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1:tính
\(\frac{5}{8}\)x\(\frac{9}{7}\)+\(\frac{5}{8}\)x\(\frac{5}{7}\)
=\(\frac{5}{8}\)x\((\)\(\frac{9}{7}\)+\(\frac{5}{7}\)\()\)
=\(\frac{5}{8}\)x2
=\(\frac{5}{4}\)
# hok tốt #
a.\(\dfrac{18}{15}+\dfrac{7}{15}+\dfrac{12}{15}=\dfrac{18+7+12}{15}=\dfrac{37}{15}\)
b.\(\dfrac{9}{7}+\dfrac{8}{7}+\dfrac{11}{7}=\dfrac{9+8+11}{7}=\dfrac{28}{7}=4\)
\(\dfrac{14}{8}:\dfrac{7}{12}-\dfrac{3}{8}:\dfrac{9}{5}\\ =\dfrac{7}{4}:\dfrac{7}{12}-\dfrac{3}{8}:\dfrac{9}{5}\\ =\dfrac{7}{4}\times\dfrac{12}{7}-\dfrac{3}{8}\times\dfrac{5}{9}\\ =\dfrac{12}{4}-\dfrac{1\times5}{8\times3}\\ =3-\dfrac{5}{24}\\ =\dfrac{3\times24-5}{24}\\ =\dfrac{72-5}{24}\\ =\dfrac{67}{24}\)
a,18/15+7/15+12/15=18+7+12/15
=37/15
b,9/7+8/7+11/7=9+8+11/7
=28/7=1/4
+8/15 + 7/15 +12/15 = (18+7+12)/7 = [(18+12)+7]/15= (30+7)/15=37/15=7/3
9/7 + 8/7 + 11/7 = (9+8+11)/7= [(9+11)+8]/7=(20+8)/7= 28/7 =4
a) \(\frac{18}{15}+\frac{7}{15}+\frac{12}{15}\)
= \(\frac{18+7+12}{15}\)
= \(\frac{37}{15}\)
b) \(\frac{9}{7}+\frac{8}{7}+\frac{11}{7}\)
= \(\frac{9+8+11}{7}\)
= \(\frac{28}{7}\)
a) 18/15 + 7/15 + 12/15
= (18/15 + 12/15) + 7/15
= 30/15 + 7/15
= 37/15
b) 9/7 + 8/7 + 11/7
= (9/7 + 11/7) + 8/7
= 20/7 + 8/7
= 28/7
chuc ban hok tot
\(\frac{15}{7}-\frac{9}{7}=\frac{6}{7}\)
15/7 - 9/7 = 6/7