow x=45:101\)
\(\Rightarrow x=\dfrac{45}{101}\)
a,
23x + 12x + 27x = 372
62x = 372
x = 372 : 62
x = 6
b,
x + 2x + 3x + ... + 15x = 840
( 1 + 2 + ... + 15 ) x = 840
1 + 2 + ... + 15
Số số hạng
( 15 - 1 ) : 1 + 1 = 15
Tổng
( 15 + 1 ) * 15 : 2 = 120
120x = 840
x = 840 : 120
x = 7
c,
( 2x - 11 ) ( 5x - 40 ) = 0
\(\orbr{\begin{cases}2x-11=0\\5x-40=0\end{cases}}\)
\(\orbr{\begin{cases}2x=11\\5x=40\end{cases}}\)
\(\orbr{\begin{cases}x=\frac{11}{2}\\x=8\end{cases}}\)
Bài làm :
\(a,23x+13x+27x=372\)
\(\left(23+13+27\right)x=372\)
\(63x=372\)
\(x=\frac{124}{21}\)
\(b,x+2x+3x+...+15x=840\)
\(\left(1+2+3+...+15\right)x=840\)
\(120x=840\)
\(x=7\)
\(c,\left(2x-11\right)\left(5x-40\right)=0\)
\(\Rightarrow\orbr{\begin{cases}2x-11=0\\5x-40=0\end{cases}}\Rightarrow\orbr{\begin{cases}2x=11\\5x=40\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{11}{2}\\x=8\end{cases}}\)
Vậy \(x=\frac{11}{2}\) hoặc x = 8 .
Học tốt
a)4.(x+3)-(2x-12)=x-(-11+4)
4x+12-2x+12=x+11-4
2x+24=x+7
2x-x=-24+7
x=-17
b)-(4x-13)+(5x-4)=-3-(-15+7)
-4x+13+5x-4=-3+15-7
(-4x+5x)+13-4=12-7
x+9=5
x=-4
c)(5x-3)-(-2x+4)=6x-12
5x-3+2x-4=6x-12
5x+2x-6x=3+4-12
x=-5
d)(15x+20)-(9x-3)=5x-(-12)
15x+20-9x+3=5x+12
15x-9x-5x=-20-3+12
x=-11
e,(7x+14)+(3x-8)=-(-9x+3)
7x+14+3x-8=9x-3
7x+3x-9x=-14+8-3
x=-9
b, \(\frac{1}{6}x+\frac{1}{10}x-\frac{4}{15}x+1=0\)
\(x\left(\frac{1}{6}+\frac{1}{10}-\frac{4}{15}\right)+1=0\)
\(x.0=-1\)
\(\Rightarrow x\in rỗng\)
4. ( x - 250 ) : 6 = 64 - 12
( x- 250 ) : 6 = 52
x - 250 = 312
x = 562
5. 10x = 1030
=> x = 103
6. 30x = 120
x = 4
7. \(x=2023\)
\(8.165-\left(35:x+3\right).19=13\)
\(\left(35:x+3\right).19=152\)
\(35:x+3=8\)
\(35:x=5\)
\(x=7\)
4) \(\left(x-250\right)\div6=4^3-2^2\times3\)
\(\left(x-250\right)\div6=64-4\times3\)
\(\left(x-250\right)\div6=64-12=52\)
\(x-250=52\times6=312\)
\(x=312+250\)
\(x=562\)
5) \(2x+3x+5x=1030\)
\(x\left(2+3+5\right)=1030\)
\(10x=1030\)
\(x=1030\div10\)
\(x=103\)
6) \(15x-35x+50x=120\)
\(x\left(15-35+50\right)=120\)
\(30x=120\)
\(x=120\div30\)
\(x=4\)
7) \(\dfrac{1}{2}x+\dfrac{1}{6}x+\dfrac{1}{3}x=2023\)
\(x\left(\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{6}\right)=2023\)
\(x\times1=2023\)
\(x=2023\)
8) \(165-\left(35\div x+3\right)\times19=13\)
\(\left(35\div x+3\right)\times19=165-13\)
\(\left(35\div x+3\right)\times19=152\)
\(35\div x+3=152\div19=8\)
\(35\div x=8-3=5\)
\(x=35\div5\)
\(x=7\)
\(\text{a)Với x = -23 để A = }3(-23)+5(-23)-15(-23)+12(-23-1)\)
\(\text{Ta có : }A=3+5-15(-23)+12(-23-1)\)
\(A=-7\cdot(-23)+12\cdot(-24)\)
\(A=161+(-288)=-127\)
Còn bài b tương tự
\(A=3x+5x-15x+12\left(x-1\right)\)
\(A=x\left(3+5-15\right)+12\left(x-1\right)\)
\(A=-23\cdot-7+12\cdot-24\)
\(A=-127\)
a) \(5x+3x+6x=280\)
\(\Leftrightarrow14x=280\)
\(\Leftrightarrow x=20\)
b) \(15x-12x+6x=3^5:3^3\)
\(\Leftrightarrow9x=3^2=9\)
\(\Leftrightarrow x=1\)
c) \(12+6\left(3x-23\right)=6^5:6^3\)
\(\Leftrightarrow12+18x-138=6^2=36\)
\(\Leftrightarrow18x=162\)
\(\Leftrightarrow x=9\)
d) \(115-15\left(6x-23\right)=5^5:5^3\)
\(\Leftrightarrow115-90x+345=5^2=25\)
\(\Leftrightarrow90x=435\)
\(\Leftrightarrow x=\frac{29}{6}\)
a)5x+3x+6x=280
14x = 280
x = 280 : 14
x = 20.
b)15x-12x+6x=35÷33
9x = \(3^2\)
9x = 9
x = 9 : 9
x = 1
c)12+6(3x-23)=65÷63
12 + \(\left[18x-138\right]\)= \(6^2\)
12 + \(\left[18x-138\right]\)= 36
\(\left[18x-138\right]\) = 36 - 12
\(\left[18x-138\right]\) = 24
18x = 24 + 138
18x = 162
x = 162 : 18
x = 9.
Câu d cậu xem lại đề nha!
Hok tốt !
15x+3x-5x=250
<=>13x=250
<=>x=250/13
\(15x+3x-5x=250\)
\(\left(15+3-5\right)x=250\)
\(13x=250\)
\(x=250:13\)
\(x=\frac{250}{13}\)