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\(a,\Rightarrow2x^2-18x-2x^2=0\\ \Rightarrow-18x=0\Rightarrow x=0\\ b,\Rightarrow2x^2-5x-12+x^2-7x+10=3x^2-17x+20\\ \Rightarrow5x=22\Rightarrow x=\dfrac{22}{5}\)
20) -5-(x + 3) = 2 - 5x ⇔ -5 - x - 3 = 2 -5x ⇔ 4x = 10 ⇔ x = \(\frac{5}{2}\)
Vậy...
a/ Ta có : \(49.x^2-4=0\)
\(\Rightarrow49x^2=4\)
\(\Rightarrow x^2=\frac{4}{49}\Rightarrow\orbr{\begin{cases}x=\frac{-2}{7}\\x=\frac{2}{7}\end{cases}}\)
b/ \(\left(x+3\right)^2-\left(x+2\right)\left(x-2\right)=11\)
\(\left(x+3\right)\left(x+3\right)-\left(x+2\right)\left(x-2\right)=11\)
\(\Rightarrow\left(x^2+2.3.x+3^2\right)-\left(x^2-2^2\right)=11\)
\(\Rightarrow x^2+6x+9-x^2+4=11\)
\(\Rightarrow6x+13=11\)
\(\Rightarrow6x=11-13\)
\(\Rightarrow x=\frac{-2}{6}=\frac{-1}{3}\)
c/ \(\left(2x+1\right)^2-\left(x-3\right)^2-3\left(x+5\right)\left(x-5\right)=5\)
\(\Rightarrow\left(2x+1\right)\left(2x+1\right)-\left(x-3\right)\left(x-3\right)-3\left[\left(x+5\right)\left(x-5\right)\right]=5\)
\(\Rightarrow\left(4x^2+2.2x+1\right)-\left(x^2-2.3x+9\right)-3\left(x^2-25\right)\)\(=5\)
\(\Rightarrow\left(4x^2+4x+1\right)-\left(x^2-6x+9\right)-\left(3x^2-75\right)=5\)
\(\Rightarrow4x^2+4x+1-x^2+6x-9-3x^2+75=5\)
\(\Rightarrow\left(4x^2-x^2-3x^2\right)+\left(4x+6x\right)+\left(1-9+75\right)=5\)
\(\Rightarrow10x+67=5\)
\(\Rightarrow10x=5-67=-62\)
\(\Rightarrow x=\frac{-62}{10}=\frac{-31}{5}\)
d/ \(\left(3x+1\right)\left(3x-1\right)=8\)
\(\Rightarrow9x^2-1=8\)
\(\Rightarrow9x^2=8+1=9\)
\(\Rightarrow x^2=\frac{9}{9}=1\Leftrightarrow\orbr{\begin{cases}x=-1\\x=1\end{cases}}\)
Ai đó bấm hộ mình cái nút đúng đi!
Ta có : 49x2 - 4 = 0
=> 49x2 = 4
=> x2 = 196
=> x2 = 142 ; (-14)2
=> x = 14 ; -14
a, \(4\left(18-5x\right)-12\left(3x-7\right)=15\left(2x-16\right)-6\left(x+14\right)\)
\(\Rightarrow72-20x-36x+84=30x-240-6x-84\)
\(\Rightarrow-20x-36x-30x+6x=-240-84-72-84\)
\(\Rightarrow-80x=-480\Rightarrow x=6\)
b, \(5\left(3x+5\right)-4\left(2x-3\right)=5x+3\left(2x+12\right)+1\)
\(\Rightarrow15x+25-8x+12=5x+6x+36+1\)
\(\Rightarrow15x-8x-5x-6x=36+1-25-12\)
\(\Rightarrow-4x=0\Rightarrow x=0\)
c, \(2\left(5x-8\right)-3\left(4x-5\right)=4\left(3x-4\right)+11\)
\(\Rightarrow10x-16-12x+15=12x-16+11\)
\(\Rightarrow10x-12x-12x=-16+11+16-15\)
\(\Rightarrow-14x=-4\Rightarrow x=\dfrac{2}{7}\)
d, \(5x-3\left\{4x-2\left[4x-3\left(5x-2\right)\right]\right\}=182\)
\(\Rightarrow5x-3\left[4x-2\left(4x-15x+6\right)\right]=182\)
\(\Rightarrow5x-3\left(4x-8x+30x-12\right)=182\)
\(\Rightarrow5x-12x+24x-90x+36=182\)
\(\Rightarrow-73x=182-36\)
\(\Rightarrow-73x=146\Rightarrow x=-2\)
Chúc bạn học tốt!!!
ĐKXĐ: \(x\ne4\)
Ta có: \(\frac{14}{3x-12}-\frac{2+x}{x-4}=\frac{3}{8-2x}-\frac{5}{6}\)
\(\Leftrightarrow\frac{14-3\left(x+2\right)}{3\left(x-4\right)}=\frac{9-5\left(4-x\right)}{6\left(4-x\right)}\)
\(\Leftrightarrow\frac{-3x+8}{3\left(x-4\right)}=\frac{5x-11}{6\left(4-x\right)}\)
\(\Leftrightarrow\frac{-6x+16}{6\left(x-4\right)}=\frac{-5x+11}{6\left(x-4\right)}\)
\(\Leftrightarrow-6x+16=-5x+11\)
\(\Leftrightarrow-x+5=0\)
\(\Leftrightarrow x=5\)(tm)
Vậy: x=5
a) \(\Rightarrow72-20x-36x+84=30x-240-6x-84\)
\(\Rightarrow80x=480\Rightarrow x=6\)
b) \(\Rightarrow15x+25-8x+12=5x+6x+36+1\)
\(\Rightarrow4x=0\Rightarrow x=0\)
c) \(\Rightarrow10x-16-12x+15=12x-16+11\)
\(\Rightarrow14x=4\Rightarrow x=\dfrac{2}{7}\)
Mấy cái này chuyển vế đổi dấu là xong í mà :3
1,
16-8x=0
=>16=8x
=>x=16/8=2
2,
7x+14=0
=>7x=-14
=>x=-2
3,
5-2x=0
=>5=2x
=>x=5/2
Mk làm 3 cau làm mẫu thôi
Lúc đăng đừng đăng như v :>
chi ra khỏi ngt nản
từ câu 1 đến câu 8 cs thể làm rất dễ,bn tham khảo bài của bn muwaa r làm những câu cn lại