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2 tháng 3 2020

1) x2 + x - y2 + y = (x2 - y2) + (x + y) = (x - y)(x + y) + (x + y) = (x - y + 1)(x + y)

2) 4x2 - 9y2 + 4x - 6y = (4x2 - 9y2) + (4x - 6y) = (2x - 3y)(2x + 3y) + 2(2x - 3y) = (2x - 3y)(2x + 3y + 2)

3) x2 + x + y2 + y + 2xy = (x2 + 2xy + y2) + (x + y) = (x + y)2 + (x + y) = (x + y)(x + y + 1)

4) -x2 + 5x + 2xy - 5y - y2 = -(x2 - 2xy + y2) + (5x - 5y) = -(x - y)2 + 5(x - y) = (x - y)(y - x + 5)

5) x2 - y2 + 2x + 1  = (x2 + 2x + 1) - y2 = (x + 1)2 - y2 = (x + 1 + y)(x - y + 1)

6) x2 - 1 - y2 + 2y = x2 - (y2 - 2y + 1) = x2 - (y - 1)2 = (x - y + 1)(x + y - 1)

7) x2 + 2xz - y2 + 2uy + z2 - u2 =(x2 + 2xz + z2) - (y2 - 2uy + u2) = (x + z)2 - (y - u)2 = (x + z - y + u)(x + z + y - u)

8) x3 + 3x2y + x + 3xy2 + y + y3 = (x3 + 3x2y + 3xy2 + y3) + (x + y) = (x + y)3 + (x + y) = (x + y)(x2 + 2xy + y2 + 1)

9) x3 + y(1 - 3x2) + x(3y2 - 1) - y3 = x3 + y - 3x2y + 3xy2 - x - y3 = (x3 - 3x2y + 3xy2 - y3) - (x - y) = (x - y)3 - (x - y) = (x - y)(x2 - 2xy+y2-1)

1: \(=a\left(x+y\right)-4\left(x+y\right)=\left(x+y\right)\left(a-4\right)\)

2: \(=x\left(x+b\right)+a\left(x+b\right)=\left(x+b\right)\left(x+q\right)\)

3: \(=a\left(x+1\right)-b\left(x+1\right)+c\left(x+1\right)\)

\(=\left(x+1\right)\left(a-b+c\right)\)

6: \(=\left(x-y\right)^2-4=\left(x-y-2\right)\left(x-y+2\right)\)

AH
Akai Haruma
Giáo viên
7 tháng 7 2019

5.

\(4x^5y^2+8x^4y^3+4x^3y^4=4x^3y^2(x^2+2xy+y^2)\)

\(=4x^3y^2(x+y)^2\)

9.

\(4x^5y^2+16x^4y^2-6x^3y^2=2x^3y^2(2x^2+4x-3)\)

13.

\(-3x^4y+6x^3y-3x^2y=-3x^2y(x^2-2x+1)=-3x^2y(x-1)^2\)

17.

\(8x^3-8x^2y+2xy^2=2x(4x^2-4xy+y^2)\)

\(=2x[(2x)^2-2.2x.y+y^2]=2x(2x-y)^2\)

AH
Akai Haruma
Giáo viên
7 tháng 7 2019

21.

\((a^2+4)^2-16a^2b^2=(a^2+4)^2-(4ab)^2\)

\(=(a^2+4-4ab)(a^2+4+4ab)\)

25.

\(100a^2-(a^2+25)^2=(10a)^2-(a^2+25)^2\)

\(=(10a-a^2-25)(10a+a^2+25)\)

\(=-(a^2-10a+25)(a^2+10a+25)=-(a-5)^2(a+5)^2\)

29.

\(25a^2b^2-4x^2+4x-1=25a^2b^2-(4x^2-4x+1)\)

\(=(5ab)^2-(2x-1)^2=(5ab-2x+1)(5ab+2x-1)\)

14 tháng 10 2020

21, \(x^3-4x^2+4x=x\left(x^2-4x+4\right)=x\left(x-2\right)^2\)

22, \(15x^2y+20xy^2-25xy=5xy\left(3x+4y-5\right)\)

23, \(4x^2+8xy-3x-6y=4x\left(x+2y\right)-3\left(x+2y\right)=\left(4x-3\right)\left(x+2y\right)\)

24, \(x^3-6x^2+9x=x\left(x^2-6x+9\right)=x\left(x-3\right)^2\)

Tương tự :)) 

14 tháng 10 2020

21.\(x^3-4x^2+4x\)

\(=x\left(x^2-4x+4\right)\)

\(=x\left(x-2\right)^2\)

22,\(15x^2y+20xy^2-25xy\)

\(=5xy\left(3x+4y-5\right)\)

23,\(4x^2+8xy-3x-6y\)

\(=4x\left(x+2y\right)-3\left(x+2y\right)\)

\(=\left(4x-3\right)\left(x+2y\right)\)

24\(x^3-6x^2+9x\)

\(=x\left(x^2-6x+9\right)\)

\(=x\left(x-3\right)^2\)

25,\(x^2-xy+x-y\)

\(=x\left(x-y\right)+\left(x-y\right)\)

\(=\left(x+1\right)\left(x-y\right)\)

26.\(xy-2x-y^2+2y\)

\(=x\left(x-2\right)-y\left(y-2\right)\)

\(=\left(x-y\right)\left(x-2\right)\)

27,\(x^2+x-xy-y\)

\(=\left(x^2-xy\right)+\left(x-y\right)\)

\(=x\left(x-y\right)+\left(x-y\right)\)

\(=\left(x+1\right)\left(x-y\right)\)

28,\(x^2+4x-y^2+4\)

\(=\left(x^2+4x+4\right)-y^2\)

\(=\left(x+2\right)^2-y^2\)

\(=\left(x+2-y\right)\left(x+2+y\right)\)

29.\(x^2-2xy+y^2-4\)

\(=\left(x-y\right)^2-2^2\)

\(=\left(x-y-2\right)\left(x-y+2\right)\)

22 tháng 11 2017

1, a,= (x+2)^2/3.(x+2) = x+2/3

b,  = 3x.(x+4)/2x.(x+4) = 3/2

k mk nha

22 tháng 6 2018

\(a.x^3-16x=x\left(x^2-16\right)=x\left(x-4\right)\left(x+4\right)\)

\(b.x^3-3x^2-4x=x^3+x^2-4x^2-4x=x^2\left(x+1\right)-4x\left(x+1\right)=\left(x+1\right)\left(x^2-4x\right)=x\left(x+1\right)\left(x-4\right)\)\(c.x^2-y^2+2x+1=\left(x+1\right)^2-y^2=\left(x+1-y\right)\left(x+1+y\right)\)

\(d.ax^2+ay-bx^2-by=a\left(x^2+y\right)-b\left(x^2+y\right)=\left(a-b\right)\left(x^2+y\right)\)\(e.2x^3-4x^2+x-2=2x^2\left(x-2\right)+\left(x-2\right)=2x^2\left(x-2\right)\)

22 tháng 6 2018

Giải:

a) \(x^3-16x=x\left(x^2-16\right)=x\left(x-4\right)\left(x+4\right)\)

b) \(x^3-3x^2-4x=x\left(x^2-3x-4\right)=x\left(x+4\right)\left(x-1\right)\)

c) \(x^2-y^2+2x+1=\left(x+1\right)^2-y^2=\left(x+1-y\right)\left(x+1+y\right)\)

d) \(ax^2+ay-bx^2-by=a\left(x^2+y\right)-b\left(x^2+y\right)=\left(a-b\right)\left(x^2+y\right)\)

e) \(2x^3-4x^2+x-2=2x^2\left(x-2\right)+\left(x-2\right)=\left(2x^2+1\right)\left(x-2\right)\)

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