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`a,`
`x*3+7=16`
`=>3x = 16 - 7`
`=> 3x = 9`
`=> x = 9 \div 3`
`=> x = 3`
Vậy, `x = 3`
`b,`
` x- 152 \div 2 = 46?`
`=> x - 76 = 46`
`=> x = 46 + 76`
`=> x = 122`
Vậy, `x = 122.`
`c,`
` 74-2*(x+3)=34`
`=> 2(x + 3) = 74 - 34`
`=> 2(x+2) = 40`
`=> x + 2 = 40 \div 2`
`=> x + 2 = 20`
`=> x = 20 - 2`
`=> x = 18`
Vậy, `x = 18.`
( x - 5 ) * 3 - 140 : 35 = 152
( x - 5 ) * 3 - 4 = 152
( x - 5 ) * 3 = 152 + 4
( x - 5 ) * 3 = 156
x - 5 = 156 : 3
x - 5 = 52
x = 52 + 5
( x + 1 ) + ( x + 5 ) + ... + ( x + 29 ) = 136
Dãy số trên gồm:( 29 - 1 ) : 4 + 1 = 8 ( số hạng )
Ta có : ( x + 29 + x + 1 ) x 8 : 2 = 136
( x * 2 + 30 ) x 4 = 136
x * 2 + 30 = 136 : 4
x * 2 + 30 = 34
x * 2 = 34 - 30
x * 2 = 4
x = 4 : 2
x = 2
Đây là bài toán lớp 4 chứ không phải là lớp 6
( x - 5 ) * 3 - 140 : 35 = 152
( x - 5 ) * 3 - 4 = 152
( x - 5 ) * 3 = 152 + 4
( x - 5 ) * 3 = 156
x - 5 = 156 : 3
x - 5 = 52
x = 52 + 5
( x + 1 ) + ( x + 5 ) + ... + ( x + 29 ) = 136
Dãy số trên gồm:( 29 - 1 ) : 4 + 1 = 8 ( số hạng )
Ta có : ( x + 29 + x + 1 ) x 8 : 2 = 136
( x * 2 + 30 ) x 4 = 136
x * 2 + 30 = 136 : 4
x * 2 + 30 = 34
x * 2 = 34 - 30
x * 2 = 4
x = 4 : 2
x = 2
a ) | x | − 3 4 = 5 3 = > | x | = 29 12 = > x = 29 12 x = − 29 12
b) x − 3 2 = 1 = > x − 3 2 = 1 x − 3 2 = − 1 = > x = 5 2 x = 1 2
c) x − 3 2 + 11 4 = 15 4 = > x − 3 2 = 1 = > x = 5 2 x = 1 2
d) 17 4 − 5 6 − x = − 7 4 = > 5 6 − x = 6 = > x = − 31 6 x = 41 6
e)
x + 1 5 2 − 9 25 = 0 = > x + 1 5 2 = 9 25 = > x + 1 5 = 3 5 x + 1 5 = − 3 5 = > x = 2 5 x = − 4 5
f) x + 1 5 2 + 17 25 = 26 25 = > x + 1 5 2 = 9 25 = > x = 2 5 x = − 4 5
n: (-8)*x+17=-23
=>\(x\cdot\left(-8\right)=-23-17=-40\)
=>\(x\cdot8=40\)
=>\(x=\dfrac{40}{8}=5\)
o: \(\left(-15\right)\cdot x=10\left(-4\right)-5\)
=>\(x\cdot\left(-15\right)=-40-5=-45\)
=>\(x\cdot15=45\)
=>\(x=\dfrac{45}{15}=3\)
p: \(\left(-3\right)\cdot x-4=2\cdot\left(-7\right)+4\)
=>\(\left(-3\right)\cdot x-4=-14+4=-10\)
=>\(x\left(-3\right)=-10+4=-6\)
=>\(3x=6\)
=>\(x=\dfrac{6}{3}=2\)
q: x+x+x+91=-2
=>\(3x+91=-2\)
=>\(3x=-2-91=-93\)
=>\(x=-\dfrac{93}{3}=-31\)
r: \(-152-\left(3x+1\right)=\left(-2\right)\cdot\left(-27\right)\)
=>\(-152-3x-1=54\)
=>\(-153-3x=54\)
=>\(3x=-153-54=-207\)
=>\(x=-\dfrac{207}{3}=-69\)
a) \(-x-14+32=-26\)
\(-x=-26-32+14\)
\(-x=-44\)
\(x=44\)
b) \(-152-\left(3x+1\right)=\left(-2\right)\left(-27\right)\)
\(-152-3x-1=54\)
\(-3x=96\)
\(x=-32\)
c) \(x+x+x+82=-2-x\)
\(3x+82=2+x\)
\(2x=-80\)
\(x=-40\)
d) \(\left(-1\right)\left(-3\right)\left(-6\right)x=36\)
\(-18x=36\)
\(x=-2\)
1)
\(-x-14+32=-26\)
\(\Rightarrow-x+18=-26\)
\(\Rightarrow-x=-26-18\)
\(\Rightarrow-x=-44\)
\(\Rightarrow x=44\)
Vậy \(x=44\)
2)
\(-152-\left(3x+1\right)=\left(-2\right)\left(-27\right)\)
\(\Rightarrow-152-3x-1=54\)
\(\Rightarrow-153-3x=54\)
\(\Rightarrow-3x=54+163\)
\(\Rightarrow-3x=207\)
\(\Rightarrow x=207:\left(-3\right)\)
\(\Rightarrow x=-69\)
Vậy \(x=-69\)
3)
\(x+x+x+82=-2-x\)
\(\Rightarrow3x+82=-2-x\)
\(\Rightarrow3x+x=-2-82\)
\(\Rightarrow4x=-84\)
\(\Rightarrow x=-21\)
Vậy \(x=-21\)
4)
\(\left(-1\right)\left(-3\right)\left(-6\right).x=36\)
\(\Rightarrow-18x=36\)
\(\Rightarrow x=-2\)
Vậy \(x=-2\)
1)-(-3)3-(2x+1)3=152
27-(2x+1)3=152
(2x+1)3=-125
(2x+1)3=(-5)3
2x+1=-5
2x=-4
x=-2
2)-(x+6)-34=12+3x
-x-6-34=12+3x
-x-3x=12+6+34
-4x=52
x=-13
a) x + 1 5 2 − 9 25 = 0 ⇒ x + 1 5 2 = 9 25 ⇒ x + 1 5 = 3 5 x + 1 5 = − 3 5 ⇒ x = 2 5 x = − 4 5
b) x + 1 5 2 + 17 25 = 26 25 ⇒ x + 1 5 2 = 9 25 ⇒ x = 2 5 x = − 4 5
\(2x+3=15\\ \Rightarrow2x=15-3=12\\ \Rightarrow x=\dfrac{12}{2}=6\\ ---\\ 28-3x=13\\ \Rightarrow3x=28-13=15\\ \Rightarrow x=\dfrac{15}{3}=5\\ ---\\ \left(x-1954\right).5=50\\ \Rightarrow x-1954=50:5=10\\ \Rightarrow x=10+1954=1964\\ ---\\ x-152:2=46\\ \Rightarrow x-76=46\\ \Rightarrow x=46+76=122\)
a, 2\(x\) + 3 = 15
2\(x\) = 12
\(x\) = 6
b, 28 - 3\(x\) = 13
3\(x\) = 28 - 13
3\(x\) = 15
\(x\) = 5
\(-152-\left(3x+1\right)=154\)
\(\Leftrightarrow3x+1=-152-154=-306\)
\(\Leftrightarrow3x=-306-1=-307\)
\(\Leftrightarrow x=-\dfrac{307}{3}\)
Ta có: -152-(3x+1)=154
\(\Leftrightarrow-152-3x-1=154\)
\(\Leftrightarrow-3x-153=154\)
\(\Leftrightarrow-3x=307\)
hay \(x=-\dfrac{307}{3}\)
Vậy: \(x=-\dfrac{307}{3}\)