Question

[???????kocoten]

14/9*11/3-8/12*14/9+20/15

Answer 1

[Nguyễn Lê Phước Thịnh]

Ta có: \(\dfrac{14}{9}\times\dfrac{11}{3}-\dfrac{8}{12}\times\dfrac{14}{9}+\dfrac{20}{15}\)

\(=\dfrac{14}{9}\times\dfrac{11}{3}-\dfrac{2}{3}\times\dfrac{14}{9}+\dfrac{4}{3}\)

\(=\dfrac{14}{9}\times\left(\dfrac{11}{3}-\dfrac{2}{3}\right)+\dfrac{4}{3}\)

\(=\dfrac{14}{9}\times3+\dfrac{4}{3}=\dfrac{14}{3}+\dfrac{4}{3}=\dfrac{18}{3}=6\)

Answer 2

[Nguyễn Thị Thương Hoài]

    \(\dfrac{14}{9}\) x \(\dfrac{11}{3}\) - \(\dfrac{8}{12}\) x \(\dfrac{14}{9}\) + \(\dfrac{20}{15}\)

=   \(\dfrac{14}{9}\) x (\(\dfrac{11}{3}\) - \(\dfrac{8}{12}\)) + \(\dfrac{4}{3}\)

=   \(\dfrac{14}{9}\) x (\(\dfrac{11}{3}\) - \(\dfrac{2}{3}\)) + \(\dfrac{4}{3}\)

= \(\dfrac{14}{9}\) x 3 + \(\dfrac{4}{3}\)

= \(\dfrac{14}{3}\) + \(\dfrac{4}{3}\)

= 6